Oscillations Formula Sheet and PYQs | Kumar Physics Classes
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OSCILLATIONS MASTER REVISION

Oscillations Formula Sheet and PYQs

Complete formula sheet, NCERT-style examples, CBSE, NEET, JEE Main, JEE Advanced, IB, IGCSE, A-Level questions, assertion-reason, case studies and quick revision notes.

CBSENEETJEE MainJEE AdvancedIBIGCSEA-Level

Complete Formula Sheet

Use this page as a final revision sheet. Each formula is written in PHYSICS form with symbol meaning, unit sense and exam use. The most common mistake in Oscillations is using the correct-looking formula in the wrong situation, so read the exam-use line carefully.

SHM Core Formulae

Restoring acceleration

a = −ω2x

Symbols and units: a is acceleration, ω is angular frequency, x is displacement from mean. Unit of a is m s−2.

Exam use: Use this to identify SHM. If acceleration is proportional to displacement and opposite in direction, motion is SHM.

Angular frequency

ω = 2π/T = 2πf

Symbols and units: T is time period in seconds and f is frequency in Hz. Unit of ω is rad s−1.

Exam use: Use to convert between time period, frequency and angular frequency.

Frequency-period relation

f = 1/T

Symbols and units: f is number of oscillations per second. Unit is Hz.

Exam use: Use in direct MCQs and graph-based questions.

Maximum speed

vmax = Aω

Symbols and units: A is amplitude. Unit is m s−1.

Exam use: Use at mean position where x = 0.

Maximum acceleration

amax = Aω2

Symbols and units: A is amplitude. Unit is m s−2.

Exam use: Use at extreme positions where x = ±A.

Displacement, Velocity and Acceleration

Displacement sine form

x = A sin(ωt + φ)

Symbols and units: φ is initial phase. x is displacement.

Exam use: Use when initial position and direction are given.

Displacement basic form

x = A sin(ωt)

Symbols and units: Starts from mean position and initially moves in positive direction.

Exam use: Use for standard graph questions.

Velocity from displacement

v = Aω cos(ωt)

Symbols and units: Velocity leads displacement by π/2 for x = A sin(ωt).

Exam use: Use to draw v-t graph correctly.

Acceleration from displacement

a = −Aω2 sin(ωt)

Symbols and units: Acceleration is opposite in phase to displacement.

Exam use: Use to draw a-t graph and compare phases.

Velocity-displacement relation

v2 = ω2(A2 − x2)

Symbols and units: Speed depends on position, maximum at mean and zero at extremes.

Exam use: Very important for NEET and JEE numericals.

Phase and Phase Difference

Phase

Phase = ωt + φ

Symbols and units: Phase tells the state of oscillation at an instant. Unit is radian.

Exam use: Use to compare two oscillations.

Phase difference

Δφ = φ2 − φ1

Symbols and units: Positive or negative sign indicates lead or lag.

Exam use: Use in graph comparison and wave-SHM analogy.

Velocity phase

v = Aω sin(ωt + π/2)

Symbols and units: Velocity leads displacement by π/2.

Exam use: Use in phase relation MCQs.

Acceleration phase

a = Aω2 sin(ωt + π)

Symbols and units: Acceleration differs from displacement by π.

Exam use: Use to remember a is opposite in phase with x.

Time difference

Δt = Δφ/ω

Symbols and units: Convert phase difference to time difference.

Exam use: Useful in JEE Main conceptual numericals.

Spring-Mass Formulae

Spring restoring force

F = −kx

Symbols and units: k is spring constant in N m−1.

Exam use: Use Hooke law and identify restoring force.

Spring angular frequency

ω = √(k/m)

Symbols and units: m is attached mass in kg.

Exam use: Use for horizontal or vertical spring about equilibrium.

Spring time period

T = 2π√(m/k)

Symbols and units: Time period increases with mass and decreases with stiffness.

Exam use: Most common spring formula.

Spring frequency

f = (1/2π)√(k/m)

Symbols and units: Frequency of spring block.

Exam use: Use when asked oscillations per second.

Vertical spring static extension

T = 2π√(y/g)

Symbols and units: y is static extension with mg = ky.

Exam use: Useful shortcut for vertical spring problems.

Spring Cut, Series, Parallel and Both Sides

Cut spring constant

k' = nk

Symbols and units: If spring of constant k is cut into n equal parts, each part has constant nk.

Exam use: Do not write k/n. Shorter spring is stiffer.

Cut spring period

T' = T/√n

Symbols and units: Using one cut part with same mass.

Exam use: Important JEE trap.

Series springs

1/keq = 1/k1 + 1/k2

Symbols and units: Series combination is softer.

Exam use: Use when same force passes through springs.

Parallel springs

keq = k1 + k2

Symbols and units: Parallel combination is stiffer.

Exam use: Use when extensions are same.

Block between two springs

keff = k1 + k2

Symbols and units: Both springs give restoring force toward mean.

Exam use: Use T = 2π√(m/(k1 + k2)).

Simple Pendulum Formulae

Pendulum period

T = 2π√(L/g)

Symbols and units: L is effective length in m, g in m s−2.

Exam use: Valid for small angular displacement.

Pendulum frequency

f = (1/2π)√(g/L)

Symbols and units: Frequency increases when g increases and decreases when length increases.

Exam use: Use in clock questions.

Effective length

L = distance from suspension point to centre of bob

Symbols and units: For spherical bob, include radius if string length is to top of bob.

Exam use: Common practical exam trap.

Seconds pendulum

T = 2 s

Symbols and units: Time from one extreme to the other is 1 s.

Exam use: Approximate length near Earth is about 1 m.

Small-angle condition

sin θ ≈ θ

Symbols and units: Needed for pendulum SHM.

Exam use: Large-angle pendulum is not exactly SHM.

Energy in SHM

Kinetic energy

K = ½mω2(A2 − x2)

Symbols and units: K is maximum at mean and zero at extremes.

Exam use: Use for energy-position questions.

Potential energy

U = ½mω2x2

Symbols and units: U is zero at mean and maximum at extremes.

Exam use: Do not make U negative in basic SHM energy graphs.

Total energy

E = ½mω2A2

Symbols and units: Total energy remains constant in ideal SHM.

Exam use: Use conservation of energy.

Equal energy point

K = U at x = ±A/√2

Symbols and units: At this displacement, each energy is E/2.

Exam use: Very common MCQ.

Energy time periods

TK = T/2, TU = T/2, TE = ∞

Symbols and units: K and U repeat twice in one oscillation, total energy does not oscillate.

Exam use: High-yield graph concept.

Resonance and Quality Factor

Damping force

Fd = −bv

Symbols and units: Damping force is opposite to velocity.

Exam use: Use in damped oscillation basics.

Forced oscillation driver

F = F0sin(ωt)

Symbols and units: External periodic driving force.

Exam use: Use to distinguish driving frequency from natural frequency.

Resonance condition

f ≈ f0

Symbols and units: Driving frequency nearly equals natural frequency for light damping.

Exam use: Use in resonance applications.

Quality factor

Q = f0/Bandwidth

Symbols and units: Q is dimensionless.

Exam use: High Q means sharp resonance and low damping.

Bandwidth

Bandwidth = f2 − f1

Symbols and units: f1 and f2 are half-power frequencies.

Exam use: Use in JEE graph/numerical questions.

Correct Diagrams and Graphs

SHM x-t, v-t, a-t Graphs

txv starts maxa opposite x

Spring Block System

restoring forcem

Cut Spring: k' = nk

original spring: keach piece: k' = nk

Springs in Series and Parallel

series: softerparallel: stiffer

Simple Pendulum

θmmean position

Energy in SHM

E constantUK−A+Ax

Resonance Curve

AmplitudeFrequencyresonancelight dampingheavy damping

Block Between Two Springs

k1k2keff = k1 + k2m

NCERT Examples and Exercise-Style Questions

These questions follow the NCERT style: direct formulas, unit sense, simple substitutions and conceptual checks.

NCERT Example

1. A particle executes SHM with amplitude 5 cm and angular frequency 4 rad/s. Find maximum speed.

Show Solution

vmax = Aω = 0.05 × 4 = 0.20 m/s.

NCERT Example

2. For x = 0.03 m, A = 0.05 m and ω = 10 rad/s, find speed.

Show Solution

v2 = ω2(A2 − x2) = 100(0.0025 − 0.0009) = 0.16, so v = 0.4 m/s.

NCERT Example

3. A spring of k = 100 N/m carries m = 1 kg. Find T.

Show Solution

T = 2π√(m/k) = 2π√(1/100) = π/5 s.

NCERT Exercise

4. A pendulum has L = 1 m and g = π2 m/s2. Find T.

Show Solution

T = 2π√(L/g) = 2 s.

NCERT Exercise

5. If the length of a pendulum becomes 4 times, what happens to time period?

Show Solution

T ∝ √L, so time period becomes 2 times.

NCERT Exercise

6. If amplitude of SHM doubles, what happens to total energy?

Show Solution

E ∝ A2, so energy becomes 4 times.

NCERT Exercise

7. Find x where kinetic and potential energies are equal.

Show Solution

K = U gives A2 − x2 = x2, so x = ±A/√2.

NCERT Example

8. A spring is cut into 4 equal parts. Find spring constant of each part.

Show Solution

Each part has k' = nk = 4k.

NCERT Exercise

9. Original spring period is 6 s. Spring is cut into 9 parts and one part is used. Find new period.

Show Solution

T' = T/√n = 6/3 = 2 s.

NCERT Example

10. For a block between springs k1 = 50 N/m and k2 = 150 N/m, find keff.

Show Solution

keff = k1 + k2 = 200 N/m.

NCERT Exercise

11. If K = 0 at an extreme, what is U there?

Show Solution

At extreme x = ±A, U = E and K = 0.

NCERT Exercise

12. What is the time period of kinetic energy if displacement has period T?

Show Solution

Kinetic energy repeats after T/2 because it depends on speed squared.

Need Help With Oscillations?

If Oscillations formulas or PYQs are not clear and you are looking for a Physics Tutor, contact Kumar Sir.

PYQs and Exam Question Bank

Includes CBSE, NEET, JEE Main, JEE Advanced, IB, IGCSE, A-Level, assertion-reason, true/false, case study, conceptual and difficult numerical questions.

CBSE PYQ

1. State the condition for SHM.

Show Answer

Acceleration must be directly proportional to displacement and opposite in direction: a = −ω2x.

CBSE PYQ

2. Write the expression for displacement in SHM.

Show Answer

x = A sin(ωt + φ).

CBSE PYQ

3. What is the phase difference between displacement and acceleration?

Show Answer

π radian. They are opposite in phase.

CBSE PYQ

4. Define time period and frequency.

Show Answer

Time period is time for one complete oscillation. Frequency is number of oscillations per second.

CBSE PYQ

5. Write energy of particle executing SHM.

Show Answer

E = ½mω2A2.

NEET PYQ

6. At mean position of SHM, which energy is maximum?

Show Answer

Kinetic energy is maximum and potential energy is minimum.

NEET PYQ

7. At extreme position in SHM, velocity is?

Show Answer

Zero.

NEET PYQ

8. If amplitude is doubled, total energy becomes?

Show Answer

Four times.

NEET PYQ

9. For a spring block, T depends on which quantities?

Show Answer

Mass m and spring constant k.

NEET PYQ

10. For a simple pendulum, period is independent of?

Show Answer

Mass of bob and small amplitude.

NEET PYQ

11. If pendulum length becomes 9 times, period becomes?

Show Answer

3 times.

NEET PYQ

12. A spring is cut into 4 equal parts. New k of one part is?

Show Answer

4k.

NEET PYQ

13. Time period using one part of spring cut into n equal parts is?

Show Answer

T' = T/√n.

NEET PYQ

14. K = U in SHM at what displacement?

Show Answer

x = ±A/√2.

NEET PYQ

15. Time period of potential energy in SHM is?

Show Answer

T/2.

JEE Main PYQ

16. For x = A sin(ωt), write velocity.

Show Answer

v = Aω cos(ωt).

JEE Main PYQ

17. For x = A sin(ωt), write acceleration.

Show Answer

a = −Aω2 sin(ωt).

JEE Main PYQ

18. Find v-x relation in SHM.

Show Answer

v2 = ω2(A2 − x2).

JEE Main PYQ

19. Two springs k and k are in series. Equivalent k is?

Show Answer

k/2.

JEE Main PYQ

20. Two springs k and k are in parallel. Equivalent k is?

Show Answer

2k.

JEE Main PYQ

21. Block between k1 and k2. Effective k is?

Show Answer

k1 + k2.

JEE Main PYQ

22. Block between two springs has period?

Show Answer

T = 2π√(m/(k1 + k2)).

JEE Main PYQ

23. Static extension of vertical spring is y. Find period.

Show Answer

T = 2π√(y/g).

JEE Main PYQ

24. A seconds pendulum has period?

Show Answer

2 s.

JEE Main PYQ

25. A seconds pendulum takes time from one extreme to another?

Show Answer

1 s.

JEE Advanced PYQ

26. Three identical springs in series give period compared to one spring?

Show Answer

keq = k/3, so T' = √3 T.

JEE Advanced PYQ

27. Three identical springs in parallel give period compared to one spring?

Show Answer

keq = 3k, so T' = T/√3.

JEE Advanced PYQ

28. Spring cut into 4 parts and mass becomes 4m. New period?

Show Answer

k' = 4k and m' = 4m, so T remains same.

JEE Advanced PYQ

29. If velocity leads displacement by π/2, what does acceleration do?

Show Answer

Acceleration leads velocity by π/2 and differs from displacement by π.

JEE Advanced PYQ

30. Write ellipse relation between x and v.

Show Answer

x2/A2 + v2/(A2ω2) = 1.

JEE Advanced PYQ

31. Write relation between a and x in SHM.

Show Answer

a = −ω2x.

IB Question

32. Explain why total energy in ideal SHM is constant.

Show Answer

Energy changes form between kinetic and potential, but their sum stays constant without damping.

IB Question

33. What is meant by phase difference?

Show Answer

Difference between phases of two oscillations or two quantities in the same oscillation.

IGCSE Question

34. How can period of pendulum be measured accurately?

Show Answer

Measure time for many oscillations and divide by number of oscillations.

IGCSE Question

35. What happens to pendulum period if bob mass changes?

Show Answer

No change for small oscillations.

A-Level Question

36. Why is simple pendulum SHM only for small angles?

Show Answer

Because sin θ ≈ θ only for small angles.

A-Level Question

37. What does high Q indicate in resonance?

Show Answer

Sharp resonance, low damping and narrow bandwidth.

Assertion-Reason

38. Assertion: A shorter part of a spring is stiffer. Reason: spring constant is inversely proportional to length.

Show Answer

Both are true and reason explains assertion.

Assertion-Reason

39. Assertion: Kinetic energy has period T/2. Reason: K depends on square of velocity.

Show Answer

Both are true and reason explains assertion.

Assertion-Reason

40. Assertion: Pendulum period depends on mass. Reason: heavier bob has greater weight.

Show Answer

Assertion is false; reason is true but mass cancels.

True/False

41. Total energy in ideal SHM oscillates with period T/2.

Show Answer

False. Total energy is constant; no oscillation.

True/False

42. Potential energy is maximum at mean position.

Show Answer

False. It is minimum at mean position.

True/False

43. Velocity is maximum at mean position.

Show Answer

True.

True/False

44. Acceleration is maximum in magnitude at extremes.

Show Answer

True.

True/False

45. Resonance always gives infinite amplitude in real systems.

Show Answer

False. Damping limits amplitude.

Case Study

46. A pendulum clock runs slow in summer. Explain.

Show Answer

Length increases due to thermal expansion, so period increases and clock runs slow.

Case Study

47. A vehicle suspension uses damping. Why?

Show Answer

To remove energy and reduce repeated oscillations after bumps.

Case Study

48. A radio selects one station. Which oscillation idea is used?

Show Answer

Electrical resonance and frequency selectivity.

Conceptual

49. Why is K never negative in SHM energy formula?

Show Answer

K = ½mv2, and square of velocity is non-negative.

Conceptual

50. Why is U never negative in standard SHM spring energy?

Show Answer

U = ½kx2, and square of displacement is non-negative.

Difficult Numerical

51. For A = 10 cm and x = 6 cm, find K/E.

Show Answer

K/E = (A2 − x2)/A2 = (100 − 36)/100 = 0.64.

Difficult Numerical

52. For f0 = 500 Hz and bandwidth 20 Hz, find Q.

Show Answer

Q = 500/20 = 25.

Difficult Numerical

53. A spring period is T. It is cut into 16 equal parts. Period with one part is?

Show Answer

T' = T/√16 = T/4.

Difficult Numerical

54. Four identical springs are in parallel. Period compared to one spring?

Show Answer

keq = 4k, so T' = T/2.

Difficult Numerical

55. Four identical springs are in series. Period compared to one spring?

Show Answer

keq = k/4, so T' = 2T.

Difficult Numerical

56. If g becomes g/4, pendulum period becomes?

Show Answer

T ∝ 1/√g, so T becomes 2T.

Difficult Numerical

57. If mass in spring block becomes 9m, period becomes?

Show Answer

T ∝ √m, so T becomes 3T.

Difficult Numerical

58. If k becomes 9k, period becomes?

Show Answer

T ∝ 1/√k, so period becomes T/3.

Quick Revision Notes

SHM

  • a = −ω2x
  • x = A sin(ωt)
  • v = Aω cos(ωt)
  • a = −Aω2 sin(ωt)

Springs

  • T = 2π√(m/k)
  • Cut into n parts: k' = nk
  • Cut part period: T' = T/√n
  • Both sides: keff = k1 + k2

Pendulum

  • T = 2π√(L/g)
  • Seconds pendulum: T = 2 s
  • Use effective length
  • Small-angle condition is needed

Energy

  • K = ½mω2(A2 − x2)
  • U = ½mω2x2
  • E = ½mω2A2
  • K = U at x = ±A/√2

Energy Period

  • Time period of K = T/2
  • Time period of U = T/2
  • Total energy period = ∞ / no oscillation
  • K and U are never negative

Resonance

  • f ≈ f0
  • Q = f0/Bandwidth
  • High Q means sharp resonance
  • Damping lowers and broadens peak

If Oscillations formulas or PYQs are not clear and you are looking for a Physics Tutor, contact Kumar Sir.

Phone: +91-9958461445   Email: kumarsirphysics@gmail.com   Website: https://kumarphysicsclasses.com

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