A spherical mirror is a reflecting surface that forms part of a sphere. If the reflecting surface is on the inner side of the spherical surface, the mirror is called a concave mirror. If the reflecting surface is on the outer bulging side, it is called a convex mirror. Spherical mirrors are essential in ray optics because they can converge or diverge light rays and form real or virtual images depending on object position.
Spherical mirrors are used in shaving mirrors, dentist mirrors, vehicle rear-view mirrors, torches, headlights, solar cookers, security mirrors and reflecting telescopes. The study of spherical mirrors introduces important terms such as pole, principal axis, centre of curvature, radius of curvature, principal focus and focal length.
Concave mirror A converging mirror whose reflecting surface is curved inward.
Convex mirror A diverging mirror whose reflecting surface bulges outward.
2. Concave Mirror
A concave mirror reflects parallel rays towards a common point called the principal focus. It can form real and inverted images as well as virtual and erect images depending on object position.
The reflected ray starts exactly at the point of incidence and passes through F.
3. Convex Mirror
A convex mirror reflects rays as if they are diverging from a focus behind the mirror. It always forms a virtual, erect and diminished image for a real object.
Convex mirror is a diverging mirror. Its virtual F and C lie behind the mirror.
4–10. Important Terms of Spherical Mirrors
4. Pole The pole P is the geometrical centre of the reflecting surface of a spherical mirror.
5. Principal Axis The straight line passing through pole P and centre of curvature C is called principal axis.
6. Centre of Curvature The centre of the sphere of which the mirror is a part is called centre of curvature C.
7. Radius of Curvature The radius of the sphere of which the mirror is a part is called radius of curvature R.
8. Principal Focus The point where rays parallel to the principal axis meet or appear to meet after reflection is called focus F.
9. Focal Length The distance between pole P and principal focus F is called focal length f.
10. Relation between Radius and Focal Length For paraxial rays of spherical mirrors, focal length is half the radius of curvature.
f = R/2
For a spherical mirror of small aperture, focus lies midway between pole P and centre C.
11. Ray Diagrams for Concave Mirror
Each diagram is generated from exact incidence points. Red incident rays strike the mirror, blue reflected rays start from the same points, and the image is placed only at ray intersection.
Object at infinity
Image at F, real, inverted, highly diminished.
Beyond C
Image between C and F, real, inverted, diminished.
At C
Image at C, real, inverted, same size.
Between C and F
Image beyond C, real, inverted, enlarged.
At F
Image at infinity, real, inverted, highly enlarged.
Between F and P
Image behind mirror, virtual, erect, enlarged.
12. Ray Diagrams for Convex Mirror
For a convex mirror, reflected rays diverge and their dotted backward extensions meet behind the mirror. The virtual image is placed exactly at that extension intersection.
Solid lines show real rays; dotted lines show backward virtual extensions.
Object at infinity Image at focus, virtual, erect and point-sized.
Object anywhere in front Image between P and F, virtual, erect and diminished.
13. New Cartesian Sign Convention
All distances are measured from pole P. Distances measured in the direction of incident light are positive and distances measured opposite to incident light are negative. Heights above principal axis are positive and below principal axis are negative.
14–15. Mirror Formula and Magnification
Mirror Formula1/f = 1/v + 1/u
u is object distance, v is image distance, f is focal length.
Magnificationm = -v/u = h'/h
m is negative for a real inverted image and positive for a virtual erect image.
Radius Relationf = R/2
R is radius of curvature.
Mirror Formula Derivation: Concave Mirror Forming Real Image
For a real object placed beyond focus of a concave mirror, the image is real and inverted on the reflecting side. Draw one ray parallel to the principal axis and another ray through centre C. Using similar triangles formed by the object, image and pole P, the ratio of heights gives the same magnification from both triangle pairs. Applying the New Cartesian Sign Convention to those ratios gives:
1/f = 1/v + 1/u
Here u < 0, v < 0 and f < 0 for the usual concave real-image case.
Mirror Formula Derivation: Concave Mirror Forming Virtual Image
When the object is between F and P, reflected rays diverge and their dotted backward extensions meet behind the mirror. The same similar-triangle construction is used, but now the image distance is behind the mirror. With sign convention, u < 0, f < 0 and v > 0. The final relation remains:
1/f = 1/v + 1/u
Mirror Formula Derivation: Convex Mirror Forming Virtual Image
For a convex mirror, reflected rays always diverge and their backward extensions meet behind the mirror between P and F. Since F and C are virtual and behind the mirror, f > 0 and v > 0, while the real object has u < 0. Similar triangles again give:
1/f = 1/v + 1/u
Magnification Derivation
From similar triangles made by object height h, image height h' and pole P:
h'/h = -v/u
Therefore:
m = h'/h = -v/u
For a real inverted image, h' is negative and m is negative. For a virtual erect image, h' is positive and m is positive.
For paraxial rays, the focus lies midway between pole and centre of curvature, hence f = R/2.
16. Image Formation Cases for Concave Mirror
Object Position
Image Position
Nature
Size
Object at infinity
Image at F
real
highly diminished.
Beyond C
Image between C and F
real
diminished.
At C
Image at C
real
same size.
Between C and F
Image beyond C
real
enlarged.
At F
Image at infinity
real
highly enlarged.
Between F and P
Image behind mirror
virtual
enlarged.
17. Image Formation Cases for Convex Mirror
Object Position
Image Position
Nature
Size
At infinity
At focus behind mirror
Virtual and erect
Highly diminished
Anywhere in front of mirror
Between P and F behind mirror
Virtual and erect
Diminished
18–19. Applications of Concave and Convex Mirrors
Dentist mirror Concave mirror gives enlarged virtual image when object is between F and P.
Shaving mirror Concave mirror magnifies the face when used close to the face.
Solar cooker Concave mirror concentrates sunlight at focus.
Vehicle rear-view mirror Convex mirror gives wide field of view.
Security mirror Convex mirror helps observe a large area.
20. Important NCERT Concepts
Paraxial rays Mirror formula and f=R/2 are accurate for rays close to principal axis.
Real vs virtual Real images form by actual intersection; virtual images by apparent intersection.
Concave versatility Concave mirrors can form real or virtual images.
Convex stability Convex mirror always forms virtual, erect, diminished image.
Sign convention Most numerical errors come from wrong signs of u, v and f.
Magnification sign Negative m usually means inverted image; positive m means erect image.
21. Common Mistakes
Using f=R instead of f=R/2.
Forgetting signs in mirror formula.
Drawing convex mirror focus in front of mirror.
Calling convex mirror image real.
Confusing C and F positions.
Using lens sign convention in mirror problems without checking.
22. Quick Revision Sheet
Formulas
f = R/2
1/f = 1/v + 1/u
m = -v/u = h′/h
Concave mirror
Converging mirror
Can form real or virtual images
Used in shaving mirror, torch, solar cooker
Convex mirror
Diverging mirror
Always virtual, erect, diminished image
Used in rear-view and security mirrors
Numerical Practice
NEET Numericals / Questions
NEET Question 1. A concave mirror has R = 40 cm. Find f.
NEET
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
NEET Question 2. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
NEET
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
NEET Question 3. A convex mirror has f = 20 cm and object at 30 cm. Find v.
NEET
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
NEET Question 4. Find magnification if u=-40 cm and v=-20 cm.
NEET
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
NEET Question 5. A mirror forms image twice the size and erect. What type of mirror?
NEET
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
NEET Question 6. A concave mirror has R = 40 cm. Find f.
NEET
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
NEET Question 7. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
NEET
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
NEET Question 8. A convex mirror has f = 20 cm and object at 30 cm. Find v.
NEET
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
NEET Question 9. Find magnification if u=-40 cm and v=-20 cm.
NEET
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
NEET Question 10. A mirror forms image twice the size and erect. What type of mirror?
NEET
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
NEET Question 11. A concave mirror has R = 40 cm. Find f.
NEET
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
NEET Question 12. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
NEET
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
NEET Question 13. A convex mirror has f = 20 cm and object at 30 cm. Find v.
NEET
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
NEET Question 14. Find magnification if u=-40 cm and v=-20 cm.
NEET
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
NEET Question 15. A mirror forms image twice the size and erect. What type of mirror?
NEET
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
NEET Question 16. A concave mirror has R = 40 cm. Find f.
NEET
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
NEET Question 17. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
NEET
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
NEET Question 18. A convex mirror has f = 20 cm and object at 30 cm. Find v.
NEET
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
NEET Question 19. Find magnification if u=-40 cm and v=-20 cm.
NEET
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
NEET Question 20. A mirror forms image twice the size and erect. What type of mirror?
NEET
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
NEET Question 21. A concave mirror has R = 40 cm. Find f.
NEET
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
NEET Question 22. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
NEET
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
NEET Question 23. A convex mirror has f = 20 cm and object at 30 cm. Find v.
NEET
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
NEET Question 24. Find magnification if u=-40 cm and v=-20 cm.
NEET
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
NEET Question 25. A mirror forms image twice the size and erect. What type of mirror?
NEET
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
NEET Question 26. A concave mirror has R = 40 cm. Find f.
NEET
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
NEET Question 27. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
NEET
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
NEET Question 28. A convex mirror has f = 20 cm and object at 30 cm. Find v.
NEET
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
NEET Question 29. Find magnification if u=-40 cm and v=-20 cm.
NEET
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
NEET Question 30. A mirror forms image twice the size and erect. What type of mirror?
NEET
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
JEE Main Numericals / Questions
JEE Main Question 31. A concave mirror has R = 40 cm. Find f.
JEE Main
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
JEE Main Question 32. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
JEE Main
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
JEE Main Question 33. A convex mirror has f = 20 cm and object at 30 cm. Find v.
JEE Main
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
JEE Main Question 34. Find magnification if u=-40 cm and v=-20 cm.
JEE Main
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
JEE Main Question 35. A mirror forms image twice the size and erect. What type of mirror?
JEE Main
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
JEE Main Question 36. A concave mirror has R = 40 cm. Find f.
JEE Main
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
JEE Main Question 37. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
JEE Main
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
JEE Main Question 38. A convex mirror has f = 20 cm and object at 30 cm. Find v.
JEE Main
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
JEE Main Question 39. Find magnification if u=-40 cm and v=-20 cm.
JEE Main
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
JEE Main Question 40. A mirror forms image twice the size and erect. What type of mirror?
JEE Main
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
JEE Main Question 41. A concave mirror has R = 40 cm. Find f.
JEE Main
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
JEE Main Question 42. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
JEE Main
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
JEE Main Question 43. A convex mirror has f = 20 cm and object at 30 cm. Find v.
JEE Main
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
JEE Main Question 44. Find magnification if u=-40 cm and v=-20 cm.
JEE Main
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
JEE Main Question 45. A mirror forms image twice the size and erect. What type of mirror?
JEE Main
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
JEE Main Question 46. A concave mirror has R = 40 cm. Find f.
JEE Main
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
JEE Main Question 47. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
JEE Main
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
JEE Main Question 48. A convex mirror has f = 20 cm and object at 30 cm. Find v.
JEE Main
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
JEE Main Question 49. Find magnification if u=-40 cm and v=-20 cm.
JEE Main
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
JEE Main Question 50. A mirror forms image twice the size and erect. What type of mirror?
JEE Main
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
JEE Main Question 51. A concave mirror has R = 40 cm. Find f.
JEE Main
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
JEE Main Question 52. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
JEE Main
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
JEE Main Question 53. A convex mirror has f = 20 cm and object at 30 cm. Find v.
JEE Main
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
JEE Main Question 54. Find magnification if u=-40 cm and v=-20 cm.
JEE Main
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
JEE Main Question 55. A mirror forms image twice the size and erect. What type of mirror?
JEE Main
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
JEE Advanced Numericals / Questions
JEE Advanced Question 56. A concave mirror has R = 40 cm. Find f.
JEE Advanced
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
JEE Advanced Question 57. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
JEE Advanced
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
JEE Advanced Question 58. A convex mirror has f = 20 cm and object at 30 cm. Find v.
JEE Advanced
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
JEE Advanced Question 59. Find magnification if u=-40 cm and v=-20 cm.
JEE Advanced
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
JEE Advanced Question 60. A mirror forms image twice the size and erect. What type of mirror?
JEE Advanced
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
JEE Advanced Question 61. A concave mirror has R = 40 cm. Find f.
JEE Advanced
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
JEE Advanced Question 62. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
JEE Advanced
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
JEE Advanced Question 63. A convex mirror has f = 20 cm and object at 30 cm. Find v.
JEE Advanced
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
JEE Advanced Question 64. Find magnification if u=-40 cm and v=-20 cm.
JEE Advanced
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
JEE Advanced Question 65. A mirror forms image twice the size and erect. What type of mirror?
JEE Advanced
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
JEE Advanced Question 66. A concave mirror has R = 40 cm. Find f.
JEE Advanced
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
JEE Advanced Question 67. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
JEE Advanced
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
JEE Advanced Question 68. A convex mirror has f = 20 cm and object at 30 cm. Find v.
JEE Advanced
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
JEE Advanced Question 69. Find magnification if u=-40 cm and v=-20 cm.
JEE Advanced
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
JEE Advanced Question 70. A mirror forms image twice the size and erect. What type of mirror?
JEE Advanced
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
JEE Advanced Question 71. A concave mirror has R = 40 cm. Find f.
JEE Advanced
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
JEE Advanced Question 72. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
JEE Advanced
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
JEE Advanced Question 73. A convex mirror has f = 20 cm and object at 30 cm. Find v.
JEE Advanced
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
JEE Advanced Question 74. Find magnification if u=-40 cm and v=-20 cm.
JEE Advanced
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
JEE Advanced Question 75. A mirror forms image twice the size and erect. What type of mirror?
JEE Advanced
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
CBSE Board Numericals / Questions
CBSE Board Question 76. A concave mirror has R = 40 cm. Find f.
CBSE Board
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
CBSE Board Question 77. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
CBSE Board
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
CBSE Board Question 78. A convex mirror has f = 20 cm and object at 30 cm. Find v.
CBSE Board
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
CBSE Board Question 79. Find magnification if u=-40 cm and v=-20 cm.
CBSE Board
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
CBSE Board Question 80. A mirror forms image twice the size and erect. What type of mirror?
CBSE Board
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
CBSE Board Question 81. A concave mirror has R = 40 cm. Find f.
CBSE Board
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
CBSE Board Question 82. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
CBSE Board
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
CBSE Board Question 83. A convex mirror has f = 20 cm and object at 30 cm. Find v.
CBSE Board
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
CBSE Board Question 84. Find magnification if u=-40 cm and v=-20 cm.
CBSE Board
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
CBSE Board Question 85. A mirror forms image twice the size and erect. What type of mirror?
CBSE Board
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
CBSE Board Question 86. A concave mirror has R = 40 cm. Find f.
CBSE Board
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
CBSE Board Question 87. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
CBSE Board
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
CBSE Board Question 88. A convex mirror has f = 20 cm and object at 30 cm. Find v.
CBSE Board
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
CBSE Board Question 89. Find magnification if u=-40 cm and v=-20 cm.
CBSE Board
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
CBSE Board Question 90. A mirror forms image twice the size and erect. What type of mirror?
CBSE Board
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
IB Physics Numericals / Questions
IB Physics Question 91. A concave mirror has R = 40 cm. Find f.
IB Physics
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
IB Physics Question 92. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
IB Physics
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
IB Physics Question 93. A convex mirror has f = 20 cm and object at 30 cm. Find v.
IB Physics
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
IB Physics Question 94. Find magnification if u=-40 cm and v=-20 cm.
IB Physics
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
IB Physics Question 95. A mirror forms image twice the size and erect. What type of mirror?
IB Physics
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
IB Physics Question 96. A concave mirror has R = 40 cm. Find f.
IB Physics
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
IB Physics Question 97. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
IB Physics
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
IB Physics Question 98. A convex mirror has f = 20 cm and object at 30 cm. Find v.
IB Physics
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
IB Physics Question 99. Find magnification if u=-40 cm and v=-20 cm.
IB Physics
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
IB Physics Question 100. A mirror forms image twice the size and erect. What type of mirror?
IB Physics
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
IB Physics Question 101. A concave mirror has R = 40 cm. Find f.
IB Physics
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
IB Physics Question 102. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
IB Physics
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
IB Physics Question 103. A convex mirror has f = 20 cm and object at 30 cm. Find v.
IB Physics
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
IB Physics Question 104. Find magnification if u=-40 cm and v=-20 cm.
IB Physics
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
IB Physics Question 105. A mirror forms image twice the size and erect. What type of mirror?
IB Physics
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
IGCSE Physics Numericals / Questions
IGCSE Physics Question 106. A concave mirror has R = 40 cm. Find f.
IGCSE Physics
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
IGCSE Physics Question 107. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
IGCSE Physics
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
IGCSE Physics Question 108. A convex mirror has f = 20 cm and object at 30 cm. Find v.
IGCSE Physics
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
IGCSE Physics Question 109. Find magnification if u=-40 cm and v=-20 cm.
IGCSE Physics
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
IGCSE Physics Question 110. A mirror forms image twice the size and erect. What type of mirror?
IGCSE Physics
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
IGCSE Physics Question 111. A concave mirror has R = 40 cm. Find f.
IGCSE Physics
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
IGCSE Physics Question 112. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
IGCSE Physics
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
IGCSE Physics Question 113. A convex mirror has f = 20 cm and object at 30 cm. Find v.
IGCSE Physics
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
IGCSE Physics Question 114. Find magnification if u=-40 cm and v=-20 cm.
IGCSE Physics
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
IGCSE Physics Question 115. A mirror forms image twice the size and erect. What type of mirror?
IGCSE Physics
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
IGCSE Physics Question 116. A concave mirror has R = 40 cm. Find f.
IGCSE Physics
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
IGCSE Physics Question 117. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
IGCSE Physics
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
IGCSE Physics Question 118. A convex mirror has f = 20 cm and object at 30 cm. Find v.
IGCSE Physics
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
IGCSE Physics Question 119. Find magnification if u=-40 cm and v=-20 cm.
IGCSE Physics
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
IGCSE Physics Question 120. A mirror forms image twice the size and erect. What type of mirror?
IGCSE Physics
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
A-Level Physics Numericals / Questions
A-Level Physics Question 121. A concave mirror has R = 40 cm. Find f.
A-Level Physics
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
A-Level Physics Question 122. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
A-Level Physics
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
A-Level Physics Question 123. A convex mirror has f = 20 cm and object at 30 cm. Find v.
A-Level Physics
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
A-Level Physics Question 124. Find magnification if u=-40 cm and v=-20 cm.
A-Level Physics
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
A-Level Physics Question 125. A mirror forms image twice the size and erect. What type of mirror?
A-Level Physics
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
A-Level Physics Question 126. A concave mirror has R = 40 cm. Find f.
A-Level Physics
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
A-Level Physics Question 127. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
A-Level Physics
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
A-Level Physics Question 128. A convex mirror has f = 20 cm and object at 30 cm. Find v.
A-Level Physics
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
A-Level Physics Question 129. Find magnification if u=-40 cm and v=-20 cm.
A-Level Physics
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
A-Level Physics Question 130. A mirror forms image twice the size and erect. What type of mirror?
A-Level Physics
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
A-Level Physics Question 131. A concave mirror has R = 40 cm. Find f.
A-Level Physics
Given: R=40 cm
Formula:
f=R/2
f=40/2=20 cm. For concave mirror, f=-20 cm by Cartesian convention.
Final result follows from sign convention.
Final Answer: -20 cm
A-Level Physics Question 132. Object is 30 cm in front of concave mirror of f = 15 cm. Find image distance.
A-Level Physics
Given: u=-30 cm, f=-15 cm
Formula:
1/f=1/v+1/u
1/(-15)=1/v+1/(-30); 1/v=-1/15+1/30=-1/30, v=-30 cm
Final result follows from sign convention.
Final Answer: -30 cm
A-Level Physics Question 133. A convex mirror has f = 20 cm and object at 30 cm. Find v.
A-Level Physics
Given: f=+20 cm, u=-30 cm
Formula:
1/f=1/v+1/u
1/20=1/v-1/30; 1/v=1/20+1/30=5/60=1/12, v=12 cm
Final result follows from sign convention.
Final Answer: +12 cm
A-Level Physics Question 134. Find magnification if u=-40 cm and v=-20 cm.
A-Level Physics
Given: u=-40 cm, v=-20 cm
Formula:
m=-v/u
m=-(-20)/(-40)=-0.5
Final result follows from sign convention.
Final Answer: -0.5
A-Level Physics Question 135. A mirror forms image twice the size and erect. What type of mirror?
A-Level Physics
Given: m=+2
Formula:
Erect enlarged image by mirror
Only concave mirror with object between F and P gives erect enlarged virtual image.
Final result follows from sign convention.
Final Answer: Concave mirror
PYQ-style Sections
CBSE PYQs
CBSE PYQs 1. State mirror formula.
CBSE PYQs
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
CBSE PYQs 2. Define pole of spherical mirror.
CBSE PYQs
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
CBSE PYQs 3. What is focus of concave mirror?
CBSE PYQs
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
CBSE PYQs 4. Why convex mirror is used as rear-view mirror?
CBSE PYQs
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
CBSE PYQs 5. What is relation between f and R?
CBSE PYQs
f=R/2.
Answer: f=R/2.
CBSE PYQs 6. State magnification formula.
CBSE PYQs
m=-v/u=h′/h.
Answer: m=-v/u=h′/h.
CBSE PYQs 7. Name mirror used in solar cooker.
CBSE PYQs
Concave mirror.
Answer: Concave mirror.
CBSE PYQs 8. What image does convex mirror form?
CBSE PYQs
Virtual, erect and diminished.
Answer: Virtual, erect and diminished.
CBSE PYQs 9. When does concave mirror form virtual image?
CBSE PYQs
When object is between F and P.
Answer: When object is between F and P.
CBSE PYQs 10. What is centre of curvature?
CBSE PYQs
Centre of sphere of which mirror is a part.
Answer: Centre of sphere of which mirror is a part.
CBSE PYQs 11. State mirror formula.
CBSE PYQs
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
CBSE PYQs 12. Define pole of spherical mirror.
CBSE PYQs
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
CBSE PYQs 13. What is focus of concave mirror?
CBSE PYQs
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
CBSE PYQs 14. Why convex mirror is used as rear-view mirror?
CBSE PYQs
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
CBSE PYQs 15. What is relation between f and R?
CBSE PYQs
f=R/2.
Answer: f=R/2.
NEET PYQs
NEET PYQs 1. State mirror formula.
NEET PYQs
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
NEET PYQs 2. Define pole of spherical mirror.
NEET PYQs
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
NEET PYQs 3. What is focus of concave mirror?
NEET PYQs
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
NEET PYQs 4. Why convex mirror is used as rear-view mirror?
NEET PYQs
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
NEET PYQs 5. What is relation between f and R?
NEET PYQs
f=R/2.
Answer: f=R/2.
NEET PYQs 6. State magnification formula.
NEET PYQs
m=-v/u=h′/h.
Answer: m=-v/u=h′/h.
NEET PYQs 7. Name mirror used in solar cooker.
NEET PYQs
Concave mirror.
Answer: Concave mirror.
NEET PYQs 8. What image does convex mirror form?
NEET PYQs
Virtual, erect and diminished.
Answer: Virtual, erect and diminished.
NEET PYQs 9. When does concave mirror form virtual image?
NEET PYQs
When object is between F and P.
Answer: When object is between F and P.
NEET PYQs 10. What is centre of curvature?
NEET PYQs
Centre of sphere of which mirror is a part.
Answer: Centre of sphere of which mirror is a part.
NEET PYQs 11. State mirror formula.
NEET PYQs
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
NEET PYQs 12. Define pole of spherical mirror.
NEET PYQs
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
NEET PYQs 13. What is focus of concave mirror?
NEET PYQs
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
NEET PYQs 14. Why convex mirror is used as rear-view mirror?
NEET PYQs
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
NEET PYQs 15. What is relation between f and R?
NEET PYQs
f=R/2.
Answer: f=R/2.
JEE Main PYQs
JEE Main PYQs 1. State mirror formula.
JEE Main PYQs
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
JEE Main PYQs 2. Define pole of spherical mirror.
JEE Main PYQs
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
JEE Main PYQs 3. What is focus of concave mirror?
JEE Main PYQs
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
JEE Main PYQs 4. Why convex mirror is used as rear-view mirror?
JEE Main PYQs
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
JEE Main PYQs 5. What is relation between f and R?
JEE Main PYQs
f=R/2.
Answer: f=R/2.
JEE Main PYQs 6. State magnification formula.
JEE Main PYQs
m=-v/u=h′/h.
Answer: m=-v/u=h′/h.
JEE Main PYQs 7. Name mirror used in solar cooker.
JEE Main PYQs
Concave mirror.
Answer: Concave mirror.
JEE Main PYQs 8. What image does convex mirror form?
JEE Main PYQs
Virtual, erect and diminished.
Answer: Virtual, erect and diminished.
JEE Main PYQs 9. When does concave mirror form virtual image?
JEE Main PYQs
When object is between F and P.
Answer: When object is between F and P.
JEE Main PYQs 10. What is centre of curvature?
JEE Main PYQs
Centre of sphere of which mirror is a part.
Answer: Centre of sphere of which mirror is a part.
JEE Main PYQs 11. State mirror formula.
JEE Main PYQs
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
JEE Main PYQs 12. Define pole of spherical mirror.
JEE Main PYQs
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
JEE Main PYQs 13. What is focus of concave mirror?
JEE Main PYQs
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
JEE Main PYQs 14. Why convex mirror is used as rear-view mirror?
JEE Main PYQs
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
JEE Main PYQs 15. What is relation between f and R?
JEE Main PYQs
f=R/2.
Answer: f=R/2.
JEE Advanced PYQs
JEE Advanced PYQs 1. State mirror formula.
JEE Advanced PYQs
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
JEE Advanced PYQs 2. Define pole of spherical mirror.
JEE Advanced PYQs
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
JEE Advanced PYQs 3. What is focus of concave mirror?
JEE Advanced PYQs
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
JEE Advanced PYQs 4. Why convex mirror is used as rear-view mirror?
JEE Advanced PYQs
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
JEE Advanced PYQs 5. What is relation between f and R?
JEE Advanced PYQs
f=R/2.
Answer: f=R/2.
JEE Advanced PYQs 6. State magnification formula.
JEE Advanced PYQs
m=-v/u=h′/h.
Answer: m=-v/u=h′/h.
JEE Advanced PYQs 7. Name mirror used in solar cooker.
JEE Advanced PYQs
Concave mirror.
Answer: Concave mirror.
JEE Advanced PYQs 8. What image does convex mirror form?
JEE Advanced PYQs
Virtual, erect and diminished.
Answer: Virtual, erect and diminished.
JEE Advanced PYQs 9. When does concave mirror form virtual image?
JEE Advanced PYQs
When object is between F and P.
Answer: When object is between F and P.
JEE Advanced PYQs 10. What is centre of curvature?
JEE Advanced PYQs
Centre of sphere of which mirror is a part.
Answer: Centre of sphere of which mirror is a part.
JEE Advanced PYQs 11. State mirror formula.
JEE Advanced PYQs
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
JEE Advanced PYQs 12. Define pole of spherical mirror.
JEE Advanced PYQs
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
JEE Advanced PYQs 13. What is focus of concave mirror?
JEE Advanced PYQs
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
JEE Advanced PYQs 14. Why convex mirror is used as rear-view mirror?
JEE Advanced PYQs
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
JEE Advanced PYQs 15. What is relation between f and R?
JEE Advanced PYQs
f=R/2.
Answer: f=R/2.
JEE Advanced PYQs 16. State magnification formula.
JEE Advanced PYQs
m=-v/u=h′/h.
Answer: m=-v/u=h′/h.
JEE Advanced PYQs 17. Name mirror used in solar cooker.
JEE Advanced PYQs
Concave mirror.
Answer: Concave mirror.
JEE Advanced PYQs 18. What image does convex mirror form?
JEE Advanced PYQs
Virtual, erect and diminished.
Answer: Virtual, erect and diminished.
JEE Advanced PYQs 19. When does concave mirror form virtual image?
JEE Advanced PYQs
When object is between F and P.
Answer: When object is between F and P.
JEE Advanced PYQs 20. What is centre of curvature?
JEE Advanced PYQs
Centre of sphere of which mirror is a part.
Answer: Centre of sphere of which mirror is a part.
IB Physics Questions
IB Physics Questions 1. State mirror formula.
IB Physics Questions
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
IB Physics Questions 2. Define pole of spherical mirror.
IB Physics Questions
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
IB Physics Questions 3. What is focus of concave mirror?
IB Physics Questions
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
IB Physics Questions 4. Why convex mirror is used as rear-view mirror?
IB Physics Questions
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
IB Physics Questions 5. What is relation between f and R?
IB Physics Questions
f=R/2.
Answer: f=R/2.
IB Physics Questions 6. State magnification formula.
IB Physics Questions
m=-v/u=h′/h.
Answer: m=-v/u=h′/h.
IB Physics Questions 7. Name mirror used in solar cooker.
IB Physics Questions
Concave mirror.
Answer: Concave mirror.
IB Physics Questions 8. What image does convex mirror form?
IB Physics Questions
Virtual, erect and diminished.
Answer: Virtual, erect and diminished.
IB Physics Questions 9. When does concave mirror form virtual image?
IB Physics Questions
When object is between F and P.
Answer: When object is between F and P.
IB Physics Questions 10. What is centre of curvature?
IB Physics Questions
Centre of sphere of which mirror is a part.
Answer: Centre of sphere of which mirror is a part.
IB Physics Questions 11. State mirror formula.
IB Physics Questions
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
IB Physics Questions 12. Define pole of spherical mirror.
IB Physics Questions
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
IB Physics Questions 13. What is focus of concave mirror?
IB Physics Questions
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
IB Physics Questions 14. Why convex mirror is used as rear-view mirror?
IB Physics Questions
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
IB Physics Questions 15. What is relation between f and R?
IB Physics Questions
f=R/2.
Answer: f=R/2.
ICSE / ISC Questions
ICSE / ISC Questions 1. State mirror formula.
ICSE / ISC Questions
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
ICSE / ISC Questions 2. Define pole of spherical mirror.
ICSE / ISC Questions
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
ICSE / ISC Questions 3. What is focus of concave mirror?
ICSE / ISC Questions
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
ICSE / ISC Questions 4. Why convex mirror is used as rear-view mirror?
ICSE / ISC Questions
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
ICSE / ISC Questions 5. What is relation between f and R?
ICSE / ISC Questions
f=R/2.
Answer: f=R/2.
ICSE / ISC Questions 6. State magnification formula.
ICSE / ISC Questions
m=-v/u=h′/h.
Answer: m=-v/u=h′/h.
ICSE / ISC Questions 7. Name mirror used in solar cooker.
ICSE / ISC Questions
Concave mirror.
Answer: Concave mirror.
ICSE / ISC Questions 8. What image does convex mirror form?
ICSE / ISC Questions
Virtual, erect and diminished.
Answer: Virtual, erect and diminished.
ICSE / ISC Questions 9. When does concave mirror form virtual image?
ICSE / ISC Questions
When object is between F and P.
Answer: When object is between F and P.
ICSE / ISC Questions 10. What is centre of curvature?
ICSE / ISC Questions
Centre of sphere of which mirror is a part.
Answer: Centre of sphere of which mirror is a part.
ICSE / ISC Questions 11. State mirror formula.
ICSE / ISC Questions
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
ICSE / ISC Questions 12. Define pole of spherical mirror.
ICSE / ISC Questions
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
ICSE / ISC Questions 13. What is focus of concave mirror?
ICSE / ISC Questions
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
ICSE / ISC Questions 14. Why convex mirror is used as rear-view mirror?
ICSE / ISC Questions
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
ICSE / ISC Questions 15. What is relation between f and R?
ICSE / ISC Questions
f=R/2.
Answer: f=R/2.
IGCSE Questions
IGCSE Questions 1. State mirror formula.
IGCSE Questions
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
IGCSE Questions 2. Define pole of spherical mirror.
IGCSE Questions
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
IGCSE Questions 3. What is focus of concave mirror?
IGCSE Questions
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
IGCSE Questions 4. Why convex mirror is used as rear-view mirror?
IGCSE Questions
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
IGCSE Questions 5. What is relation between f and R?
IGCSE Questions
f=R/2.
Answer: f=R/2.
IGCSE Questions 6. State magnification formula.
IGCSE Questions
m=-v/u=h′/h.
Answer: m=-v/u=h′/h.
IGCSE Questions 7. Name mirror used in solar cooker.
IGCSE Questions
Concave mirror.
Answer: Concave mirror.
IGCSE Questions 8. What image does convex mirror form?
IGCSE Questions
Virtual, erect and diminished.
Answer: Virtual, erect and diminished.
IGCSE Questions 9. When does concave mirror form virtual image?
IGCSE Questions
When object is between F and P.
Answer: When object is between F and P.
IGCSE Questions 10. What is centre of curvature?
IGCSE Questions
Centre of sphere of which mirror is a part.
Answer: Centre of sphere of which mirror is a part.
IGCSE Questions 11. State mirror formula.
IGCSE Questions
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
IGCSE Questions 12. Define pole of spherical mirror.
IGCSE Questions
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
IGCSE Questions 13. What is focus of concave mirror?
IGCSE Questions
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
IGCSE Questions 14. Why convex mirror is used as rear-view mirror?
IGCSE Questions
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
IGCSE Questions 15. What is relation between f and R?
IGCSE Questions
f=R/2.
Answer: f=R/2.
A-Level Questions
A-Level Questions 1. State mirror formula.
A-Level Questions
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
A-Level Questions 2. Define pole of spherical mirror.
A-Level Questions
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
A-Level Questions 3. What is focus of concave mirror?
A-Level Questions
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
A-Level Questions 4. Why convex mirror is used as rear-view mirror?
A-Level Questions
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
A-Level Questions 5. What is relation between f and R?
A-Level Questions
f=R/2.
Answer: f=R/2.
A-Level Questions 6. State magnification formula.
A-Level Questions
m=-v/u=h′/h.
Answer: m=-v/u=h′/h.
A-Level Questions 7. Name mirror used in solar cooker.
A-Level Questions
Concave mirror.
Answer: Concave mirror.
A-Level Questions 8. What image does convex mirror form?
A-Level Questions
Virtual, erect and diminished.
Answer: Virtual, erect and diminished.
A-Level Questions 9. When does concave mirror form virtual image?
A-Level Questions
When object is between F and P.
Answer: When object is between F and P.
A-Level Questions 10. What is centre of curvature?
A-Level Questions
Centre of sphere of which mirror is a part.
Answer: Centre of sphere of which mirror is a part.
A-Level Questions 11. State mirror formula.
A-Level Questions
1/f = 1/v + 1/u.
Answer: 1/f = 1/v + 1/u.
A-Level Questions 12. Define pole of spherical mirror.
A-Level Questions
The geometrical centre of reflecting surface is pole P.
Answer: The geometrical centre of reflecting surface is pole P.
A-Level Questions 13. What is focus of concave mirror?
A-Level Questions
Point where rays parallel to principal axis meet after reflection.
Answer: Point where rays parallel to principal axis meet after reflection.
A-Level Questions 14. Why convex mirror is used as rear-view mirror?
A-Level Questions
It gives wide field of view and erect diminished image.
Answer: It gives wide field of view and erect diminished image.
A-Level Questions 15. What is relation between f and R?
A-Level Questions
f=R/2.
Answer: f=R/2.
Case Studies
Case Study 1: Dentist mirror
Passage: Dentist mirror uses spherical mirror properties. The selected mirror depends on whether a magnified image, parallel beam, concentrated heat or wide field of view is required.
Representative spherical mirror diagram for Dentist mirror.
Case 1.1. Explain physics point 1 for Dentist mirror.
Case Study
Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 1.2. Explain physics point 2 for Dentist mirror.
Case Study
Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 1.3. Explain physics point 3 for Dentist mirror.
Case Study
Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 1.4. Explain physics point 4 for Dentist mirror.
Case Study
Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 1.5. Explain physics point 5 for Dentist mirror.
Case Study
Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Dentist mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case Study 2: Shaving mirror
Passage: Shaving mirror uses spherical mirror properties. The selected mirror depends on whether a magnified image, parallel beam, concentrated heat or wide field of view is required.
Representative spherical mirror diagram for Shaving mirror.
Case 2.1. Explain physics point 1 for Shaving mirror.
Case Study
Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 2.2. Explain physics point 2 for Shaving mirror.
Case Study
Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 2.3. Explain physics point 3 for Shaving mirror.
Case Study
Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 2.4. Explain physics point 4 for Shaving mirror.
Case Study
Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 2.5. Explain physics point 5 for Shaving mirror.
Case Study
Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Shaving mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case Study 3: Vehicle rear-view mirror
Passage: Vehicle rear-view mirror uses spherical mirror properties. The selected mirror depends on whether a magnified image, parallel beam, concentrated heat or wide field of view is required.
Representative spherical mirror diagram for Vehicle rear-view mirror.
Case 3.1. Explain physics point 1 for Vehicle rear-view mirror.
Case Study
Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 3.2. Explain physics point 2 for Vehicle rear-view mirror.
Case Study
Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 3.3. Explain physics point 3 for Vehicle rear-view mirror.
Case Study
Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 3.4. Explain physics point 4 for Vehicle rear-view mirror.
Case Study
Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 3.5. Explain physics point 5 for Vehicle rear-view mirror.
Case Study
Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Vehicle rear-view mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case Study 4: Solar cooker
Passage: Solar cooker uses spherical mirror properties. The selected mirror depends on whether a magnified image, parallel beam, concentrated heat or wide field of view is required.
Representative spherical mirror diagram for Solar cooker.
Case 4.1. Explain physics point 1 for Solar cooker.
Case Study
Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 4.2. Explain physics point 2 for Solar cooker.
Case Study
Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 4.3. Explain physics point 3 for Solar cooker.
Case Study
Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 4.4. Explain physics point 4 for Solar cooker.
Case Study
Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 4.5. Explain physics point 5 for Solar cooker.
Case Study
Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Solar cooker is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case Study 5: Torch reflector
Passage: Torch reflector uses spherical mirror properties. The selected mirror depends on whether a magnified image, parallel beam, concentrated heat or wide field of view is required.
Representative spherical mirror diagram for Torch reflector.
Case 5.1. Explain physics point 1 for Torch reflector.
Case Study
Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 5.2. Explain physics point 2 for Torch reflector.
Case Study
Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 5.3. Explain physics point 3 for Torch reflector.
Case Study
Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 5.4. Explain physics point 4 for Torch reflector.
Case Study
Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 5.5. Explain physics point 5 for Torch reflector.
Case Study
Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Torch reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case Study 6: Security mirror
Passage: Security mirror uses spherical mirror properties. The selected mirror depends on whether a magnified image, parallel beam, concentrated heat or wide field of view is required.
Representative spherical mirror diagram for Security mirror.
Case 6.1. Explain physics point 1 for Security mirror.
Case Study
Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 6.2. Explain physics point 2 for Security mirror.
Case Study
Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 6.3. Explain physics point 3 for Security mirror.
Case Study
Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 6.4. Explain physics point 4 for Security mirror.
Case Study
Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 6.5. Explain physics point 5 for Security mirror.
Case Study
Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Security mirror is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case Study 7: Headlight reflector
Passage: Headlight reflector uses spherical mirror properties. The selected mirror depends on whether a magnified image, parallel beam, concentrated heat or wide field of view is required.
Representative spherical mirror diagram for Headlight reflector.
Case 7.1. Explain physics point 1 for Headlight reflector.
Case Study
Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 7.2. Explain physics point 2 for Headlight reflector.
Case Study
Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 7.3. Explain physics point 3 for Headlight reflector.
Case Study
Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 7.4. Explain physics point 4 for Headlight reflector.
Case Study
Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Case 7.5. Explain physics point 5 for Headlight reflector.
Case Study
Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Answer: Headlight reflector is explained using concave or convex mirror behaviour, focus, image formation and the mirror formula when numerical data is given.
Need Help in Spherical Mirrors?
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