A premium Physics-only practice page for serious NEET preparation, built from the PDF's Physics section Q1 to Q45 with clickable options, official answers, official solutions, and NEET-style marking.
This page is designed for disciplined self-assessment in Physics. Attempt every question with full concentration, check the correct answer only after making a choice, and then use the official solution to understand the reasoning behind the result.
The questions cover important Class 11 and Class 12 concepts that a NEET aspirant must handle with speed, accuracy, and clarity.
Physics is often the section that separates a good NEET score from an exceptional one. Biology and Chemistry reward memory and revision, but Physics demands conceptual command, mathematical confidence, and the ability to apply ideas under time pressure.
Students who build strong fundamentals in mechanics, heat, waves, optics, electricity, magnetism, and modern physics are better prepared for changing paper patterns. A strong Physics foundation also improves confidence because the student learns how to think through unfamiliar problems instead of depending only on memorised formulas.
Regular practice with concept-based questions helps students identify weak areas early, correct mistakes, and develop the calm problem-solving temperament required in a competitive examination.
Dear NEET Aspirants,
If you are preparing for Physics, you must understand that the NEET examination pattern in the coming years is expected to become more digital, more competitive, and more concept-oriented. From NEET 2027 onwards, students should prepare themselves for an online-style examination environment where speed, accuracy, conceptual clarity, and independent problem-solving will become extremely important.
Kumar Sir has been guiding students in Physics for more than 30 years with a strong focus on conceptual clarity, disciplined problem-solving, and exam-oriented preparation. His teaching style is not based on shortcuts alone; it is based on deep understanding. He believes that a student can score well in Physics only when the basic concepts are clear and the student knows how to apply those concepts in different types of questions.
The NEET Physics questions shared by Kumar Sir are carefully selected to help students understand their real preparation level. These are not ordinary practice questions. They are concept-based, application-oriented, and designed to test whether a student has truly understood the chapter or is only memorising formulas. Many students study in big coaching institutes and spend a lot of money, but their doubts often remain unresolved. Kumar Sir's question sets are created to fill that gap.
These questions cover important ideas from Class 11 and Class 12 Physics and are useful for serious NEET aspirants. By attempting these questions honestly, students can identify their weak areas, improve accuracy, build confidence, and develop the ability to think logically under exam pressure. The questions are useful not only for practice but also for self-assessment.
Kumar Sir strongly advises students to first revise the chapter properly, then solve the questions with a timer, and only after that check the answers and solutions. This method helps students develop examination temperament and deeper understanding.
If a student finds Physics difficult or feels that concepts are not clear, Kumar Sir provides personalised one-to-one online Physics classes. His guidance can help students strengthen fundamentals, clear doubts, and prepare effectively for NEET, CBSE, JEE, IB, IGCSE, AP Physics and other examinations.
A spring executes SHM with mass of 4 kg attached to it. The force constant of spring is 100 N/m. If at any instant its velocity is 40 cm/s, the displacement from the mean position will be (Here amplitude is 0.5 m).
v = ω√(A2 - x2)
v = √(k/m) √(A2 - x2)
v = 5√(A2 - x2) = 40 × 10-2
(402/52) × 10-4 = (0.50)2 - x2
x = 0.49 m
A star is going away from earth with a speed of 100 km/s. Find the shift in wavelength of a 6900 Å ray produced by it, when observed from earth.
Δλ = (v/c)λ = (105 / 3 × 108) × 6900 Å
Shift in wavelength = 2.3 Å.
Which of the following statements are true during the propagation of a plane progressive harmonic mechanical wave in a non-dissipative medium?
I. All the particles are vibrating in the same phase.
II. Amplitudes of all the particles are equal.
III. Particles of medium executes S.H.M.
IV. Wave velocity depends upon the nature of the medium.
Factual.
The angle of a prism is A. One of its refracting surfaces is silvered. Light rays falling at an angle of incidence 2A on the first surface returns back through the same path after suffering reflection at the silvered surface. The refractive index μ of the prism is
r2 = 0
r1 = A - r2 ⇒ r1 = A
1 × sin(2A) = μ sin(A)
μ = 2 cos(A)
The half life of a radioactive nucleus is 100 days. The time interval (t1 - t2) between the time t2 when half of it has decayed and the time t1 when three-fourth of it had decayed is
t1 = 200 day
t2 = 100 day
Time interval = 100 days.
A conveyor belt is moving at a constant speed of 4 m/s. A box is gently dropped on it. The coefficient of friction between them is μ = 0.2. The distance that the box will move relative to ground before coming to rest with respect to belt, is
a = μg = 2 m/s2
v = u + at
4 = 2 × t ⇒ t = 2 s
s = 1/2 at2 = 1/2 × 2 × 22 = 4 m
For transistor action
a. Base, emitter and collector regions should have similar size and doping concentrations.
b. The base region must be very thin and lightly doped.
c. The emitter-base junction is forward biased and base-collector junction is reverse biased.
d. Both the emitter-base junction as well as the base collector junction are forward biased.
Which one of the following pairs of statements is correct?
For transistor action BE junction → forward bias.
BC junction → reverse bias.
Length profile: C > E > B
Doping profile: E > C > B
A hollow sphere of mass m is rolling with a speed v on a smooth horizontal surface and strikes a massless spring of force constant k attached to a massless smooth platform. Then the maximum compression of spring is
The translational KE = 1/2 kx2
1/2 mv2 = 1/2 kx2
x = √(m/k) v
Space between plates of a capacitor (of area A) is filled with two dielectric slabs of dielectric constants k1 and k2. The capacitor is connected to battery of emf E, then the charge stored on the capacitor will be (d2 = 1.5d1 and k1 = 2k2).
C = ε0Ak2 / 2d1
q = CE
q = ε0Ak2E / 2d1
The diameter of a cylinder is measured with a meter rod having least count 0.1 cm. Its length is measured with Vernier calipers having least count 0.01 cm. Given that length is 2.00 cm and diameter is 4.0 cm. The percentage error in the calculated value of the curved surface area will be
ΔS/S = Δd/d + Δℓ/ℓ
Percentage error = 3%.
The coefficient of static friction between the two blocks shown in figure is μ and the table is smooth. What maximum horizontal force F can be applied to the block of mass M so that the blocks move together?
F/(m + M) = μg
F = (m + M)μg
A body of mass m is released from the top of a fixed rough inclined plane as shown in figure. If the frictional force has magnitude F, then body will reach the bottom with a velocity (L = √2h).
1/2 mv2 = mgh - FL
1/2 mv2 = mgh - √2hF
v = √(2gh - 2√2Fh/m)
A particle of mass m is moving in a horizontal circle of radius r, under a centripetal force equal to (-k/r2), where k is a constant. The magnitude of kinetic energy of the particle is proportional to
mv2/r = k/r2
1/2 mv2 = 1/2 k/r
Kinetic energy is proportional to r-1.
The potential energy between two atoms in a molecule is given by U(x) = a/x12 - b/x6, where a and b are positive constant and x is the distance between the atoms. The atoms are at equilibrium, when x is equal to
At equilibrium, ∂U/∂x = 0
12a/x13 = 6b/x7
x6 = 2a/b
A bullet of mass 0.01 kg travelling at a speed of 800 m/s strikes a block of mass 2 kg, which is suspended by a string of length 10 m. The centre of gravity of the block is found to rise a vertical distance of 0.2 m. The speed of the bullet after it emerges from the block will be
Speed of block after collision = √(2g × 0.2) = 2 m/s
Conservation of momentum:
0.01 × 800 = 2 × 2 + 0.01v
v = 400 m/s
Photoelectric emission occurs only when the incident light has more than a certain minimum
For photoelectric emission:
ν > ν0
Or hν > φ
The center of mass of a uniform triangular lamina shown in figure has coordinates (h = 6 m, b = 3 m).
COM = Centroid.
If linear mass density of a rod of length 3 m varies as μ = 2 + x2, then the position of the centre of mass of the rod is (w.r.t. to the end of the rod from where x is measured).
xCM = ∫03(2 + x2)x dx / ∫03(2 + x2) dx
xCM = 1.95 m
The angular momentum of a system of particles is conserved
τ = dL/dt
Angular momentum is conserved when no external torque acts on the system.
Two solid spheres each of mass M and radius R/2 are connected with a rod of mass M, connected to their surfaces normally, as shown in the figure. The moment of inertia of the system about an axis passing through the center of one of the spheres and perpendicular to the rod will be (center to center distance of the spheres is 2R).
IB = IA = (2/5)M(R/2)2 = MR2/10
I'B = M(2R)2 + MR2/10
IA + I'B = 21MR2/5
Irod = MR2/12 + MR2 = 13MR2/12
Inet = 317MR2/60
If g is the acceleration due to gravity on the earth’s surface, the gain in P.E. of an object of mass m raised from the surface of the earth to a height equal to the radius R of the earth is
Ui = -GMm/R
Uf = -GMm/2R
ΔU = GMm/2R = gmR/2
Two satellites S1 and S2 revolve round a planet in the same direction in circular orbits. Their periods of revolutions are 1 hour and 8 hour respectively. The radius of S1 is 104 km. The radius of S2 will be
T2 ∝ r3
(r1/r2)1/2 = 1/2
r2 = 4 × 104 km
The ratio of modulus of rigidity to bulk modulus for a Poisson's ratio of 0.15 would be
Y = 2η(1 + ν)
Y = 3B(1 - 2ν)
(1 + 0.15)2η = 3B(1 - 2 × 0.15)
1.15 × 2η = 0.7 × 3B
Two soap bubbles of radii equal to 6 cm and 8 cm are touching each other over a common surface. Radius of the common surface will be
1/r = 1/r1 - 1/r2
1/r = 1/6 - 1/8
r = (8 × 6)/2 = 24 cm
One mole of an ideal gas at an initial temperature of T K does 15R joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of gas will be
ΔU = nCvΔT
Q = W + ΔU
ΔU = -15R
-15R = (R/(γ - 1))ΔT
-15R = (3/2)RΔT
ΔT = -10
TF = T - 10
One mole of an ideal monatomic gas is taken from A to C along the path ABC. The temperature of the gas at A is T0. For the process ABC
W = WAB + WAC
= P0(2V0 - V0) + 0
= P0V0
P0V0 = RT0
W = RT0
The temperature of sink of Carnot engine is 27°C and efficiency of engine is 60%. Then temperature of source is
60/100 = 1 - 300/T
300/T = 40/100
T = 750 K
T = 477°C
Three large plates A, B and C are placed parallel to each other and charges are given as shown. The charge that appears on the left surface of plate B is
Change on outer surface of A and C = (-3C + 4C + 5C)/2 = 3C
x + 3 = -3C
x = -6C
y = -x = 6C
The lengths of the three wires of copper are in the ratio of 1 : 4 : 8 and their masses are in the ratio of 5 : 3 : 1. The ratio of their electrical resistance is
R = ρℓ/A
Let density be d, so m/(Aℓ) = d
A = m/(ℓd)
Therefore R ∝ ℓ2/m
Ratio = 1/5 : 16/3 : 64/1 = 3 : 80 : 960
In the circuit shown, the current through 8 Ω is same before and after connecting E. The value of E is
(12/24) × 8 = E
E = 4 V
In the given circuit diagram when the current reaches steady state in the circuit, the charge on the capacitor of capacitance C will be
No current flows via capacitor.
Vc = Vr2
Vc = Er2/(r + r2)
q/C = Vc
q = CEr2/(r + r2)
In the series combination of 18 cells each cell having emf 6 V and internal resistance 2 ohm, if three cells are wrongly connected (i.e. their polarity is opposite to remaining 15 cells), then total emf and internal resistance of this combination will be
e = (15 - 3) × 6 = 72 V
r = 18 × 2 = 36 Ω
A thin wire bent to form a circle and carrying a current I has a magnetic moment M. The shape of the wire is changed to a square and it carries the same current. It will have a magnetic moment
M = IπR2
2πR = 4a
a = πR/2
M' = I(πR/2)2
= (π/4)πR2I = πM/4
If a magnetic dipole of moment M, initially situated in the direction of a magnetic field B is rotated by 180°, then the amount of work done is
Ui = -MB cos0° = -MB
Uf = -MB cos180° = MB
W = Uf - Ui = 2MB
Self inductance of primary and secondary of a perfectly coupled coils are 4 mH and 9 mH respectively. The coefficient of mutual inductance between them is
M = √(L1L2)
= √(4 × 9) = 6 mH
An ac source of angular frequency ω is fed across a resistor r and a capacitor C in series. The current in the circuit measured is I. If now the frequency of source is changed to ω/3 (but maintaining the same voltage), the current in the circuit is found to reduce by a factor of three. The power factor of the circuit at the original frequency ω is
I = V/√(R2 + XC2)
I/3 = V/√(R2 + 9XC2)
√(R2 + 9XC2) = 3√(R2 + XC2)
R2 + 9XC2 = 9R2 + 9XC2
R = 0
Power factor = 0
The r.m.s. value of potential difference V shown in the figure between 0 and T/2 is
Vrms = √{∫0T/2V2dT / ∫0T/2dT}
Vrms = V0
The inductance between A and D is
All inductors are parallel.
Match List-I (Electromagnetic wave type) with List-II (Its Application) and select the correct option from the choices given below the lists:
Factual.
In the Rutherford experiment, α-particles are scattered from a nucleus as shown. Out of the four paths, which path is not possible?
α-particle cannot be attracted to nucleus.
A parallel narrow beam of light is incident on the surface of a transparent hemisphere of radius R and refractive index μ = 1.5. The position of the image formed by refraction at the spherical surface only is
μ2/v - μ1/u = (μ2 - μ1)/R
u = -∞
v = 3R
The ratio of thickness of plates of two transparent medium A and B is 16 : 5. If time taken by light through A is twice than that through B, then refractive index of A with respect to B will be
16μA = 10μB
μA/μB = 10/16 = 0.625
A small coin is resting on the bottom of a beaker filled with liquid. A ray of light from the coin travels upto the surface of the liquid and moves along its surface. What is the refractive index of the liquid?
sin iC = 1/μ
μ = 5/3
In the figure shown if a parallel beam of white light is incident on the plane of the slits then the distance of the nearest white spot on the screen from O is d/A. Find the value of A. (Assume d << D).
White spot will be formed on perpendicular bisector of line joining the slits.
y = d/2 - 2d/3
= d/3
If the magnetic dipole moment of an atom of diamagnetic material, paramagnetic material and ferromagnetic material denoted by d, p, f respectively then
Factual.
