Electromagnetic Waves Formula Sheet

Given: Given circular plates radius r = 12 cm = 0.12 m, separation d = 5.0 cm = 0.05 m and charging current I = 0.15 A.

Formula:

1. A = π(0.12)² = 4.52×10^-2 m², C = (8.85×10^-12)(4.52×10^-2)/0.05 = 8.0×10^-12 F. dV/dt = I/C = 0.15/(8.0×10^-12) = 1.9×10¹⁰ V s^-1. Displacement current equals conduction current = 0.15 A. Kirchhoff junction rule is valid if displacement current is included.

Given: Given R = 6.0 cm, C = 100 pF, V_rms = 230 V, ω = 300 rad s^-1, point r = 3.0 cm.

Formula:

1. I_rms = 300×100×10^-12×230 = 6.9×10^-6 A. The conduction current equals displacement current. I₀ = √2 I_rms = 9.76×10^-6 A. For r<R, B = μ₀I₀r/(2πR²) = (4π×10^-7)(9.76×10^-6)(0.03)/(2π(0.06)²) = 1.6×10^-11 T.

Given: Wavelengths are different: X-rays, red light and radio waves.

Formula:

1. Their wavelengths and frequencies are different, but in vacuum their speed is the same.

Given: Frequency ν = 30 MHz = 3.0×10⁷ Hz.

Formula:

1. If wave travels along z-axis, E and B are perpendicular to z and also perpendicular to each other. λ = 3×10⁸/(3×10⁷) = 10 m.

Given: Frequency range 7.5 MHz to 12 MHz.

Formula:

1. For 7.5 MHz, λ = 3×10⁸/(7.5×10⁶) = 40 m. For 12 MHz, λ = 25 m.

Given: Oscillating charge frequency = 10⁹ Hz.

Formula:

1. An accelerated or oscillating charge emits EM waves of the same frequency as its oscillation.

Given: B₀ = 510 nT = 510×10^-9 T.

Formula:

1. E₀ = (3×10⁸)(510×10^-9) = 153 N C^-1.

Given: E₀ = 120 N C^-1, ν = 50.0 MHz.

Formula:

1. B₀ = 120/(3×10⁸) = 4.0×10^-7 T. ω = 2π(50×10⁶) = 3.14×10⁸ rad s^-1. λ = 3×10⁸/(50×10⁶) = 6.0 m. k = 2π/6 = 1.05 rad m^-1.

Given: Use photon energy formula for different frequencies.

Formula:

1. Radio photons have very small energy because frequency is small. X-ray and gamma photons have large energy because frequency is very high. This is why low-frequency waves are produced by circuits and high-frequency waves require atomic or nuclear processes.

Given: ν = 2.0×10¹⁰ Hz, E₀ = 48 V m^-1.

Formula:

1. λ=3×10⁸/(2×10¹⁰)=1.5×10^-2 m. B₀=48/(3×10⁸)=1.6×10^-7 T. Using E₀/B₀=c and c²=1/(μ₀ε₀), average magnetic energy density becomes equal to average electric energy density.

Given: E = (3.1 N/C) cos[(1.8 rad/m)y + (5.4×10⁶ rad/s)t] î.

Formula:

1. Since phase is ky + ωt, wave travels in negative y-direction. λ=2π/1.8=3.49 m. ν=5.4×10⁶/(2π)=8.6×10⁵ Hz. B₀=3.1/(3×10⁸)=1.03×10^-8 T. For propagation along -y and E along +x, B is along -z.

Given: 5% of 100 W is visible, so P = 5 W.

Formula:

1. At r=1 m, I=5/(4π)=0.40 W m^-2. At r=10 m, I=5/(4π×100)=0.0040 W m^-2.

Given: λ_mT = 0.29 cm K.

Formula:

1. Large wavelength corresponds to low temperature sources; small wavelength corresponds to high temperature sources. Radio/microwave correspond to very low characteristic temperatures, infrared to ordinary warm bodies, visible to hot bodies like filament or Sun, UV/X-rays to very high temperature processes.

Given: Given wavelengths/frequencies/energies: 21 cm, 1057 MHz, 2.7 K, 5890-5896 Å, 14.4 keV.

Formula:

1. 21 cm is radio wave. 1057 MHz is microwave/radio region. 2.7 K cosmic background peaks in microwave region. 5890-5896 Å sodium lines are visible yellow light. 14.4 keV transition is gamma ray region for nuclear transition.

Given: Questions on short-wave broadcast, TV transmission, X-ray astronomy, ozone layer, atmosphere and nuclear winter.

Formula:

1. Short waves are reflected by ionosphere and can travel long distances. TV signals have shorter wavelengths and are not reflected effectively by ionosphere, so satellites are needed. X-rays are absorbed by Earth atmosphere, so X-ray astronomy needs satellites. Ozone absorbs harmful UV radiation and protects life. Without atmosphere, greenhouse warming would be absent, so average temperature would be lower. Nuclear winter prediction is based on smoke and dust blocking sunlight after nuclear war.

Displacement current is I_d=ε₀dΦ_E/dt, associated with changing electric flux.

Their electric field, magnetic field and direction of propagation are mutually perpendicular.

∮B·dl = μ₀(I + I_d).

S=(E×B)/μ₀, representing energy flow per unit area per unit time.

Microwaves are used in radar, satellite communication and microwave ovens.

It absorbs harmful ultraviolet rays from the Sun.

E₀/B₀=c.

Pressure exerted by electromagnetic radiation on a surface.

Accelerated charges produce electromagnetic waves.

Atmosphere absorbs X-rays, so they must be observed above atmosphere.

Infrared and microwave regions are commonly used in remote sensing.

Short-wave radio waves are reflected by the ionosphere.

c = 3×10⁸ m s^-1.

Restriction of electric field vibrations to one plane.

u_E=½ε₀E².

Very short wavelength and high penetrating power.

They can pass through the ionosphere with low attenuation.

E=hν.

EM waves beyond red, mainly emitted by hot bodies.

c=νλ.

Microwaves are used in radar because they have suitable wavelength and can be directed in narrow beams.

Gamma rays have maximum photon energy in the electromagnetic spectrum.

Ampere-Maxwell law introduces displacement current.

E/B = c, the speed of light in vacuum.

Photon energy increases because E=hc/λ.

Ultraviolet rays, especially UV-B and UV-C, are absorbed by ozone.

Microwaves are used because they pass through the ionosphere.

Poynting vector describes EM energy flow.

Accelerated charges produce EM waves.

It is ε0 times the rate of change of electric flux.

Microwaves are used in radar because they have suitable wavelength and can be directed in narrow beams.

Gamma rays have maximum photon energy in the electromagnetic spectrum.

Ampere-Maxwell law introduces displacement current.

E/B = c, the speed of light in vacuum.

Photon energy increases because E=hc/λ.

Ultraviolet rays, especially UV-B and UV-C, are absorbed by ozone.

Microwaves are used because they pass through the ionosphere.

Poynting vector describes EM energy flow.

Accelerated charges produce EM waves.

It is ε0 times the rate of change of electric flux.

Microwaves are used in radar because they have suitable wavelength and can be directed in narrow beams.

Gamma rays have maximum photon energy in the electromagnetic spectrum.

Ampere-Maxwell law introduces displacement current.

E/B = c, the speed of light in vacuum.

Photon energy increases because E=hc/λ.

Ultraviolet rays, especially UV-B and UV-C, are absorbed by ozone.

Microwaves are used because they pass through the ionosphere.

Poynting vector describes EM energy flow.

Accelerated charges produce EM waves.

It is ε0 times the rate of change of electric flux.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Displacement current is I_d=ε₀dΦ_E/dt, associated with changing electric flux.

Their electric field, magnetic field and direction of propagation are mutually perpendicular.

∮B·dl = μ₀(I + I_d).

S=(E×B)/μ₀, representing energy flow per unit area per unit time.

Microwaves are used in radar, satellite communication and microwave ovens.

It absorbs harmful ultraviolet rays from the Sun.

E₀/B₀=c.

Pressure exerted by electromagnetic radiation on a surface.

Accelerated charges produce electromagnetic waves.

Atmosphere absorbs X-rays, so they must be observed above atmosphere.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Displacement current is I_d=ε₀dΦ_E/dt, associated with changing electric flux.

Their electric field, magnetic field and direction of propagation are mutually perpendicular.

∮B·dl = μ₀(I + I_d).

S=(E×B)/μ₀, representing energy flow per unit area per unit time.

Microwaves are used in radar, satellite communication and microwave ovens.

It absorbs harmful ultraviolet rays from the Sun.

E₀/B₀=c.

Pressure exerted by electromagnetic radiation on a surface.

Accelerated charges produce electromagnetic waves.

Atmosphere absorbs X-rays, so they must be observed above atmosphere.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Combining Maxwell equations for time-varying electric and magnetic fields gives wave equation with speed v=1/√(με). In vacuum μ=μ0 and ε=ε0, so c=1/√(μ0ε0).

Conduction current exists in wire but no charges cross dielectric gap. Maxwell added displacement current so magnetic field is continuous and Kirchhoff law remains valid.

For perfect reflector, momentum change doubles, so P=2I/c.

A changing electric field produces magnetic field and changing magnetic field produces electric field.

Using E/B=c and c²=1/(μ0ε0), electric and magnetic energy densities are equal on average.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Answer: Both are true and Reason correctly explains Assertion.

Explanation: The pair tests the relation between EM wave property and its physical cause.

Given: λ = 102 nm = 102×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(102×10^-9) = 2.94e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 4×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 4×10¹⁴ = 2.65e-19 J
2. Write the final answer with proper unit.

Given: B₀ = 130 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 130×10^-9 = 39.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 40 W m^-2

Formula:

1. P = I/c = 40/(3×10⁸) = 1.33e-07 N m^-2
2. Write the final answer with proper unit.

Given: C=5 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 5×10^-12 × 2×10⁹ = 1.00e-02 A
2. Write the final answer with proper unit.

Given: λ = 112 nm = 112×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(112×10^-9) = 2.68e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 9×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 9×10¹⁴ = 5.97e-19 J
2. Write the final answer with proper unit.

Given: B₀ = 180 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 180×10^-9 = 54.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 90 W m^-2

Formula:

1. P = I/c = 90/(3×10⁸) = 3.00e-07 N m^-2
2. Write the final answer with proper unit.

Given: C=10 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 10×10^-12 × 2×10⁹ = 2.00e-02 A
2. Write the final answer with proper unit.

Given: λ = 122 nm = 122×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(122×10^-9) = 2.46e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 14×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 14×10¹⁴ = 9.28e-19 J
2. Write the final answer with proper unit.

Given: B₀ = 230 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 230×10^-9 = 69.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 140 W m^-2

Formula:

1. P = I/c = 140/(3×10⁸) = 4.67e-07 N m^-2
2. Write the final answer with proper unit.

Given: C=15 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 15×10^-12 × 2×10⁹ = 3.00e-02 A
2. Write the final answer with proper unit.

Given: λ = 132 nm = 132×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(132×10^-9) = 2.27e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 19×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 19×10¹⁴ = 1.26e-18 J
2. Write the final answer with proper unit.

Given: B₀ = 280 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 280×10^-9 = 84.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 190 W m^-2

Formula:

1. P = I/c = 190/(3×10⁸) = 6.33e-07 N m^-2
2. Write the final answer with proper unit.

Given: C=20 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 20×10^-12 × 2×10⁹ = 4.00e-02 A
2. Write the final answer with proper unit.

Given: λ = 142 nm = 142×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(142×10^-9) = 2.11e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 24×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 24×10¹⁴ = 1.59e-18 J
2. Write the final answer with proper unit.

Given: B₀ = 330 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 330×10^-9 = 99.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 240 W m^-2

Formula:

1. P = I/c = 240/(3×10⁸) = 8.00e-07 N m^-2
2. Write the final answer with proper unit.

Given: C=25 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 25×10^-12 × 2×10⁹ = 5.00e-02 A
2. Write the final answer with proper unit.

Given: λ = 152 nm = 152×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(152×10^-9) = 1.97e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 29×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 29×10¹⁴ = 1.92e-18 J
2. Write the final answer with proper unit.

Given: B₀ = 380 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 380×10^-9 = 114.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 290 W m^-2

Formula:

1. P = I/c = 290/(3×10⁸) = 9.67e-07 N m^-2
2. Write the final answer with proper unit.

Given: C=30 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 30×10^-12 × 2×10⁹ = 6.00e-02 A
2. Write the final answer with proper unit.

Given: λ = 162 nm = 162×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(162×10^-9) = 1.85e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 34×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 34×10¹⁴ = 2.25e-18 J
2. Write the final answer with proper unit.

Given: B₀ = 430 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 430×10^-9 = 129.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 340 W m^-2

Formula:

1. P = I/c = 340/(3×10⁸) = 1.13e-06 N m^-2
2. Write the final answer with proper unit.

Given: C=35 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 35×10^-12 × 2×10⁹ = 7.00e-02 A
2. Write the final answer with proper unit.

Given: λ = 172 nm = 172×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(172×10^-9) = 1.74e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 39×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 39×10¹⁴ = 2.59e-18 J
2. Write the final answer with proper unit.

Given: B₀ = 480 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 480×10^-9 = 144.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 390 W m^-2

Formula:

1. P = I/c = 390/(3×10⁸) = 1.30e-06 N m^-2
2. Write the final answer with proper unit.

Given: C=40 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 40×10^-12 × 2×10⁹ = 8.00e-02 A
2. Write the final answer with proper unit.

Given: λ = 182 nm = 182×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(182×10^-9) = 1.65e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 44×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 44×10¹⁴ = 2.92e-18 J
2. Write the final answer with proper unit.

Given: B₀ = 530 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 530×10^-9 = 159.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 440 W m^-2

Formula:

1. P = I/c = 440/(3×10⁸) = 1.47e-06 N m^-2
2. Write the final answer with proper unit.

Given: C=45 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 45×10^-12 × 2×10⁹ = 9.00e-02 A
2. Write the final answer with proper unit.

Given: λ = 192 nm = 192×10^-9 m

Formula:

1. ν = c/λ = 3×10⁸/(192×10^-9) = 1.56e+15 Hz
2. Write the final answer with proper unit.

Given: ν = 49×10¹⁴ Hz

Formula:

1. E = hν = 6.63×10^-34 × 49×10¹⁴ = 3.25e-18 J
2. Write the final answer with proper unit.

Given: B₀ = 580 nT

Formula:

1. E₀ = cB₀ = 3×10⁸ × 580×10^-9 = 174.0 N C^-1
2. Write the final answer with proper unit.

Given: I = 490 W m^-2

Formula:

1. P = I/c = 490/(3×10⁸) = 1.63e-06 N m^-2
2. Write the final answer with proper unit.

Given: C=50 pF, dV/dt=2×10⁹ V s^-1

Formula:

1. I_d=C dV/dt = 50×10^-12 × 2×10⁹ = 1.00e-01 A
2. Write the final answer with proper unit.