Continuous Spectrum
A continuous spectrum contains all wavelengths without gaps. It is produced by hot solids, liquids and dense gases at high temperature — e.g. incandescent bulb filament or sunlight through a prism (before selective absorption).
Study line spectrum, emission spectrum, absorption spectrum, spectral series, Rydberg formula and important numericals.
Continuous, emission and absorption spectra — foundation of atomic spectroscopy.
A continuous spectrum contains all wavelengths without gaps. It is produced by hot solids, liquids and dense gases at high temperature — e.g. incandescent bulb filament or sunlight through a prism (before selective absorption).
When atoms in an excited gas de-excite, they emit photons of specific energies. The result is a bright line spectrum — coloured lines on a dark background.
When white light passes through cool gas, atoms absorb photons matching their transition energies. The continuous spectrum shows dark lines at those wavelengths.
Hydrogen has discrete quantised energy levels (Bohr model). Electrons can only absorb or emit photons with energy exactly equal to the difference between two allowed levels — hence discrete spectral lines.
Discrete lines from quantised electron transitions.
A line spectrum consists of sharp, discrete wavelengths (or frequencies) rather than a continuous spread. For hydrogen, each line corresponds to a unique electron transition between two energy levels.
When an electron moves from a higher orbit n₂ to a lower orbit n₁, energy is released as a photon: hν = En₂ − En₁. Because only certain orbits are allowed, only certain photon energies — and hence wavelengths — are observed.
Bright line spectrum from de-excitation of hydrogen atoms.
Electrical discharge, heat or photon absorption raises electrons to higher energy states (n = 2, 3, 4 …).
The excited state is unstable. The electron spontaneously falls to a lower permitted orbit.
The energy difference appears as a photon: ΔE = hν = hc/λ.
Each transition produces one spectral line. The collection of all possible transitions gives the complete emission spectrum of hydrogen.
Dark lines in a continuous background.
When white light (continuous spectrum) passes through hydrogen gas at low pressure:
Unified expression for all hydrogen spectral lines.
From Bohr's energy formula Eₙ = −13.6/n² eV, the photon energy for a transition is:
Converting to wave number (1/λ) gives the Rydberg formula with R = me⁴/(8ε₀²h³c) ≈ 1.097×10⁷ m⁻¹.
Ultraviolet region. Shortest λ ≈ 91.2 nm (series limit).
Visible region. Hα = 656 nm, Hβ = 486 nm, Hγ = 434 nm.
Infrared region. λ > 820 nm.
Infrared. Discovered 1922.
Far infrared. Discovered 1924.
Transitions to ground state — ultraviolet.
91.2 nm (series limit) to 121.6 nm (Lyman-α, n=2→1)
Ultraviolet (UV). Not visible to the naked eye.
Stellar UV spectroscopy, interstellar hydrogen detection, laboratory discharge tube studies.
Transitions to n = 2 — visible hydrogen lines.
n=3→2
656.3 nm
Red line
n=4→2
486.1 nm
Blue-green
n=5→2
434.0 nm
Violet
Astronomical red-shift measurement, hydrogen identification in stars, spectroscopy labs.
Transitions to n = 3 — infrared.
820 nm (series limit) to 1875 nm (first line, n=4→3). All lines lie in the infrared region.
Infrared astronomy, molecular physics laboratories, semiconductor industry spectroscopy.
NCERT diagrams — circular orbits and energy level diagram.
All important hydrogen spectrum formulae.
Basic, medium and advanced — wavelength, frequency, photon energy, spectral series.
n₂=2, n₁=1, R=1.097×10⁷ m⁻¹
1/λ = 1.097×10⁷(1 − 1/4) = 8.228e+06 m⁻¹
λ = 121.5 nm
Lyman series lies in ultraviolet region.
n₂=3, n₁=1, R=1.097×10⁷ m⁻¹
1/λ = 1.097×10⁷(1 − 1/9) = 9.751e+06 m⁻¹
λ = 102.6 nm
Lyman series lies in ultraviolet region.
n₂=4, n₁=1, R=1.097×10⁷ m⁻¹
1/λ = 1.097×10⁷(1 − 1/16) = 1.028e+07 m⁻¹
λ = 97.2 nm
Lyman series lies in ultraviolet region.
n₂=5, n₁=1, R=1.097×10⁷ m⁻¹
1/λ = 1.097×10⁷(1 − 1/25) = 1.053e+07 m⁻¹
λ = 95.0 nm
Lyman series lies in ultraviolet region.
n₂=6, n₁=1, R=1.097×10⁷ m⁻¹
1/λ = 1.097×10⁷(1 − 1/36) = 1.067e+07 m⁻¹
λ = 93.8 nm
Lyman series lies in ultraviolet region.
n₂=7, n₁=1, R=1.097×10⁷ m⁻¹
1/λ = 1.097×10⁷(1 − 1/49) = 1.075e+07 m⁻¹
λ = 93.1 nm
Lyman series lies in ultraviolet region.
n₂=3, n₁=2
ΔE=1.889 eV
λ ≈ 656.3 nm (Balmer series)
This is a Balmer series line.
n₂=4, n₁=2
ΔE=2.550 eV
λ ≈ 486.1 nm (Balmer series)
This is a Balmer series line.
n₂=5, n₁=2
ΔE=2.856 eV
λ ≈ 434.0 nm (Balmer series)
This is a Balmer series line.
n₂=6, n₁=2
ΔE=3.022 eV
λ ≈ 410.2 nm (Balmer series)
This is a Balmer series line.
n₂=7, n₁=2
ΔE=3.122 eV
λ ≈ 397.0 nm (Balmer series)
This is a Balmer series line.
n₂=4, n₁=3
ΔE=0.661 eV
λ ≈ 1875.1 nm (Paschen series)
This is a Paschen series line.
n₂=5, n₁=3
ΔE=0.967 eV
λ ≈ 1281.8 nm (Paschen series)
This is a Paschen series line.
n₂=6, n₁=3
ΔE=1.133 eV
λ ≈ 1093.8 nm (Paschen series)
This is a Paschen series line.
n₂=5, n₁=4
ΔE=0.306 eV
λ ≈ 4051.2 nm (Brackett series)
This is a Brackett series line.
n₂=6, n₁=4
ΔE=0.472 eV
λ ≈ 2625.1 nm (Brackett series)
This is a Brackett series line.
n₂=6, n₁=5
ΔE=0.166 eV
λ ≈ 7457.8 nm (Pfund series)
This is a Pfund series line.
n₂=2, n₁=2
ΔE = 13.6(1/4 − 1/4)
0.000 eV
Balmer series is in visible region for lower members.
n₂=3, n₁=2
ΔE = 13.6(1/4 − 1/9)
1.889 eV
Balmer series is in visible region for lower members.
n₂=4, n₁=2
ΔE = 13.6(1/4 − 1/16)
2.550 eV
Balmer series is in visible region for lower members.
n₂=5, n₁=2
ΔE = 13.6(1/4 − 1/25)
2.856 eV
Balmer series is in visible region for lower members.
n₂=6, n₁=2
ΔE = 13.6(1/4 − 1/36)
3.022 eV
Balmer series is in visible region for lower members.
n₂=7, n₁=2
ΔE = 13.6(1/4 − 1/49)
3.122 eV
Balmer series is in visible region for lower members.
n₂=2, n₁=1
ν = 1.097×10⁷ × 3×10⁸ × (1 − 1/4)
ν = 2.468e+15 Hz
Use c = 3×10⁸ m/s.
n₂=3, n₁=1
ν = 1.097×10⁷ × 3×10⁸ × (1 − 1/9)
ν = 2.925e+15 Hz
Use c = 3×10⁸ m/s.
n₂=4, n₁=1
ν = 1.097×10⁷ × 3×10⁸ × (1 − 1/16)
ν = 3.085e+15 Hz
Use c = 3×10⁸ m/s.
n₂=5, n₁=1
ν = 1.097×10⁷ × 3×10⁸ × (1 − 1/25)
ν = 3.159e+15 Hz
Use c = 3×10⁸ m/s.
n₂=6, n₁=1
ν = 1.097×10⁷ × 3×10⁸ × (1 − 1/36)
ν = 3.200e+15 Hz
Use c = 3×10⁸ m/s.
n₂=7, n₁=1
ν = 1.097×10⁷ × 3×10⁸ × (1 − 1/49)
ν = 3.224e+15 Hz
Use c = 3×10⁸ m/s.
n₁=1, n₂=∞
λ = 1240 / 13.600
≈ 91.2 nm
Lyman series terminates at n₁=1.
n₁=2, n₂=∞
λ = 1240 / 3.400
≈ 364.7 nm
Balmer series terminates at n₁=2.
n₁=3, n₂=∞
λ = 1240 / 1.511
≈ 820.6 nm
Paschen series terminates at n₁=3.
n₁=4, n₂=∞
λ = 1240 / 0.850
≈ 1458.8 nm
Brackett series terminates at n₁=4.
n₁=5, n₂=∞
λ = 1240 / 0.544
≈ 2279.4 nm
Pfund series terminates at n₁=5.
n = 7
N = 7×6/2
21 lines
Count all possible downward transitions.
n = 3
N = 3×2/2
3 lines
Count all possible downward transitions.
n = 4
N = 4×3/2
6 lines
Count all possible downward transitions.
n = 5
N = 5×4/2
10 lines
Count all possible downward transitions.
n = 6
N = 6×5/2
15 lines
Count all possible downward transitions.
n = 7
N = 7×6/2
21 lines
Count all possible downward transitions.
n = 7
N = 7×6/2
21 lines
Count all possible downward transitions.
n = 3
N = 3×2/2
3 lines
Count all possible downward transitions.
n = 4
N = 4×3/2
6 lines
Count all possible downward transitions.
n = 5
N = 5×4/2
10 lines
Count all possible downward transitions.
n = 6
N = 6×5/2
15 lines
Count all possible downward transitions.
n = 7
N = 7×6/2
21 lines
Count all possible downward transitions.
n = 7
N = 7×6/2
21 lines
Count all possible downward transitions.
n = 3
N = 3×2/2
3 lines
Count all possible downward transitions.
n = 4
N = 4×3/2
6 lines
Count all possible downward transitions.
n = 5
N = 5×4/2
10 lines
Count all possible downward transitions.
n = 6
N = 6×5/2
15 lines
Count all possible downward transitions.
n = 7
N = 7×6/2
21 lines
Count all possible downward transitions.
1 mark, 2 mark, 3 mark, 5 mark and case study questions.
Spectrum produced when atoms emit radiation at specific wavelengths.
Write series name and wavelength range in CBSE answers.
Spectrum consisting of discrete bright or dark lines.
Write series name and wavelength range in CBSE answers.
R = 1.097 × 10⁷ m⁻¹.
Write series name and wavelength range in CBSE answers.
Balmer series.
Write series name and wavelength range in CBSE answers.
Continuous: all wavelengths; Line: discrete wavelengths only.
Write series name and wavelength range in CBSE answers.
Due to quantised energy levels and discrete transitions.
Write series name and wavelength range in CBSE answers.
Excited electrons fall to lower levels emitting photons of definite energy.
Write series name and wavelength range in CBSE answers.
1/λ=R(1/n₁²−1/n₂²); n₁ lower, n₂ higher level.
Write series name and wavelength range in CBSE answers.
From Bohr model: Eₙ=−13.6/n² eV for hydrogen.
Write series name and wavelength range in CBSE answers.
All transitions ending at n=2.
Write series name and wavelength range in CBSE answers.
Spectrum produced when atoms emit radiation at specific wavelengths.
Write series name and wavelength range in CBSE answers.
Spectrum consisting of discrete bright or dark lines.
Write series name and wavelength range in CBSE answers.
R = 1.097 × 10⁷ m⁻¹.
Write series name and wavelength range in CBSE answers.
Balmer series.
Write series name and wavelength range in CBSE answers.
Continuous: all wavelengths; Line: discrete wavelengths only.
Write series name and wavelength range in CBSE answers.
Due to quantised energy levels and discrete transitions.
Write series name and wavelength range in CBSE answers.
Excited electrons fall to lower levels emitting photons of definite energy.
Write series name and wavelength range in CBSE answers.
1/λ=R(1/n₁²−1/n₂²); n₁ lower, n₂ higher level.
Write series name and wavelength range in CBSE answers.
From Bohr model: Eₙ=−13.6/n² eV for hydrogen.
Write series name and wavelength range in CBSE answers.
All transitions ending at n=2.
Write series name and wavelength range in CBSE answers.
Spectrum produced when atoms emit radiation at specific wavelengths.
Write series name and wavelength range in CBSE answers.
Spectrum consisting of discrete bright or dark lines.
Write series name and wavelength range in CBSE answers.
R = 1.097 × 10⁷ m⁻¹.
Write series name and wavelength range in CBSE answers.
Balmer series.
Write series name and wavelength range in CBSE answers.
Continuous: all wavelengths; Line: discrete wavelengths only.
Write series name and wavelength range in CBSE answers.
Due to quantised energy levels and discrete transitions.
Write series name and wavelength range in CBSE answers.
Excited electrons fall to lower levels emitting photons of definite energy.
Write series name and wavelength range in CBSE answers.
1/λ=R(1/n₁²−1/n₂²); n₁ lower, n₂ higher level.
Write series name and wavelength range in CBSE answers.
From Bohr model: Eₙ=−13.6/n² eV for hydrogen.
Write series name and wavelength range in CBSE answers.
All transitions ending at n=2.
Write series name and wavelength range in CBSE answers.
Spectrum produced when atoms emit radiation at specific wavelengths.
Write series name and wavelength range in CBSE answers.
Spectrum consisting of discrete bright or dark lines.
Write series name and wavelength range in CBSE answers.
R = 1.097 × 10⁷ m⁻¹.
Write series name and wavelength range in CBSE answers.
Balmer series.
Write series name and wavelength range in CBSE answers.
Continuous: all wavelengths; Line: discrete wavelengths only.
Write series name and wavelength range in CBSE answers.
Due to quantised energy levels and discrete transitions.
Write series name and wavelength range in CBSE answers.
Excited electrons fall to lower levels emitting photons of definite energy.
Write series name and wavelength range in CBSE answers.
1/λ=R(1/n₁²−1/n₂²); n₁ lower, n₂ higher level.
Write series name and wavelength range in CBSE answers.
From Bohr model: Eₙ=−13.6/n² eV for hydrogen.
Write series name and wavelength range in CBSE answers.
All transitions ending at n=2.
Write series name and wavelength range in CBSE answers.
Spectrum produced when atoms emit radiation at specific wavelengths.
Write series name and wavelength range in CBSE answers.
Spectrum consisting of discrete bright or dark lines.
Write series name and wavelength range in CBSE answers.
R = 1.097 × 10⁷ m⁻¹.
Write series name and wavelength range in CBSE answers.
Balmer series.
Write series name and wavelength range in CBSE answers.
Continuous: all wavelengths; Line: discrete wavelengths only.
Write series name and wavelength range in CBSE answers.
Due to quantised energy levels and discrete transitions.
Write series name and wavelength range in CBSE answers.
Excited electrons fall to lower levels emitting photons of definite energy.
Write series name and wavelength range in CBSE answers.
1/λ=R(1/n₁²−1/n₂²); n₁ lower, n₂ higher level.
Write series name and wavelength range in CBSE answers.
From Bohr model: Eₙ=−13.6/n² eV for hydrogen.
Write series name and wavelength range in CBSE answers.
All transitions ending at n=2.
Write series name and wavelength range in CBSE answers.
Last 20 years important questions — 100 with solutions.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
121.6 nm
NEET often asks series identification and wavelength.
Visible region
NEET often asks series identification and wavelength.
Infrared
NEET often asks series identification and wavelength.
1.097×10⁷ m⁻¹
NEET often asks series identification and wavelength.
≈1.89 eV
NEET often asks series identification and wavelength.
n=3 to n=2
NEET often asks series identification and wavelength.
Lyman
NEET often asks series identification and wavelength.
Dark lines at same wavelengths as emission
NEET often asks series identification and wavelength.
n=∞ to n=2
NEET often asks series identification and wavelength.
6
NEET often asks series identification and wavelength.
Single correct, numerical value type and integer type.
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
486.1 nm
10.2
10
91.2
1.097
50 difficult questions — single, multiple correct, numerical, matrix match.
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
2.47×10¹⁵
Lyman→1, Balmer→2, Paschen→3
4
656 nm, 486 nm, 434 nm
SL, HL, structured and data-based — 30 questions.
Discrete wavelength from atomic transition.
Predicts hydrogen wavelengths from quantum numbers.
Emission: bright lines; Absorption: dark lines in continuous spectrum.
≈1.89 eV
Discrete wavelength from atomic transition.
Predicts hydrogen wavelengths from quantum numbers.
Emission: bright lines; Absorption: dark lines in continuous spectrum.
≈1.89 eV
Discrete wavelength from atomic transition.
Predicts hydrogen wavelengths from quantum numbers.
Emission: bright lines; Absorption: dark lines in continuous spectrum.
≈1.89 eV
Discrete wavelength from atomic transition.
Predicts hydrogen wavelengths from quantum numbers.
Emission: bright lines; Absorption: dark lines in continuous spectrum.
≈1.89 eV
Discrete wavelength from atomic transition.
Predicts hydrogen wavelengths from quantum numbers.
Emission: bright lines; Absorption: dark lines in continuous spectrum.
≈1.89 eV
Discrete wavelength from atomic transition.
Predicts hydrogen wavelengths from quantum numbers.
Emission: bright lines; Absorption: dark lines in continuous spectrum.
≈1.89 eV
Discrete wavelength from atomic transition.
Predicts hydrogen wavelengths from quantum numbers.
Emission: bright lines; Absorption: dark lines in continuous spectrum.
≈1.89 eV
Discrete wavelength from atomic transition.
Predicts hydrogen wavelengths from quantum numbers.
MCQ, structured and long answer — 30 questions.
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Line spectrum
Quantised energy levels
Transitions to n=2, visible lines
Cambridge and Edexcel — 40 questions.
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
1/λ=R(1/n₁²−1/n₂²)
121.6 nm
Atoms absorb photons matching transition energies.
Paschen, Brackett, Pfund
50 assertion-reason questions with explanations.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Assertion false; Reason true.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason does not fully explain Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Assertion false; Reason true.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason does not fully explain Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Assertion false; Reason true.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason does not fully explain Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Assertion false; Reason true.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason does not fully explain Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Assertion false; Reason true.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason does not fully explain Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Assertion false; Reason true.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason does not fully explain Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
Both true; Reason explains Assertion.
The assertion concerns hydrogen spectral behaviour; the reason links to quantised atomic structure and the Rydberg relation.
25 case studies — 4 questions each with detailed solutions.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
Passage: A physics laboratory uses a hydrogen discharge tube and a spectrometer. When the gas is excited electrically, discrete coloured lines appear. Astronomers use the same principle to identify hydrogen in distant stars by matching observed wavelengths with the Rydberg formula 1/λ = R(1/n₁² − 1/n₂²).
Q1. Name the series for transitions ending at n=2. Answer: Balmer series.
Q2. Why are the lines discrete? Answer: Because only certain energy differences are allowed between quantised levels.
Q3. Calculate approximate wavelength for n=3→2. Answer: 656 nm (Hα line).
Q4. What region does the Lyman series lie in? Answer: Ultraviolet region.
One-page revision for exam day.
Hydrogen spectrum = discrete lines from quantised transitions. Emission = bright lines; Absorption = dark lines. Rydberg: 1/λ = R(1/n₁²−1/n₂²). Lyman (UV, n₁=1), Balmer (visible, n₁=2), Paschen (IR, n₁=3). Eₙ = −13.6/n² eV. ΔE = hν = hc/λ. λ(nm) = 1240/ΔE(eV).
✔ Remember: Lyman = UV (n₁=1), Balmer = Visible (n₁=2), Paschen/Brackett/Pfund = IR (n₁=3,4,5). ✔ Use λ(nm) = 1240/ΔE(eV) for quick calculations. ✔ Absorption lines appear at the same λ as emission lines. ✔ For "number of lines" questions: N = n(n−1)/2. ✔ Series limit corresponds to n₂ → ∞. ✔ R = 1.097 × 10⁷ m⁻¹ — memorise this value.