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Sound Waves and Their Properties

Class 11 Physics notes covering sound waves, longitudinal nature, pressure variation, speed of sound, Laplace correction, intensity, loudness, quality, pitch, numericals and PYQs.

CBSENEETJEE MainJEE AdvancedIBICSEIGCSEA-Level

Sound Is Longitudinal

Sound in air travels through compressions and rarefactions. Particles vibrate parallel to propagation while pressure disturbance moves forward.

Laplace Correction

Newton used isothermal compression and got a low value. Laplace used adiabatic compression and obtained v = √(γP/ρ).

Sound Properties

Intensity is physical, loudness is subjective, pitch depends on frequency, and quality depends on waveform and harmonics.

Concept

Introduction

Sound is one of the most important mechanical waves in Class 11 Physics because it connects wave motion with daily life, music, hearing, echo, ultrasound, communication and measurement of distance.

A sound wave is a longitudinal mechanical wave. It needs a material medium such as air, water, steel or wood. It cannot travel through vacuum because there are no particles to pass compressions and rarefactions.

Real-life example: when a bell rings, the metal surface vibrates and pushes nearby air layers. These air layers create alternate high-pressure and low-pressure regions that move outward as sound.

Exam perspective: NEET and CBSE focus on definitions, speed of sound and temperature dependence. JEE often asks Newton-Laplace correction, pressure-density phase, intensity and conceptual traps.

Exam FocusMemory trick: sound needs stuff; vacuum is silent.
Exam FocusConceptual trap: air particles do not travel from speaker to ear; pressure disturbance travels.
Concept

Sound Waves

Sound waves are produced by vibrating bodies. The vibration creates periodic compression and expansion of the surrounding medium, and this disturbance travels outward carrying energy.

Production of sound requires a source, a medium and a receiver. The source vibrates, the medium transfers energy layer by layer, and the receiver such as an ear or microphone detects pressure variation.

Propagation happens due to elasticity and inertia. Elasticity restores compressed layers, while inertia carries particles beyond equilibrium, creating the next rarefaction and compression.

Mathematically, the speed of sound in a medium depends on elasticity divided by inertia. That is why the general form is v = √(elastic property / density).

Real-life example: sound travels faster in steel than in air because steel is much more elastic for mechanical disturbances, even though it is denser.

Exam FocusSound is mechanical and longitudinal in gases.
Exam FocusEnergy travels; matter oscillates locally.
Exam FocusNo medium means no sound.
Concept

Longitudinal Nature

Sound in air is longitudinal because air particles vibrate parallel to the direction of propagation. If the sound travels to the right, air particles oscillate to and fro along the same line.

Compression is a region where particles are closer than normal, pressure is high and density is high. Rarefaction is a region where particles are farther apart, pressure is low and density is low.

The distance between two consecutive compressions or two consecutive rarefactions is one wavelength. One compression followed by one rarefaction forms half a wavelength.

Real-life example: push and pull a slinky spring along its length. Dense coil regions and loose coil regions move along the spring just like compressions and rarefactions in air.

Common mistake: do not call compressions crests and rarefactions troughs in a particle diagram. Use crest/trough mainly for displacement or pressure graphs.

Exam FocusCompression: high P, high density.
Exam FocusRarefaction: low P, low density.
Exam FocusParticle motion is parallel to propagation.
Concept

Pressure Variation

A sound wave can be described as pressure variation, density variation or particle displacement variation. Pressure and density are maximum at compression and minimum at rarefaction.

Pressure variation is not the same as displacement variation. In a progressive sound wave, pressure variation and particle displacement are out of phase by π/2 in the standard description.

When displacement of particles is maximum, pressure variation is zero; when displacement changes most rapidly with position, pressure variation is maximum.

Real-life example: a microphone mainly responds to pressure variation of air, while a small dust particle in the air shows local displacement due to the sound wave.

Exam trap: pressure maximum occurs at compression, but particle displacement need not be maximum there.

Exam FocusPressure and density variations are in phase.
Exam FocusPressure and displacement variation are shifted by π/2.
Exam FocusMicrophones detect pressure changes.
Concept

Speed of Sound

Newton assumed that compressions and rarefactions in sound propagation are isothermal, meaning temperature remains constant. His formula was v = √(P/ρ), where P is pressure and ρ is density.

Using air pressure and density, Newton's formula gives about 280 m s−1, which is much lower than the experimental value near 331 m s−1 at 0°C.

The historical problem was important: the wave theory was correct, but the thermodynamic assumption was wrong. Sound compressions and rarefactions happen very rapidly, so there is not enough time for heat exchange.

The general idea remains valuable: speed of sound depends on elasticity and density. Greater elasticity increases speed; greater density decreases speed if elasticity is unchanged.

Real-life example: sound reaches faster through railway tracks than through air because the solid track transmits elastic disturbance more effectively.

Exam FocusNewton formula was too small for air.
Exam FocusMistake: isothermal assumption.
Exam FocusGeneral form: v = √(elasticity/density).
Concept

Laplace Correction

Laplace corrected Newton's formula by saying that sound propagation in a gas is adiabatic, not isothermal. Correct formula: v = √(γP/ρ).

γ is the ratio of specific heats: γ = Cp/Cv. For air, γ is approximately 1.4.

Compression and rarefaction are adiabatic because they occur very rapidly. Heat does not get enough time to flow from compressed hot regions to rarefied cool regions.

Laplace correction works because adiabatic bulk modulus of a gas is γP, not P. Replacing P by γP increases the predicted speed from Newton's value to the experimental value.

JEE-level point: the correction is not a small empirical adjustment; it comes from thermodynamics of rapid pressure changes.

Exam FocusLaplace formula: v = √(γP/ρ).
Exam Focusγ = Cp/Cv.
Exam FocusSound in gas is effectively adiabatic.
Concept

Factors Affecting Speed of Sound

Temperature: in air, speed approximately follows v = v0 + 0.61T, where v0 is speed at 0°C and T is temperature in °C.

As temperature increases, gas molecules move faster and pressure response becomes quicker, so speed of sound increases. At 0°C speed is about 331 m s−1; at 20°C it is about 343 m s−1.

Humidity increases the speed of sound in air because water vapour makes moist air less dense than dry air at the same temperature and pressure.

Pressure alone has almost no effect on speed of sound in an ideal gas at constant temperature because P/ρ remains constant.

Nature of medium matters strongly: sound generally travels fastest in solids, slower in liquids and slowest in gases, due to different elasticity and density.

Exam FocusTemperature increases sound speed.
Exam FocusHumidity increases sound speed in air.
Exam FocusPressure alone does not affect ideal-gas sound speed at fixed temperature.
Concept

Intensity

Intensity is sound power transmitted per unit area perpendicular to the direction of propagation. Formula: I = P/A, where P is power and A is area.

SI unit of intensity is W m−2. Intensity is an objective physical quantity and can be measured by instruments.

For a point source spreading sound uniformly, intensity decreases with distance because the same power spreads over a larger spherical area.

Real-life example: as you move away from a loudspeaker, sound intensity decreases. Doubling distance from a point source ideally reduces intensity to one-fourth.

Common mistake: intensity and loudness are not identical. Intensity is physical power per area; loudness is human sensation.

Exam FocusI = P/A.
Exam FocusIntensity unit: W m−2.
Exam FocusFor point source, I ∝ 1/r2.
Concept

Loudness

Loudness is the subjective sensation of how strong a sound appears to the human ear. It depends mainly on intensity, but also on frequency and ear sensitivity.

A sound of same intensity may not feel equally loud at all frequencies because the human ear is more sensitive around the speech-frequency range.

Real-life example: a high-frequency whistle and a low-frequency hum may have the same measured intensity but may not be perceived equally loud.

Examination perspective: if a question asks physical quantity, answer intensity; if it asks sensation perceived by ear, answer loudness.

Memory trick: intensity belongs to instruments; loudness belongs to ears.

Exam FocusLoudness is subjective.
Exam FocusIntensity is objective.
Exam FocusEar sensitivity matters.
Concept

Quality or Timbre

Quality, also called timbre, is the property by which two sounds of same pitch and loudness can be distinguished.

It depends on waveform, harmonics and overtones present in the sound. Different instruments produce different mixtures of harmonics.

Real-life example: a flute and a violin can play the same note at the same loudness, but we can identify them because their waveforms and harmonics are different.

Musical instruments have a fundamental frequency plus harmonics. The relative strength of these harmonics decides the quality of sound.

Common trap: quality is not frequency alone. Frequency decides pitch; harmonic composition decides quality.

Exam FocusQuality distinguishes instruments.
Exam FocusDepends on harmonics and waveform.
Exam FocusSame pitch can still sound different.
Concept

Pitch

Pitch is the sensation that lets us classify sound as high or low. It depends mainly on frequency.

Higher frequency gives higher pitch; lower frequency gives lower pitch. A whistle has high pitch, while a drum has low pitch.

Human hearing typically covers about 20 Hz to 20,000 Hz. Frequencies below 20 Hz are infrasonic, and above 20 kHz are ultrasonic.

Real-life example: tightening a guitar string increases frequency and therefore pitch.

Common mistake: pitch and loudness are different. A sound can be high-pitched but soft, or low-pitched but loud.

Exam FocusPitch depends on frequency.
Exam FocusLoudness depends mainly on intensity.
Exam FocusQuality depends on waveform.
Formula

Premium Formula Cards

Laplace Formulav = √(γP/ρ)

γ is Cp/Cv, P is pressure and ρ is density. Use for sound in gases.

Elastic Mediumv = √(E/ρ)

E is elastic modulus and ρ is density. This expresses elasticity versus inertia.

IntensityI = P/A

I is intensity, P is power and A is area normal to propagation.

Temperaturev = v0 + 0.61T

Approximate speed in air at T°C, with v0 near 331 m s−1.

Wave Relationv = fλ

Connects speed, frequency and wavelength of sound.

Echod = vt/2

Echo time is round trip time, so one-way distance is half of vt.

Comparison

Newton vs Laplace

PointNewtonLaplace
AssumptionCompression and rarefaction are isothermal.Compression and rarefaction are adiabatic.
Formulav = √(P/ρ)v = √(γP/ρ)
Prediction in airAbout 280 m s−1, too small.About 331 m s−1 at 0°C, close to experiment.
ReasonAssumes heat exchange during compression.Recognises rapid sound propagation leaves no time for heat exchange.
Exam importanceHistorical error and conceptual trap.Correct NEET/JEE formula for gases.
NCERT Style

Sound Wave Diagrams

These diagrams use black lines with red labels and arrows, matching board-work style for Class 11 Physics.

Longitudinal Wave

sound propagation compressionrarefaction particles vibrate parallel to wave direction

Compression and Rarefaction

high pressurelow pressurehigh pressure compressionrarefaction

Pressure Variation Graph

Px pressure maximum at compression pressure minimum at rarefaction

Density Variation Graph

ρx density varies with pressure compressions: high density, rarefactions: low density

Sound Propagation

energy travels through airvibrating source

Newton Formula Concept

Newton assumed isothermal compression v = √(P/ρ) gives too small value for sound in air

Laplace Correction Concept

Laplace: compression and rarefaction are adiabatic v = √(γP/ρ) matches experiment

Speed vs Temperature

vT v = v0 + 0.61T speed increases with temperature

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Solved

50 Diverse Solved Numericals

This numerical bank avoids repeated data-only duplicates and covers temperature, Laplace correction, Newton formula, intensity, echo, pitch, wavelength, medium comparison, humidity reasoning and sound perception.

Numerical 1CBSE Easy

Find speed of sound at 20°C using v = v0 + 0.61T, v0 = 331 m s−1.

Show Solution

Given: T = 20°C, v0 = 331

Formula: v = v0 + 0.61T

Solution: v = 331 + 0.61 × 20 = 343.2 m s−1

Final Answer: 343.2 m s−1

Numerical 2CBSE Easy

Find speed of sound at 30°C if speed at 0°C is 331 m s−1.

Show Solution

Given: T = 30°C

Formula: v = 331 + 0.61T

Solution: v = 331 + 18.3 = 349.3 m s−1

Final Answer: 349.3 m s−1

Numerical 3CBSE Easy

A sound wave has frequency 500 Hz and speed 340 m s−1. Find wavelength.

Show Solution

Given: f = 500 Hz, v = 340

Formula: λ = v/f

Solution: λ = 340/500 = 0.68 m

Final Answer: 0.68 m

Numerical 4CBSE Easy

A wavelength of sound is 2 m and frequency is 170 Hz. Find speed.

Show Solution

Given: λ = 2 m, f = 170 Hz

Formula: v = fλ

Solution: v = 170 × 2 = 340 m s−1

Final Answer: 340 m s−1

Numerical 5CBSE Easy

A source emits sound power 20 W through area 5 m2. Find intensity.

Show Solution

Given: P = 20 W, A = 5 m2

Formula: I = P/A

Solution: I = 20/5 = 4 W m−2

Final Answer: 4 W m−2

Numerical 6CBSE Easy

An echo is heard after 2 s. Speed of sound is 340 m s−1. Find distance of wall.

Show Solution

Given: t = 2 s, v = 340

Formula: d = vt/2

Solution: d = 340 × 2/2 = 340 m

Final Answer: 340 m

Numerical 7CBSE Medium

If speed of sound is 331 m s−1 at 0°C, at what temperature will speed be 343.2 m s−1?

Show Solution

Given: v = 343.2, v0 = 331

Formula: T = (v - v0)/0.61

Solution: T = (343.2 - 331)/0.61 = 20°C

Final Answer: 20°C

Numerical 8CBSE Medium

A sound of wavelength 0.5 m travels at 350 m s−1. Find frequency and pitch type relative to 350 Hz.

Show Solution

Given: λ = 0.5 m, v = 350

Formula: f = v/λ

Solution: f = 350/0.5 = 700 Hz, higher than 350 Hz so higher pitch

Final Answer: 700 Hz, higher pitch

Numerical 9CBSE Medium

A point source emits 100 W uniformly over area 200 m2. Find intensity.

Show Solution

Given: P = 100 W, A = 200 m2

Formula: I = P/A

Solution: I = 100/200 = 0.5 W m−2

Final Answer: 0.5 W m−2

Numerical 10CBSE Medium

If intensity becomes 4 times, what happens to amplitude, assuming I ∝ A2?

Show Solution

Given: I' = 4I

Formula: I ∝ A2

Solution: A'/A = √4 = 2

Final Answer: Amplitude doubles

Numerical 11NEET Easy

Using Newton formula, find speed for P = 1.01 × 105 Pa and ρ = 1.29 kg m−3.

Show Solution

Given: P = 1.01 × 105, ρ = 1.29

Formula: v = √(P/ρ)

Solution: v = √(1.01 × 105/1.29) = 279.8 m s−1

Final Answer: 279.8 m s−1

Numerical 12NEET Easy

Using Laplace formula with γ = 1.4, P = 1.01 × 105 Pa and ρ = 1.29 kg m−3, find speed.

Show Solution

Given: γ = 1.4, P = 1.01 × 105, ρ = 1.29

Formula: v = √(γP/ρ)

Solution: v = √(1.4 × 1.01 × 105/1.29) = 331.0 m s−1

Final Answer: 331 m s−1

Numerical 13NEET Medium

If Newton's predicted speed is 280 m s−1 and γ = 1.4, find Laplace speed.

Show Solution

Given: vN = 280, γ = 1.4

Formula: vL = √γ vN

Solution: vL = √1.4 × 280 = 331.3 m s−1

Final Answer: 331.3 m s−1

Numerical 14NEET Medium

Find speed at 40°C using v = 331 + 0.61T.

Show Solution

Given: T = 40°C

Formula: v = 331 + 0.61T

Solution: v = 331 + 24.4 = 355.4 m s−1

Final Answer: 355.4 m s−1

Numerical 15NEET Medium

Temperature rises from 10°C to 30°C. Find increase in speed of sound.

Show Solution

Given: ΔT = 20°C

Formula: Δv = 0.61ΔT

Solution: Δv = 0.61 × 20 = 12.2 m s−1

Final Answer: 12.2 m s−1

Numerical 16NEET Medium

A sound intensity is 8 W m−2 over area 3 m2. Find power crossing the area.

Show Solution

Given: I = 8, A = 3

Formula: P = IA

Solution: P = 8 × 3 = 24 W

Final Answer: 24 W

Numerical 17NEET Medium

At 20 m from a point source intensity is I. What is intensity at 40 m?

Show Solution

Given: r doubles

Formula: I ∝ 1/r2

Solution: I' = I/22 = I/4

Final Answer: I/4

Numerical 18NEET Medium

A sound has frequency 1000 Hz and wavelength 0.34 m. Find speed and decide if it is audible.

Show Solution

Given: f = 1000 Hz, λ = 0.34 m

Formula: v = fλ

Solution: v = 340 m s−1; 1000 Hz is audible

Final Answer: 340 m s−1, audible

Numerical 19NEET Difficult

A bat receives ultrasound echo after 0.04 s from an insect. Speed is 340 m s−1. Find distance.

Show Solution

Given: t = 0.04 s, v = 340

Formula: d = vt/2

Solution: d = 340 × 0.04/2 = 6.8 m

Final Answer: 6.8 m

Numerical 20NEET Difficult

A submarine sonar echo returns after 0.6 s. Speed in water is 1500 m s−1. Find depth.

Show Solution

Given: t = 0.6 s, v = 1500

Formula: d = vt/2

Solution: d = 1500 × 0.6/2 = 450 m

Final Answer: 450 m

Numerical 21NEET Difficult

If frequency changes from 256 Hz to 512 Hz at same speed, what happens to wavelength and pitch?

Show Solution

Given: f doubles, v constant

Formula: λ = v/f

Solution: Wavelength halves; pitch increases

Final Answer: Wavelength halves, pitch higher

Numerical 22NEET Difficult

Two sounds have same frequency and intensity but different waveforms. Which property differs?

Show Solution

Given: Same f, same intensity, different waveform

Formula: Quality depends on waveform

Solution: Quality or timbre differs

Final Answer: Quality/timbre

Numerical 23JEE Main Easy

For air with γ = 1.4, calculate ratio of Laplace speed to Newton speed.

Show Solution

Given: γ = 1.4

Formula: vL/vN = √γ

Solution: ratio = √1.4 = 1.183

Final Answer: 1.183

Numerical 24JEE Main Easy

If pressure is doubled at constant temperature for ideal gas, what happens to sound speed?

Show Solution

Given: T constant, ideal gas

Formula: P/ρ constant

Solution: Speed remains unchanged

Final Answer: No change

Numerical 25JEE Main Medium

A gas has γ = 5/3, P = 105 Pa, ρ = 1.2 kg m−3. Find sound speed.

Show Solution

Given: γ = 5/3, P = 105, ρ = 1.2

Formula: v = √(γP/ρ)

Solution: v = √((5/3)×105/1.2) = 372.7 m s−1

Final Answer: 372.7 m s−1

Numerical 26JEE Main Medium

Find bulk modulus of a liquid where sound speed is 1400 m s−1 and density is 1000 kg m−3.

Show Solution

Given: v = 1400, ρ = 1000

Formula: E = ρv2

Solution: E = 1000 × 14002 = 1.96 × 109 Pa

Final Answer: 1.96 × 109 Pa

Numerical 27JEE Main Medium

Two media have same elasticity but densities in ratio 1:4. Find sound speed ratio.

Show Solution

Given: E same, ρ12 = 1:4

Formula: v ∝ 1/√ρ

Solution: v1:v2 = 2:1

Final Answer: 2:1

Numerical 28JEE Main Medium

Two media have same density but elasticities in ratio 9:16. Find speed ratio.

Show Solution

Given: ρ same, E1:E2 = 9:16

Formula: v ∝ √E

Solution: v1:v2 = 3:4

Final Answer: 3:4

Numerical 29JEE Main Medium

A source emits 80 W uniformly over a sphere of radius 2 m. Find intensity.

Show Solution

Given: P = 80 W, r = 2 m

Formula: I = P/(4πr2)

Solution: I = 80/(16π) = 5/π W m−2

Final Answer: 5/π W m−2

Numerical 30JEE Main Medium

If distance from point source becomes 3 times, what happens to intensity?

Show Solution

Given: r' = 3r

Formula: I ∝ 1/r2

Solution: I' = I/9

Final Answer: I/9

Numerical 31JEE Main Difficult

At what temperature will speed be 360 m s−1 using v = 331 + 0.61T?

Show Solution

Given: v = 360

Formula: T = (v - 331)/0.61

Solution: T = 29/0.61 = 47.54°C

Final Answer: 47.5°C

Numerical 32JEE Main Difficult

Find frequency of ultrasound of wavelength 5 mm in air at 340 m s−1.

Show Solution

Given: λ = 5 mm = 0.005 m, v = 340

Formula: f = v/λ

Solution: f = 340/0.005 = 68000 Hz

Final Answer: 68 kHz

Numerical 33JEE Main Difficult

A sound intensity level problem gives I/I0 = 100. By what factor is amplitude greater than threshold amplitude?

Show Solution

Given: I/I0 = 100

Formula: I ∝ A2

Solution: A/A0 = √100 = 10

Final Answer: 10

Numerical 34JEE Main Difficult

A detector area 0.02 m2 receives sound energy 0.6 J in 10 s. Find intensity.

Show Solution

Given: E = 0.6 J, t = 10 s, A = 0.02

Formula: P = E/t, I = P/A

Solution: P = 0.06 W; I = 0.06/0.02 = 3 W m−2

Final Answer: 3 W m−2

Numerical 35JEE Advanced Easy

Show why Newton speed is lower than Laplace speed.

Show Solution

Given: Newton: P, Laplace: γP

Formula: vL/vN = √γ

Solution: Since γ > 1, Laplace speed is larger

Final Answer: Laplace speed is √γ times Newton speed

Numerical 36JEE Advanced Medium

A gas has Newton speed 300 m s−1. Experimental speed is 354 m s−1. Find γ.

Show Solution

Given: vN = 300, vL = 354

Formula: γ = (vL/vN)2

Solution: γ = (354/300)2 = 1.3924

Final Answer: 1.39

Numerical 37JEE Advanced Medium

A gas mixture changes γ from 1.4 to 1.67 at same P and ρ. Find speed ratio.

Show Solution

Given: γ1 = 1.4, γ2 = 1.67

Formula: v ∝ √γ

Solution: v2/v1 = √(1.67/1.4) = 1.092

Final Answer: 1.092

Numerical 38JEE Advanced Medium

Speed in a solid is 5000 m s−1, density is 8000 kg m−3. Estimate elastic modulus.

Show Solution

Given: v = 5000, ρ = 8000

Formula: E = ρv2

Solution: E = 8000 × 25 × 106 = 2.0 × 1011 Pa

Final Answer: 2.0 × 1011 Pa

Numerical 39JEE Advanced Medium

A pressure antinode corresponds to which density condition in sound wave?

Show Solution

Given: Pressure antinode in sound

Formula: Pressure and density variations are in phase

Solution: Density variation is maximum there

Final Answer: Maximum density variation

Numerical 40JEE Advanced Medium

If sound speed changes from 330 to 345 m s−1 and frequency remains 690 Hz, find wavelength change.

Show Solution

Given: v1 = 330, v2 = 345, f = 690

Formula: λ = v/f

Solution: λ1 = 0.478 m; λ2 = 0.500 m; increase = 0.022 m

Final Answer: 0.022 m increase

Numerical 41JEE Advanced Difficult

A source power is constant. If distance from source changes from 5 m to 20 m, find intensity ratio.

Show Solution

Given: r1 = 5, r2 = 20

Formula: I ∝ 1/r2

Solution: I2/I1 = (5/20)2 = 1/16

Final Answer: 1/16

Numerical 42JEE Advanced Difficult

Two sounds have intensities in ratio 16:1. Find amplitude ratio.

Show Solution

Given: I1:I2 = 16:1

Formula: I ∝ A2

Solution: A1:A2 = 4:1

Final Answer: 4:1

Numerical 43JEE Advanced Difficult

At 27°C speed is about 331 + 0.61 × 27. Find time for sound to travel 1 km.

Show Solution

Given: T = 27°C, distance = 1000 m

Formula: v = 331 + 0.61T, t = s/v

Solution: v = 347.47; t = 1000/347.47 = 2.88 s

Final Answer: 2.88 s

Numerical 44JEE Advanced Difficult

An observer hears echo after 3 s at 30°C. Use v = 331 + 0.61T. Find reflector distance.

Show Solution

Given: T = 30°C, echo time = 3 s

Formula: v = 331 + 0.61T, d = vt/2

Solution: v = 349.3; d = 349.3 × 3/2 = 523.95 m

Final Answer: 524 m

Numerical 45IB

A sound wave transfers 12 J energy in 4 s through area 6 m2. Find intensity.

Show Solution

Given: E = 12 J, t = 4 s, A = 6

Formula: P = E/t, I = P/A

Solution: P = 3 W; I = 3/6 = 0.5 W m−2

Final Answer: 0.5 W m−2

Numerical 46ICSE

If frequency of a sound is doubled but amplitude unchanged, what changes: pitch or loudness?

Show Solution

Given: Frequency doubles, amplitude same

Formula: Pitch depends on frequency

Solution: Pitch increases; loudness may remain nearly same

Final Answer: Pitch increases

Numerical 47IGCSE

A student says louder sound always has higher pitch. Correct using an example.

Show Solution

Given: Loudness and pitch are different

Formula: Loudness depends intensity; pitch depends frequency

Solution: A loud drum can have low pitch and a soft whistle can have high pitch

Final Answer: Statement is false

Numerical 48A-Level

A sound wave in air has pressure and displacement variations. What is their phase relation?

Show Solution

Given: Progressive sound wave

Formula: Pressure and displacement differ by π/2

Solution: Pressure variation is maximum where displacement gradient is maximum

Final Answer: Phase difference π/2

Numerical 49Reasoning

Why does humidity increase speed of sound in air?

Show Solution

Given: Moist air has lower density than dry air at same T and P

Formula: v = √(γP/ρ)

Solution: Lower density gives higher speed

Final Answer: Humidity increases speed

Numerical 50Reasoning

Why pressure at constant temperature does not affect speed in ideal gas?

Show Solution

Given: P changes with ρ proportionally

Formula: v = √(γP/ρ)

Solution: P/ρ remains constant at fixed T

Final Answer: Speed unchanged

Numerical 51Conceptual

A flute and violin play same note with same loudness. Which property distinguishes them?

Show Solution

Given: Same pitch, same loudness

Formula: Quality depends on waveform and harmonics

Solution: Their quality or timbre differs

Final Answer: Quality/timbre

Numerical 52Conceptual

A sound is ultrasonic at 40 kHz. Is it audible to normal human ear?

Show Solution

Given: f = 40 kHz

Formula: Human range about 20 Hz to 20 kHz

Solution: 40 kHz is above hearing range

Final Answer: Not audible

Numerical 53Conceptual

If amplitude of sound wave increases but frequency remains same, which perception changes mainly?

Show Solution

Given: Amplitude increases, frequency same

Formula: Loudness depends on amplitude/intensity

Solution: Loudness increases; pitch remains same

Final Answer: Loudness increases

Numerical 54Conceptual

If waveform changes but frequency and intensity remain same, which perception changes?

Show Solution

Given: Waveform changes

Formula: Quality depends on waveform

Solution: Quality/timbre changes

Final Answer: Quality changes

Question Bank

60 PYQs and Exam Questions

Includes CBSE, NEET, JEE Main, JEE Advanced, IB, ICSE, IGCSE, A-Level, assertion-reason, true-false, case-study, reasoning and conceptual questions.

Question 1CBSE

Why is sound called a mechanical wave?

Show Answer

Because it requires a material medium for propagation.

Question 2CBSE

What type of wave is sound in air?

Show Answer

Longitudinal mechanical wave.

Question 3CBSE

Define compression and rarefaction.

Show Answer

Compression is high pressure-density region; rarefaction is low pressure-density region.

Question 4CBSE

Can sound travel in vacuum?

Show Answer

No, because sound needs a material medium.

Question 5CBSE

Write Newton's formula for speed of sound.

Show Answer

v = √(P/ρ).

Question 6CBSE

Write Laplace corrected formula.

Show Answer

v = √(γP/ρ).

Question 7CBSE

What is intensity of sound?

Show Answer

Power transmitted per unit area normal to propagation.

Question 8CBSE

Write SI unit of intensity.

Show Answer

W m−2.

Question 9NEET

Why was Newton's formula incorrect?

Show Answer

It assumed isothermal changes, but sound propagation in gas is adiabatic.

Question 10NEET

What is γ in Laplace formula?

Show Answer

Ratio of specific heats, Cp/Cv.

Question 11NEET

What happens to speed of sound with temperature?

Show Answer

It increases with temperature.

Question 12NEET

What is approximate temperature formula in air?

Show Answer

v = v0 + 0.61T.

Question 13NEET

Does pressure affect speed of sound in ideal gas at constant temperature?

Show Answer

No, because P/ρ remains constant.

Question 14NEET

Does humidity increase or decrease sound speed?

Show Answer

It increases sound speed in air.

Question 15NEET

Which is objective: intensity or loudness?

Show Answer

Intensity is objective.

Question 16NEET

Pitch depends mainly on which quantity?

Show Answer

Frequency.

Question 17JEE Main

Why are sound compressions adiabatic?

Show Answer

They happen too fast for heat exchange.

Question 18JEE Main

Compare Newton and Laplace speeds.

Show Answer

Laplace speed is √γ times Newton speed.

Question 19JEE Main

What is the general formula for sound speed in elastic medium?

Show Answer

v = √(E/ρ) or v = √(elastic modulus/density).

Question 20JEE Main

What is pressure-displacement phase difference in progressive sound wave?

Show Answer

π/2.

Question 21JEE Main

What is pressure-density relation in sound?

Show Answer

Pressure and density variations are in phase.

Question 22JEE Main

What is the speed formula in a liquid using bulk modulus?

Show Answer

v = √(B/ρ).

Question 23JEE Advanced

Why does Laplace correction solve historical error?

Show Answer

It uses adiabatic bulk modulus γP instead of isothermal modulus P.

Question 24JEE Advanced

If γ increases at same P and ρ, what happens to speed?

Show Answer

Speed increases as √γ.

Question 25JEE Advanced

Why is sound faster in solids than gases generally?

Show Answer

Solids have much larger elastic modulus.

Question 26JEE Advanced

Can two sounds have same pitch but different quality?

Show Answer

Yes, if harmonic composition differs.

Question 27IB

Explain loudness versus intensity.

Show Answer

Loudness is subjective sensation; intensity is measurable power per area.

Question 28IB

Explain pitch versus frequency.

Show Answer

Pitch is perception; frequency is physical quantity mainly deciding pitch.

Question 29IB

What is timbre?

Show Answer

Quality of sound determined by waveform and harmonics.

Question 30IB

What is an overtone?

Show Answer

A frequency component above the fundamental.

Question 31ICSE

Name the regions of high pressure in sound wave.

Show Answer

Compressions.

Question 32ICSE

Name regions of low pressure in sound wave.

Show Answer

Rarefactions.

Question 33ICSE

What frequency range is audible to humans?

Show Answer

About 20 Hz to 20 kHz.

Question 34ICSE

What is ultrasound?

Show Answer

Sound with frequency above 20 kHz.

Question 35IGCSE

Give one example proving sound needs medium.

Show Answer

Bell in evacuated jar becomes faint or inaudible.

Question 36IGCSE

Why is sound louder near a speaker?

Show Answer

Intensity is larger near the source.

Question 37IGCSE

What changes when guitar string is tightened?

Show Answer

Frequency and pitch increase.

Question 38IGCSE

Why do instruments sound different at same note?

Show Answer

Different harmonics and waveform.

Question 39A-Level

State relation between intensity and amplitude.

Show Answer

Intensity is proportional to amplitude squared.

Question 40A-Level

State inverse square relation for a point source.

Show Answer

I ∝ 1/r2.

Question 41A-Level

What thermodynamic process occurs in sound propagation in gas?

Show Answer

Adiabatic process.

Question 42A-Level

What modulus is used in Laplace formula for gas?

Show Answer

Adiabatic bulk modulus γP.

Question 43Assertion-Reason

Assertion: Sound cannot travel in vacuum. Reason: Sound is mechanical.

Show Answer

Both true and reason explains assertion.

Question 44Assertion-Reason

Assertion: Laplace formula is more accurate than Newton formula. Reason: Sound propagation is adiabatic.

Show Answer

Both true and reason explains assertion.

Question 45Assertion-Reason

Assertion: Humidity increases speed of sound. Reason: Moist air is less dense than dry air.

Show Answer

Both true and reason explains assertion.

Question 46Assertion-Reason

Assertion: Pressure alone changes sound speed in ideal gas at constant temperature. Reason: P/ρ remains constant.

Show Answer

Assertion false, reason true.

Question 47True/False

Sound in air is transverse.

Show Answer

False.

Question 48True/False

Loudness and intensity are exactly same.

Show Answer

False.

Question 49True/False

Pitch depends mainly on frequency.

Show Answer

True.

Question 50True/False

Quality depends on waveform and harmonics.

Show Answer

True.

Question 51True/False

Speed of sound increases with temperature.

Show Answer

True.

Question 52Case Study

A bell jar is evacuated and bell sound becomes weak. What does it prove?

Show Answer

Sound requires a material medium.

Question 53Case Study

A sonar echo returns after 0.5 s in water. Which formula is used for depth?

Show Answer

d = vt/2.

Question 54Case Study

A violin and flute play same note. Why do they sound different?

Show Answer

Different timbre due to different harmonics.

Question 55Case Study

A hot day gives larger sound speed than cold day. Which relation explains this?

Show Answer

v = v0 + 0.61T.

Question 56Reasoning

Why is loudness subjective?

Show Answer

It depends on human ear sensitivity, not only physical intensity.

Question 57Reasoning

Why is intensity objective?

Show Answer

It is measurable power per unit area.

Question 58Conceptual

Can a low-pitch sound be loud?

Show Answer

Yes, pitch and loudness are different.

Question 59Conceptual

Can two sounds have same loudness and pitch but different quality?

Show Answer

Yes, if their waveforms/harmonics differ.

Question 60Conceptual

What is the main conceptual difference between pressure graph and particle displacement graph?

Show Answer

They represent different variables and are phase shifted.

Question 61Conceptual

Why does sound carry energy but not matter from source to listener?

Show Answer

Medium particles oscillate locally while disturbance propagates.

Mistakes

Common Mistakes

  • Confusing loudness and intensity: intensity is measurable power per area; loudness is sensation.
  • Confusing pitch and quality: pitch depends on frequency; quality depends on waveform and harmonics.
  • Using Newton formula incorrectly: Newton's isothermal assumption gives a low speed for sound in air.
  • Forgetting Laplace correction: use v = √(γP/ρ) for gases.
  • Wrong temperature relation: in air use approximate v = v0 + 0.61T, with T in °C.
  • Echo mistake: reflector distance is vt/2, not vt.
Revision

Quick Revision Notes

  • Sound is a longitudinal mechanical wave.
  • Sound needs a material medium.
  • Compression has high pressure and density.
  • Rarefaction has low pressure and density.
  • Newton formula: v = √(P/ρ).
  • Laplace formula: v = √(γP/ρ).
  • γ = Cp/Cv.
  • Sound propagation in gases is adiabatic.
  • Temperature increases sound speed.
  • Humidity increases sound speed in air.
  • Intensity I = P/A.
  • Pitch depends on frequency.
  • Loudness depends mainly on intensity and ear sensitivity.
  • Quality depends on harmonics and waveform.
  • Echo distance is vt/2.

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