Progressive waves, phase, velocity, acceleration, superposition, beats and standing waves.
Waves Formula Sheet and PYQs
Complete Class 11 Physics Waves Formula Sheet, NCERT Examples, NCERT Exercises, PYQs, Numericals and Quick Revision Notes.
Formula Families Covered
Speed of sound, Laplace correction, intensity, loudness, decibel level and echo.
Open pipe, closed pipe, harmonics, end correction, displacement and pressure nodes.
NCERT-style solved examples, exercises, 70+ PYQ-style questions and revision notes.
All Important Waves Formulae
v = fλSymbols: v: wave speed, f: frequency, λ: wavelength
Units: m s-1, Hz, m
Exam Tip: Use for periodic waves in a uniform medium.
Common Mistake: Do not use particle speed in place of wave speed.
f = 1/TSymbols: f: frequency, T: time period
Units: Hz, s
Exam Tip: One oscillation per second means 1 Hz.
Common Mistake: Do not confuse T with total time for many oscillations.
ω = 2πf = 2π/TSymbols: ω: angular frequency
Units: rad s-1
Exam Tip: Coefficient of t in y = A sin(ωt - kx).
Common Mistake: Do not write ω = 2πT.
k = 2π/λSymbols: k: angular wave number
Units: rad m-1
Exam Tip: Coefficient of x in wave equation.
Common Mistake: Do not confuse k with spring constant.
+x direction: y = A sin(ωt - kx)Symbols: A: amplitude, ω: angular frequency, k: wave number
Units: m, rad s-1, rad m-1
Exam Tip: Minus before kx means propagation in +x direction.
Common Mistake: Do not decide direction from the sign of t alone.
y = A sin[(2π/λ)(vt - x)]Symbols: v: wave velocity, x: position, t: time
Units: m, m s-1, s
Exam Tip: Form vt - x represents +x direction.
Common Mistake: x - vt also represents +x direction with opposite phase convention.
vp = dy/dt = Aω cos(ωt - kx)Symbols: vp: transverse particle velocity
Units: m s-1
Exam Tip: Differentiate displacement with respect to time.
Common Mistake: Do not call this wave velocity.
vp,max = AωSymbols: A: amplitude, ω: angular frequency
Units: m s-1
Exam Tip: Maximum value of cosine is 1.
Common Mistake: Use A in metre, not cm, unless answer is in cm/s.
a = d2y/dt2 = -ω2ySymbols: a: transverse acceleration of particle
Units: m s-2
Exam Tip: SHM relation applies to each medium particle.
Common Mistake: Negative sign means acceleration is towards mean position.
dy/dx = -Ak cos(ωt - kx)Symbols: dy/dx: slope of string/wave profile
Units: dimensionless
Exam Tip: Differentiate with respect to x at fixed time.
Common Mistake: Do not mix slope with velocity.
φ = ωt - kx + φ0Symbols: φ: phase, φ0: initial phase
Units: radian
Exam Tip: Same phase points differ by 2πn.
Common Mistake: Phase is not displacement.
Δφ = 2πΔx/λ = 2πΔt/TSymbols: Δx: path difference, Δt: time difference
Units: radian
Exam Tip: Use distance form or time form as per data.
Common Mistake: Do not mix path difference and time difference units.
Δx = (λ/2π)ΔφSymbols: Δx: path difference
Units: m
Exam Tip: Useful in interference and phase questions.
Common Mistake: Use radians for phase difference.
Δx = nλ, Δφ = 2nπSymbols: n: integer
Units: m, rad
Exam Tip: Waves arrive in phase.
Common Mistake: Do not use half wavelength for maxima.
Δx = (2n+1)λ/2Symbols: n: integer
Units: m
Exam Tip: Waves arrive in opposite phase.
Common Mistake: This is for equal-amplitude complete cancellation.
R = √(A12 + A22 + 2A1A2cosφ)Symbols: A1, A2: amplitudes, φ: phase difference
Units: m
Exam Tip: Use when two SHM/waves of same frequency superpose.
Common Mistake: Do not add amplitudes directly unless phase is zero.
R = 2A cos(φ/2)Symbols: A: each amplitude, φ: phase difference
Units: m
Exam Tip: Fast way for two equal-amplitude waves.
Common Mistake: Use magnitude if cosine is negative.
y = 2A sin kx cos ωtSymbols: nodes from sin kx = 0
Units: m
Exam Tip: Standing waves do not transport energy along the medium.
Common Mistake: Do not call antinode spacing one wavelength.
distance between adjacent nodes = λ/2Symbols: λ: wavelength
Units: m
Exam Tip: Same for adjacent antinodes.
Common Mistake: Node to nearest antinode is λ/4.
f1 = v/2LSymbols: L: string length fixed at both ends
Units: Hz
Exam Tip: Same pattern as open pipe displacement condition.
Common Mistake: Use L as vibrating length.
fn = nv/2LSymbols: n = 1, 2, 3, ...
Units: Hz
Exam Tip: All harmonics are allowed.
Common Mistake: Closed pipe has only odd harmonics.
v = √(T/μ)Symbols: T: tension, μ: mass per unit length
Units: m s-1
Exam Tip: Higher tension increases speed.
Common Mistake: Do not use total mass unless divided by length.
Pavg = (1/2)μω2A2vSymbols: μ: linear density, A: amplitude
Units: W
Exam Tip: Shows power proportional to A2.
Common Mistake: Amplitude doubling makes power four times.
fb = |f1 - f2|Symbols: f1, f2: close frequencies
Units: Hz
Exam Tip: Number of loud beats per second.
Common Mistake: Unknown frequency may be above or below standard.
Sound Waves, Intensity, Loudness and Laplace Correction
v = √(γP/ρ)Symbols: γ: ratio of specific heats, P: pressure, ρ: density
Units: m s-1
Exam Tip: Laplace correction uses adiabatic bulk modulus.
Common Mistake: Do not use isothermal formula for sound in air.
v = √(E/ρ)Symbols: E: elastic modulus, ρ: density
Units: m s-1
Exam Tip: General elastic wave speed form.
Common Mistake: Choose correct modulus for medium.
v = √(P/ρ)Symbols: P: pressure, ρ: density
Units: m s-1
Exam Tip: Historical formula before Laplace correction.
Common Mistake: It underestimates speed in air.
vLaplace = √(γ) vNewtonSymbols: γ: Cp/Cv
Units: m s-1
Exam Tip: Sound compression/rarefaction is nearly adiabatic.
Common Mistake: Do not take γ = 1 for air.
v = v0 + 0.61TSymbols: T: temperature in degree Celsius
Units: m s-1
Exam Tip: Approximate speed in air near room temperature.
Common Mistake: Do not put Kelvin in this linear Celsius formula.
v ∝ √TKSymbols: TK: absolute temperature
Units: m s-1
Exam Tip: Use for ratio problems.
Common Mistake: Temperature must be in Kelvin.
I = P/ASymbols: P: power, A: area
Units: W m-2
Exam Tip: Intensity is power per unit area.
Common Mistake: Do not confuse intensity with loudness.
I = P/(4πr2)Symbols: r: distance from point source
Units: W m-2
Exam Tip: Intensity follows inverse square law.
Common Mistake: Doubling distance makes intensity one-fourth.
β = 10 log10(I/I0)Symbols: I0 = 10-12 W m-2
Units: dB
Exam Tip: Use base-10 logarithm.
Common Mistake: 10 dB increase means intensity becomes 10 times.
β2 - β1 = 10 log10(I2/I1)Symbols: I1, I2: intensities
Units: dB
Exam Tip: Good for comparing two sound levels.
Common Mistake: Do not subtract intensities directly.
Loudness depends on intensity and ear responseSymbols: I: objective intensity; loudness: subjective sensation
Units: phon/sone in acoustics
Exam Tip: For school exams, intensity is physical quantity.
Common Mistake: Loudness is not measured in W m-2.
I ∝ p02Symbols: p0: pressure amplitude
Units: W m-2
Exam Tip: If pressure amplitude doubles, intensity becomes four times.
Common Mistake: Do not use direct proportionality with p0.
M = u/vSymbols: u: source speed, v: sound speed
Units: dimensionless
Exam Tip: M > 1 means supersonic.
Common Mistake: Classical Doppler formula fails at vs approaching v.
d = vt/2Symbols: t: echo time, v: sound speed
Units: m
Exam Tip: Sound travels to obstacle and back.
Common Mistake: Do not forget factor 2.
Open Pipe, Closed Pipe, Nodes and Antinodes
f1 = v/2LSymbols: L: pipe length, v: sound speed
Units: Hz
Exam Tip: Both ends are displacement antinodes.
Common Mistake: End correction may be needed in precision problems.
fn = nv/2LSymbols: n = 1, 2, 3, ...
Units: Hz
Exam Tip: All harmonics are present.
Common Mistake: Do not omit even harmonics in open pipe.
λn = 2L/nSymbols: n: harmonic number
Units: m
Exam Tip: For n loops in open pipe.
Common Mistake: Use effective length if end correction is given.
f1 = v/4LSymbols: Closed end: displacement node; open end: displacement antinode
Units: Hz
Exam Tip: Lowest mode has quarter wavelength in pipe.
Common Mistake: Closed pipe fundamental is half of open pipe same length.
fn = nv/4L, n = 1, 3, 5, ...Symbols: n: odd harmonic number
Units: Hz
Exam Tip: Only odd harmonics are allowed.
Common Mistake: Do not include n = 2, 4, 6 for closed pipe.
λn = 4L/n, n oddSymbols: L: pipe length
Units: m
Exam Tip: Use odd n only.
Common Mistake: Third harmonic is 3v/4L, not 2v/4L.
Open end: pressure nodeSymbols: Pressure variation is minimum at open end
Units: --
Exam Tip: Pressure node corresponds to displacement antinode.
Common Mistake: Do not confuse pressure and displacement patterns.
Closed end: pressure antinodeSymbols: Pressure variation is maximum at closed end
Units: --
Exam Tip: Closed end has displacement node.
Common Mistake: Pressure and displacement nodes are interchanged.
Leff = L + e for one open end; L + 2e for two open endsSymbols: e: end correction
Units: m
Exam Tip: Use effective length in organ pipe formulas.
Common Mistake: Do not add end correction at closed end.
L + e = λ/4 for first resonanceSymbols: L: air column length
Units: m
Exam Tip: Second resonance in closed pipe differs by λ/2.
Common Mistake: Difference of successive resonances gives λ/2.
Observer Motion, Source Motion, Beats and Sign Convention
f' = f(v ± v0)/(v ∓ vs)Symbols: v: sound speed, v0: observer speed, vs: source speed
Units: Hz
Exam Tip: Choose signs so approach increases f' and separation decreases f'.
Common Mistake: Do not memorize signs without drawing arrows.
f' = f(v + v0)/vSymbols: stationary source, moving observer
Units: Hz
Exam Tip: Observer meets more wavefronts per second.
Common Mistake: Observer speed belongs in numerator.
f' = f(v - v0)/vSymbols: stationary source, observer receding
Units: Hz
Exam Tip: Receiving rate decreases.
Common Mistake: Do not put v0 in denominator.
f' = fv/(v - vs)Symbols: moving source, stationary observer
Units: Hz
Exam Tip: Wavelength in front becomes smaller.
Common Mistake: Approaching source uses minus in denominator.
f' = fv/(v + vs)Symbols: source receding from stationary observer
Units: Hz
Exam Tip: Wavelength reaching observer is longer.
Common Mistake: Receding source uses plus in denominator.
f' = f(v + v0)/(v - vs)Symbols: source and observer move towards each other
Units: Hz
Exam Tip: Frequency increases strongly.
Common Mistake: Do not use relative velocity alone in denominator.
f' = f(v - v0)/(v + vs)Symbols: source and observer separate
Units: Hz
Exam Tip: Frequency decreases strongly.
Common Mistake: Check whether separation really increases.
fb = |f1 - f2|Symbols: nearby frequencies
Units: Hz
Exam Tip: Used in tuning instruments.
Common Mistake: Beat frequency is not average frequency.
Δf ≈ 2uf/vSymbols: u: reflector speed, f: emitted frequency
Units: Hz
Exam Tip: Radar/ultrasound reflection gives double shift.
Common Mistake: Use wave speed of the relevant wave.
Approach: f' increases; separation: f' decreasesSymbols: Draw S and O arrows first
Units: --
Exam Tip: This rule prevents most sign errors.
Common Mistake: Do not rely only on plus/minus symbols.
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Important NCERT Class 11 Solved Examples
A wave has frequency 50 Hz and wavelength 0.8 m. Find wave speed.
Show Solution
Given/Idea: f=50 Hz, λ=0.8 m
Solution: v=fλ=50×0.8=40 m s-1
Final Answer: 40 m s-1
For y=0.02 sin(100πt - 4πx), find amplitude, angular frequency and wave number.
Show Solution
Given/Idea: A=0.02 m, coefficient of t=100π, coefficient of x=4π
Solution: ω=100π rad s-1, k=4π rad m-1
Final Answer: A=0.02 m, ω=100π, k=4π
For y=5 sin(20t - 4x), find wave velocity.
Show Solution
Given/Idea: ω=20, k=4
Solution: v=ω/k=20/4=5 m s-1
Final Answer: 5 m s-1
A wave has A=0.01 m and ω=200 rad s-1. Find maximum particle speed.
Show Solution
Given/Idea: A=0.01 m, ω=200
Solution: vp,max=Aω=0.01×200=2 m s-1
Final Answer: 2 m s-1
Two points are separated by λ/6. Find phase difference.
Show Solution
Given/Idea: Δx=λ/6
Solution: Δφ=2πΔx/λ=2π/6=π/3
Final Answer: π/3 rad
A string has tension 100 N and linear density 0.01 kg m-1. Find wave speed.
Show Solution
Given/Idea: T=100 N, μ=0.01 kg m-1
Solution: v=√(T/μ)=√(100/0.01)=100 m s-1
Final Answer: 100 m s-1
A string of length 1 m has speed 200 m/s. Find fundamental frequency.
Show Solution
Given/Idea: L=1 m, v=200 m/s
Solution: f1=v/2L=200/2=100 Hz
Final Answer: 100 Hz
Find speed of sound at 20 degree Celsius using v=331+0.61T.
Show Solution
Given/Idea: T=20
Solution: v=331+0.61×20=343.2 m/s
Final Answer: 343.2 m/s
If I=10-8 W m-2, find sound level.
Show Solution
Given/Idea: I=10-8, I0=10-12
Solution: β=10log(I/I0)=10log(104)=40 dB
Final Answer: 40 dB
An open pipe of length 0.5 m has sound speed 340 m/s. Find fundamental frequency.
Show Solution
Given/Idea: L=0.5 m, v=340 m/s
Solution: f1=v/2L=340/1=340 Hz
Final Answer: 340 Hz
A closed pipe of length 0.25 m has v=340 m/s. Find first resonant frequency.
Show Solution
Given/Idea: L=0.25 m
Solution: f1=v/4L=340/1=340 Hz
Final Answer: 340 Hz
Find third harmonic of a closed pipe of length 0.5 m if v=340 m/s.
Show Solution
Given/Idea: n=3, L=0.5 m
Solution: f3=3v/4L=3×340/2=510 Hz
Final Answer: 510 Hz
Two tuning forks 256 Hz and 260 Hz are sounded together. Find beats per second.
Show Solution
Given/Idea: f1=256, f2=260
Solution: fb=|256-260|=4 Hz
Final Answer: 4 beats/s
A 512 Hz fork gives 5 beats/s with another fork. Find possible frequencies.
Show Solution
Given/Idea: standard=512 Hz, beat=5 Hz
Solution: unknown=512±5
Final Answer: 507 Hz or 517 Hz
A 500 Hz source moves towards stationary observer at 34 m/s. v=340 m/s. Find apparent frequency.
Show Solution
Given/Idea: f=500, v=340, vs=34
Solution: f'=fv/(v-vs)=500×340/306=555.6 Hz
Final Answer: 555.6 Hz
Observer moves towards 600 Hz stationary source at 20 m/s. v=340 m/s. Find f'.
Show Solution
Given/Idea: f=600, v0=20
Solution: f'=f(v+v0)/v=600×360/340=635.3 Hz
Final Answer: 635.3 Hz
An echo is heard after 2 s. Speed of sound is 340 m/s. Find distance of wall.
Show Solution
Given/Idea: t=2 s, v=340 m/s
Solution: d=vt/2=340×2/2=340 m
Final Answer: 340 m
Two successive resonances in a closed pipe differ by 17 cm. Find wavelength.
Show Solution
Given/Idea: L2-L1=17 cm
Solution: Difference=λ/2, so λ=34 cm
Final Answer: 0.34 m
Exercise-style Questions With Solutions
Identify direction of y=A sin(ωt-kx).
Show Solution
Given/Idea: Phase constant gives ωt-kx=constant. As t increases, x increases.
Solution: Wave travels in +x direction.
Final Answer: undefined
Identify direction of y=A sin(ωt+kx).
Show Solution
Given/Idea: ωt+kx=constant. As t increases, x decreases.
Solution: Wave travels in -x direction.
Final Answer: undefined
In y=0.01 sin(50t-2x), find wavelength.
Show Solution
Given/Idea: k=2 rad/m, λ=2π/k=2π/2=π m.
Solution: π m
Final Answer: undefined
In y=0.01 sin(100πt-5x), find frequency.
Show Solution
Given/Idea: ω=100π, f=ω/2π=50 Hz.
Solution: 50 Hz
Final Answer: undefined
If y=0.02 m and ω=10 rad/s at an instant, find acceleration.
Show Solution
Given/Idea: a=-ω2y=-100×0.02=-2 m/s2.
Solution: -2 m/s2
Final Answer: undefined
Sound level increases by 20 dB. Find intensity ratio.
Show Solution
Given/Idea: 20=10log(I2/I1), ratio=102.
Solution: 100
Final Answer: undefined
Speed of sound ratio at 300 K and 1200 K.
Show Solution
Given/Idea: v ∝ √T, ratio=√(1200/300)=2.
Solution: 2
Final Answer: undefined
Open pipe has f1=170 Hz. Find f2.
Show Solution
Given/Idea: Open pipe has all harmonics, f2=2f1.
Solution: 340 Hz
Final Answer: undefined
Closed pipe fundamental is 100 Hz. Find next allowed frequency.
Show Solution
Given/Idea: Closed pipe allowed harmonics are 1,3,5... next is 3f1.
Solution: 300 Hz
Final Answer: undefined
A fork produces 6 beats with standard. Filing increases fork frequency and beats decrease. Was original fork above or below standard?
Show Solution
Given/Idea: Filing increases frequency. If beats decrease, fork was below standard.
Solution: Below standard.
Final Answer: undefined
CBSE, NEET, JEE, IB, IGCSE and A-Level Questions
Define wavelength and frequency of a progressive wave.
Show Answer
Wavelength is distance between consecutive same-phase particles; frequency is number of oscillations per second.
Write relation between wave velocity, frequency and wavelength.
Show Answer
v=fλ.
What is the SI unit of wave number?
Show Answer
rad m-1 or m-1 when radian is treated dimensionless.
For y=A sin(ωt-kx), what is wave speed?
Show Answer
v=ω/k.
Differentiate between particle velocity and wave velocity.
Show Answer
Particle velocity is dy/dt of medium particle; wave velocity is speed of disturbance, v=fλ.
What is beat frequency?
Show Answer
fb=|f1-f2|.
Why is sound speed in gas given by Laplace correction?
Show Answer
Sound propagation is adiabatic, not isothermal.
What is the distance between adjacent nodes in a standing wave?
Show Answer
λ/2.
Why are only odd harmonics present in closed pipe?
Show Answer
Boundary conditions require displacement node at closed end and antinode at open end.
What happens to apparent frequency when source approaches observer?
Show Answer
It increases.
A wave has f=100 Hz and λ=2 m. Find speed.
Show Answer
v=fλ=200 m/s.
A wave equation has ω=40 rad/s and k=5 rad/m. Find speed.
Show Answer
v=ω/k=8 m/s.
If amplitude doubles, maximum particle velocity becomes?
Show Answer
It doubles because vp,max=Aω.
If intensity of sound becomes 100 times, sound level increases by?
Show Answer
20 dB.
At 27 degree Celsius approximate speed of sound in air is?
Show Answer
v=331+0.61×27=347.5 m/s approximately.
Open pipe length is L. Fundamental frequency is?
Show Answer
v/2L.
Closed pipe length is L. Fundamental frequency is?
Show Answer
v/4L.
Two forks 300 Hz and 305 Hz are sounded. Beat frequency?
Show Answer
5 Hz.
Distance between node and nearest antinode is?
Show Answer
λ/4.
Doppler Effect is due to change in what?
Show Answer
Apparent frequency due to relative motion.
For y=2 sin(10t-5x), find wave speed.
Show Answer
v=ω/k=10/5=2 units/s.
For y=A sin(100πt-2πx), find frequency and wavelength.
Show Answer
f=50 Hz, λ=1 m.
Find maximum transverse velocity for A=2 cm, f=5 Hz.
Show Answer
ω=10π, vmax=0.02×10π=0.2π m/s.
Two waves of equal amplitude A and phase difference 120 degree superpose. Resultant amplitude?
Show Answer
R=2A cos60 degree=A.
If two equal waves interfere destructively, phase difference is?
Show Answer
(2n+1)π.
String speed depends on tension how?
Show Answer
v ∝ √T.
If string tension is made four times, frequency becomes?
Show Answer
Twice, for same length and mode.
Open pipe third harmonic if fundamental is 200 Hz?
Show Answer
600 Hz.
Closed pipe first overtone if fundamental is 120 Hz?
Show Answer
Third harmonic = 360 Hz.
Source approaching stationary observer: formula?
Show Answer
f'=fv/(v-vs).
A source and observer move towards each other. How should signs be chosen?
Show Answer
Use larger numerator and smaller denominator: f'=f(v+v0)/(v-vs).
For a standing wave y=2A sin kx cos ωt, where are nodes?
Show Answer
sin kx=0, so x=nπ/k=nλ/2.
Power carried by a sinusoidal wave on string depends on amplitude how?
Show Answer
P ∝ A2.
If pressure amplitude doubles in sound wave, intensity becomes?
Show Answer
Four times.
Two close frequencies have average 500 Hz and beat frequency 6 Hz. Find frequencies.
Show Answer
497 Hz and 503 Hz.
A reflected Doppler shift is approximately why doubled?
Show Answer
Wave is shifted on incidence and reflection from moving target.
If radial relative velocity is zero, classical first-order Doppler shift?
Show Answer
Zero.
Why source velocity appears in denominator in Doppler formula?
Show Answer
Moving source changes wavelength.
Why observer velocity appears in numerator?
Show Answer
Moving observer changes rate of receiving wavefronts.
Closed pipe cannot have which harmonics?
Show Answer
Even harmonics.
State the relation between period and frequency.
Show Answer
f=1/T.
What is phase difference between two points separated by half wavelength?
Show Answer
π rad.
What is a node?
Show Answer
A point of zero displacement in a standing wave.
What is an antinode?
Show Answer
A point of maximum displacement in a standing wave.
How does sound intensity vary with distance from point source?
Show Answer
I ∝ 1/r2.
Explain beats in one sentence.
Show Answer
Periodic loudness variation due to superposition of two close frequencies.
What does a 10 dB increase mean for intensity?
Show Answer
Intensity becomes 10 times.
Sound is longitudinal or transverse in air?
Show Answer
Longitudinal.
Compression and rarefaction are related to what wave?
Show Answer
Longitudinal sound wave.
Can sound travel in vacuum?
Show Answer
No.
What changes when pitch increases?
Show Answer
Frequency increases.
What changes when loudness increases physically?
Show Answer
Intensity/amplitude increases.
Echo formula for distance?
Show Answer
d=vt/2.
Write speed of transverse wave on a stretched string.
Show Answer
v=√(T/μ).
State formula for sound intensity level.
Show Answer
β=10log10(I/I0).
Why is temperature in Kelvin required in v ∝ √T?
Show Answer
Because proportionality uses absolute thermodynamic temperature.
State the general two-source resultant amplitude formula.
Show Answer
R=√(A12+A22+2A1A2cosφ).
What is end correction?
Show Answer
Small extra effective length added at open end of pipe.
A closed pipe has first resonance at L. Next resonance occurs at?
Show Answer
L+λ/2, so difference is λ/2.
Assertion: Wave speed equals particle speed. Reason: Particles move with the wave.
Show Answer
Both assertion and reason are false for progressive waves in a medium.
Assertion: In an open pipe both ends are displacement antinodes. Reason: Air is free to vibrate at open ends.
Show Answer
Both true and reason explains assertion.
Assertion: Closed pipe has odd harmonics only. Reason: One end is node and the other is antinode.
Show Answer
Both true and reason explains assertion.
Assertion: Beat frequency is zero when two frequencies are equal. Reason: fb=|f1-f2|.
Show Answer
Both true and reason explains assertion.
Assertion: Laplace correction gives greater sound speed than Newton's formula. Reason: Sound propagation is adiabatic.
Show Answer
Both true and reason explains assertion.
Wave number k=2πλ.
Show Answer
False. k=2π/λ.
Angular frequency ω=2πf.
Show Answer
True.
Adjacent nodes are separated by λ.
Show Answer
False. They are separated by λ/2.
In a closed pipe, second harmonic is absent.
Show Answer
True.
Doppler Effect changes the emitted frequency of source.
Show Answer
False. It changes observed frequency.
Why is y=A sin(ωt-kx) a wave travelling in +x direction?
Show Answer
For constant phase, x increases as t increases.
Why does intensity decrease with distance from a point source?
Show Answer
Same power spreads over larger spherical area.
Why are beats useful in tuning?
Show Answer
Beat frequency becomes smaller as frequencies become closer.
Why is pressure node at open end of organ pipe?
Show Answer
Pressure must nearly equal atmospheric pressure at open end.
Why is sound speed higher at higher temperature?
Show Answer
Molecules move faster and pressure-density response is faster.
A 1 m open pipe has v=340 m/s. Find first three frequencies.
Show Answer
170 Hz, 340 Hz, 510 Hz.
A 1 m closed pipe has v=340 m/s. Find first three allowed frequencies.
Show Answer
85 Hz, 255 Hz, 425 Hz.
If sound level changes from 40 dB to 70 dB, intensity ratio?
Show Answer
103.
Two forks produce 8 beats/s. One is 256 Hz. Possible other frequencies?
Show Answer
248 Hz or 264 Hz.
Wave has T=0.02 s and λ=4 m. Find speed.
Show Answer
f=50 Hz, v=200 m/s.
A guitar string is tuned using a 440 Hz tuning fork. Beats reduce from 5/s to 1/s as tension is adjusted. What does this show?
Show Answer
The string frequency is approaching 440 Hz.
A student sees y=0.03 sin(60t+5x). Which way does the wave travel?
Show Answer
Negative x direction.
A resonance tube has consecutive resonances at 18 cm and 52 cm. Find wavelength.
Show Answer
Difference=34 cm=λ/2, so λ=68 cm.
An ambulance approaches and then recedes. How does pitch change?
Show Answer
Higher during approach, lower during recession.
A sound source power is constant. Listener moves from 2 m to 4 m. Intensity becomes?
Show Answer
One-fourth.
Quick Revision Sheet
One-page Revision Sheet
- v=fλ links speed, frequency and wavelength.
- ω=2πf and k=2π/λ are read from wave equation.
- For y=A sin(ωt-kx), wave travels in +x direction.
- Particle velocity is dy/dt; wave velocity is ω/k.
- Acceleration of particle is a=-ω2y.
- Standing wave nodes are λ/2 apart.
- Open pipe has all harmonics; closed pipe has odd harmonics only.
Most Important Formulas
- v=fλ
- v=√(T/μ) for string waves.
- v=√(γP/ρ) for sound in gas.
- I=P/A and β=10log(I/I0).
- Open pipe: fn=nv/2L.
- Closed pipe: fn=nv/4L, n odd.
- Doppler: f'=f(v±v0)/(v∓vs).
Most Important Concepts
- Waves transfer energy without net transport of medium.
- Phase decides position in oscillation.
- Superposition means algebraic addition of displacements.
- Beats need close frequencies.
- Sound is longitudinal in air.
- Pressure and displacement nodes are interchanged in organ pipes.
- Doppler shift depends on radial relative motion.
Exam Tips
- Read coefficients of t and x carefully in wave equation.
- Convert cm to m before using Aω or wave speed formulas.
- Use Kelvin in temperature ratio formula.
- In closed pipe, first overtone is third harmonic.
- In beats, unknown frequency can be above or below standard.
- Draw arrows before Doppler formula.
- For sound level, intensity ratio is logarithmic.
Most Common Mistakes
- Writing k=2πλ instead of 2π/λ.
- Confusing particle velocity with wave velocity.
- Using even harmonics for closed pipe.
- Forgetting end correction in resonance tube questions when given.
- Using Celsius in v∝√T ratio problems.
- Taking beat frequency as sum of frequencies.
- Putting source speed in numerator in Doppler formula.
Last Day Revision Notes
- Memorize formula families, not isolated formulas.
- Direction: ωt-kx means +x, ωt+kx means -x.
- Node-antinode distance is λ/4.
- Sound intensity varies as amplitude squared.
- A 10 dB rise means intensity becomes 10 times.
- Open-open pipe behaves like string fixed at both ends for frequency pattern.
- Approach increases Doppler frequency; separation decreases it.
Most Important Formulas in One View
- Wave Speed: v = fλ
- Frequency and Period: f = 1/T
- Angular Frequency: ω = 2πf = 2π/T
- Wave Number: k = 2π/λ
- Wave Equation: +x direction: y = A sin(ωt - kx)
- Wave Equation Alternate: y = A sin[(2π/λ)(vt - x)]
- Particle Velocity: vp = dy/dt = Aω cos(ωt - kx)
- Maximum Particle Velocity: vp,max = Aω
- Particle Acceleration: a = d2y/dt2 = -ω2y
- Wave Slope: dy/dx = -Ak cos(ωt - kx)
- Phase: φ = ωt - kx + φ0
- Phase Difference: Δφ = 2πΔx/λ = 2πΔt/T
- Path Difference: Δx = (λ/2π)Δφ
- Constructive Interference: Δx = nλ, Δφ = 2nπ
- Destructive Interference: Δx = (2n+1)λ/2
- Resultant Amplitude: R = √(A12 + A22 + 2A1A2cosφ)
- Equal Amplitude Resultant: R = 2A cos(φ/2)
- Standing Wave: y = 2A sin kx cos ωt
- Node Spacing: distance between adjacent nodes = λ/2
- String Fundamental: f1 = v/2L
- String Harmonics: fn = nv/2L
- Wave Speed on String: v = √(T/μ)
- Power on String: Pavg = (1/2)μω2A2v
- Beat Frequency: fb = |f1 - f2|
- Speed of Sound in Gas: v = √(γP/ρ)
- Elastic Wave Speed: v = √(E/ρ)
- Newton Formula: v = √(P/ρ)
- Laplace Correction: vLaplace = √(γ) vNewton
- Temperature Formula: v = v0 + 0.61T
- Kelvin Dependence: v ∝ √TK
- Intensity: I = P/A
- Spherical Wave Intensity: I = P/(4πr2)
- Sound Level: β = 10 log10(I/I0)
- Intensity Ratio: β2 - β1 = 10 log10(I2/I1)
- Loudness Idea: Loudness depends on intensity and ear response
- Pressure Amplitude Relation: I ∝ p02
- Mach Number: M = u/v
- Echo Distance: d = vt/2
- Open Pipe Fundamental: f1 = v/2L
- Open Pipe Harmonics: fn = nv/2L
- Open Pipe Wavelength: λn = 2L/n
- Closed Pipe Fundamental: f1 = v/4L
- Closed Pipe Odd Harmonics: fn = nv/4L, n = 1, 3, 5, ...
- Closed Pipe Wavelength: λn = 4L/n, n odd
- Pressure Nodes: Open end: pressure node
- Pressure Antinode: Closed end: pressure antinode
- End Correction: Leff = L + e for one open end; L + 2e for two open ends
- Resonance Tube: L + e = λ/4 for first resonance
- General Doppler: f' = f(v ± v0)/(v ∓ vs)
- Observer Towards Source: f' = f(v + v0)/v
- Observer Away From Source: f' = f(v - v0)/v
- Source Towards Observer: f' = fv/(v - vs)
- Source Away From Observer: f' = fv/(v + vs)
- Both Approach: f' = f(v + v0)/(v - vs)
- Both Recede: f' = f(v - v0)/(v + vs)
- Beat Frequency: fb = |f1 - f2|
- Reflected Doppler Approximation: Δf ≈ 2uf/v
- Sign Rule: Approach: f' increases; separation: f' decreases
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