Magnetism and Matter Important Questions
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Magnetism and Matter Important Questions

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1. Introduction to Magnetism and Matter

Magnetism and Matter studies bar magnets, magnetic dipoles, magnetic field intensity, axial and equatorial fields, torque on magnetic dipoles, potential energy, earth magnetism, magnetisation and the magnetic behaviour of materials. For examinations, students must connect formulas with correct physical meaning and units.

Bar Magnet

A bar magnet behaves as a magnetic dipole having north and south poles separated by magnetic length 2l.

Magnetic Moment

Magnetic moment measures strength and orientation of a magnetic dipole.

Magnetic Materials

Diamagnetic, paramagnetic and ferromagnetic materials are classified through susceptibility and permeability.

2. Very Important Theory Points

Current loop magnetic momentM = NIA
Bar magnet momentM = m × 2l
Torque on dipoleτ = MB sinθ
Potential energyU = −MB cosθ
Axial field of short dipoleB = (μ₀/4π)(2M/r³)
Equatorial field of short dipoleB = (μ₀/4π)(M/r³)

A current carrying loop behaves like a magnetic dipole. One face behaves like a north pole and the other face behaves like a south pole. The direction of magnetic moment is given by the right hand thumb rule.

Magnetic moment of a current loop
M = NIA current current Right hand thumb rule gives direction of magnetic moment.
Bar magnet as magnetic dipole
N S M = m × 2l pole strength m magnetic length 2l

3. Questions Extracted From Uploaded Book Pages

All clearly visible questions from the uploaded pages are solved below. One visibly cropped question is included with a note that the remaining data is not visible.

Type A - Q1Force between unequal magnetic poles

Question: The force between two magnetic poles in air is 9.604 mN. If one pole is 10 times stronger than the other, calculate the pole strength of each. Given distance between two poles = 10 cm.

Given Data: F = 9.604 × 10⁻³ N, r = 0.10 m, stronger pole = 10m.

Formula UsedF = (μ₀/4π)(m₁m₂/r²)
Step-by-step Solution:

Let the weaker pole strength be m. The stronger pole is 10m.

F = 10⁻⁷ × (10m²)/(0.10)² = 10⁻⁴m².

9.604 × 10⁻³ = 10⁻⁴m², so m² = 96.04 and m = 9.8 A m.

Stronger pole = 10m = 98 A m.

Final Answer: 9.8 A m and 98 A m.
Type A - Q2Distance changed for equal poles

Question: Two equal magnetic poles placed 5 cm apart in air attract eachother with a force of 14.4×10⁻⁴ N. How far from eachother should they be held so that the force of attraction becomes 1.6 × 10⁻⁴ N ?

Given Data: F₁ = 14.4 × 10⁻⁴ N, r₁ = 5 cm, F₂ = 1.6 × 10⁻⁴ N.

Formula UsedF ∝ 1/r²
Step-by-step Solution:

For same poles, F₁/F₂ = r₂²/r₁².

14.4/1.6 = r₂²/(5 cm)² = 9.

r₂ = 3 × 5 cm = 15 cm = 0.15 m.

Final Answer: 0.15 m.
Type A - Q3Two magnets in a vertical glass tube

Question: Two identical magnets with a length 10 cm and weight 50 gf each are arranged freely with their like poles facing in a vertical glass tube. The upper magnet hangs in air above the lower one so that the distance between the nearest poles of the magnets is 3 mm. Determine the pole strength of the poles of these magnets.

Given Data: Magnetic length = 10 cm, weight = 50 gf = 0.49 N, nearest pole separation = 3 mm.

Formula UsedNet magnetic repulsion = weight; use the four-pole force correction.
Step-by-step Solution:

The upper magnet is supported by magnetic repulsion. Because both magnets have finite length, all four pole interactions contribute.

Using the standard finite-magnet correction, W = (μ₀m²/4π)[1/d² + 1/(d+2l)² − 2/(d+l)²].

Substituting W = 0.49 N, d = 0.003 m and 2l = 0.10 m gives m ≈ 6.64 A m.

Final Answer: 6.64 A m.
Type A - Q4Pole strength from magnetic moment

Question: A bar magnet of magnetic moment 5 Am² has poles 0.20 m apart. Calculate the pole strength.

Given Data: M = 5 A m², pole separation = 2l = 0.20 m.

Formula UsedM = m × 2l
Step-by-step Solution:

m = M/(2l) = 5/0.20 = 25 A m.

Final Answer: 25 A m.
Type A - Q5Semicircular magnet

Question: A steel wire of length l has a magnetic moment M. It is then bent into a semicircular arc. What is the new magnetic moment ?

Given Data: Original length = l, original moment = M, semicircular arc length = l.

Formula UsedM = m × magnetic length
Step-by-step Solution:

Original pole strength m = M/l.

For a semicircle, arc length l = πR, so diameter = 2R = 2l/π.

New moment M' = m × diameter = (M/l)(2l/π).

Final Answer: 2M/π.
Type B - Q6Equatorial field of a bar magnet

Question: Calculate the magnetic induction at a point 4 cm from the centre and along the equator of a bar magnet of length 6 cm and magnetic moment 0.26 A m².

Given Data: r = 0.04 m, magnetic length 2l = 0.06 m so l = 0.03 m, M = 0.26 A m².

Formula UsedB_eq = (μ₀/4π) M/(r² + l²)³ᐟ²
Step-by-step Solution:

For a finite bar magnet at an equatorial point, B = 10⁻⁷ M/(r² + l²)³ᐟ².

r² + l² = (0.04)² + (0.03)² = 0.0025.

(r²+l²)³ᐟ² = (0.0025)³ᐟ² = 1.25 × 10⁻⁴.

B = 10⁻⁷ × 0.26/(1.25 × 10⁻⁴) = 2.08 × 10⁻⁴ T.

Final Answer: 2.08 × 10⁻⁴ T.
Type B - Q7Magnetic moment from axial and equatorial fields

Question: The magnetic field at a point, 10 cm away from a magnetic dipole, is found to be 2.0 × 10⁻⁴ T. Find the magnetic moment of the dipole if the point is (a) in end-on position of the dipole and (b) in broadside-on position of the dipole.

Given Data: B = 2.0 × 10⁻⁴ T, r = 0.10 m.

Formula UsedB_axial = (μ₀/4π)(2M/r³), B_equatorial = (μ₀/4π)(M/r³)
Step-by-step Solution:

End-on: M = Br³/(2 × 10⁻⁷) = (2.0×10⁻⁴)(10⁻³)/(2×10⁻⁷) = 1.0 A m².

Broadside-on: M = Br³/(10⁻⁷) = (2.0×10⁻⁴)(10⁻³)/(10⁻⁷) = 2.0 A m².

Final Answer: (a) 1.0 A m², (b) 2.0 A m².
Type B - Q8Order of earth magnetic field

Question: The earth’s field, it is claimed, roughly approximates the field due to a dipole of magnetic moment 8 × 10²² J T⁻¹ located at its centre. Check the order of magnitude of this number in some way.

Given Data: M = 8 × 10²² A m², R = 6.4 × 10⁶ m.

Formula UsedAt magnetic equator, B = (μ₀/4π) M/R³
Step-by-step Solution:

B ≈ 10⁻⁷ × (8×10²²)/(6.4×10⁶)³.

(6.4×10⁶)³ ≈ 2.62×10²⁰.

B ≈ 3.1×10⁻⁵ T, which is the correct order for the earth's magnetic field.

Final Answer: Order is correct; B is about 10⁻⁵ T.
Type B - Q9Earth dipole moment from equatorial field

Question: The earth’s magnetic field at the equator is approximately 0.4 G. Estimate the earth’s dipole moment.

Given Data: B = 0.4 G = 4 × 10⁻⁵ T, R = 6.4 × 10⁶ m.

Formula UsedM = BR³/10⁻⁷
Step-by-step Solution:

M = (4×10⁻⁵)(6.4×10⁶)³/(10⁻⁷).

M ≈ 1.04 × 10²³ A m².

Final Answer: 1.04 × 10²³ A m².
Type B - Q10Field due to short bar magnet

Question: Calculate the magnetic field due to a bar magnet 2 cm long and having a pole strength of 100 Am at a point 10 cm from each pole.

Given Data: 2l = 0.02 m, m = 100 A m, distance from each pole = 0.10 m.

Formula UsedB = (μ₀/4π)(m × 2l)/d³
Step-by-step Solution:

The point is equidistant from both poles, so it is on the equatorial line.

M = m × 2l = 100 × 0.02 = 2 A m².

B = 10⁻⁷ × 2/(0.10)³ = 2 × 10⁻⁴ T.

Final Answer: 2 × 10⁻⁴ T.
Type B - Q11Field at geomagnetic poles

Question: The magnetic moment of the assumed dipole at the earth’s centre is 8.0 × 10²² A m². Calculate the magnetic field B at the geomagnetic poles of the earth. Radius of the earth is 6400 km.

Given Data: M = 8.0 × 10²² A m², R = 6.4 × 10⁶ m.

Formula UsedB_pole = (μ₀/4π)(2M/R³)
Step-by-step Solution:

B = 2×10⁻⁷×8.0×10²²/(6.4×10⁶)³.

B ≈ 6.0 × 10⁻⁵ T = 60 μT.

Final Answer: 60 μT.
Type B - Q12Earth dipole moment from equatorial field

Question: The magnetic field at a point on the magnetic equator is found to be 3.1 × 10⁻⁵ T. Taking the earth’s radius to be 6400 km, calculate the magnetic moment of the assumed dipole at the earth’s centre.

Given Data: B = 3.1 × 10⁻⁵ T, R = 6.4 × 10⁶ m.

Formula UsedM = BR³/10⁻⁷
Step-by-step Solution:

M = (3.1×10⁻⁵)(6.4×10⁶)³/(10⁻⁷).

M ≈ 8.1 × 10²² A m².

Final Answer: 8.1 × 10²² A m².
Type B - Q13Earth field at poles from equator value

Question: If the earth’s magnetic field has a magnitude 3.4 × 10⁻⁵ T at the magnetic equator of the earth, what would be its value at the earth’s geomagnetic poles ?

Given Data: B_equator = 3.4 × 10⁻⁵ T.

Formula UsedB_pole = 2B_equator
Step-by-step Solution:

For a dipole, axial field is twice the equatorial field at the same distance.

B_pole = 2 × 3.4×10⁻⁵ = 6.8 × 10⁻⁵ T.

Final Answer: 6.8 × 10⁻⁵ T.
Type C - Q14Magnet in two inclined magnetic fields

Question: A bar magnet is suspended in a region where it is acted upon by two magnetic fields inclined at an angle of 60° to each other. One of the fields has a magnitude of 1.2 × 10⁻² T. The magnet attains stable equilibrium at an angle of 15° with this field. Calculate the magnitude of other field. Ignore earth’s field.

Given Data: B₁ = 1.2 × 10⁻² T, angle between fields = 60°, magnet makes 15° with B₁.

Formula UsedFor resultant direction: B₂ sin(60°−15°) = B₁ sin15°
Step-by-step Solution:

B₂ = B₁ sin15°/sin45°.

B₂ = 1.2×10⁻² × 0.2588/0.7071 = 4.4 × 10⁻³ T.

Final Answer: 4.4 × 10⁻³ T.
Type C - Q15Two crossed magnets

Question: Two magnets of magnetic moments M and M√3 are joined to form a cross (+). The combination is suspended freely in a uniform magnetic field. In equilibrium position, the magnet of magnetic moment M makes an angle θ with the field. Determine θ.

Given Data: Moments are perpendicular: M and M√3.

Formula Usedtan θ = perpendicular component / reference component
Step-by-step Solution:

The resultant magnetic moment lies along the field in equilibrium.

tanθ = (M√3)/M = √3.

θ = 60°.

Final Answer: 60°.
Type C - Q16Torque on bar magnet

Question: Calculate the torque acting on a magnet of length 20 cm and of pole strength 2 × 10⁻⁵ Am, placed in earth’s magnetic field of flux density 2 × 10⁻⁵ T, when (a) magnet is ∥ to field (b) magnet is ⊥ to field.

Given Data: 2l = 0.20 m, m = 2 × 10⁻⁵ A m, B = 2 × 10⁻⁵ T.

Formula UsedM = m(2l), τ = MB sinθ
Step-by-step Solution:

M = 2×10⁻⁵ × 0.20 = 4×10⁻⁶ A m².

(a) θ = 0°, τ = 0.

(b) θ = 90°, τ = 4×10⁻⁶ × 2×10⁻⁵ = 0.8×10⁻¹⁰ N m.

Final Answer: (a) zero, (b) 0.8 × 10⁻¹⁰ N m.
Type D - Q17Work to rotate a circular coil

Question: A circular coil of 100 turns and having a radius of 0.05 m carries a current of 0.1 A. Calculate the work required to turn the coil in an external magnetic field of 1.5 T through 180° about an axis perpendicular to the magnetic field. The plane of the coil is initially at right angles to the magnetic field.

Given Data: N = 100, r = 0.05 m, I = 0.1 A, B = 1.5 T.

Formula UsedM = NIA, W = 2MB
Step-by-step Solution:

A = πr² = π(0.05)² = 7.854×10⁻³ m².

M = 100×0.1×7.854×10⁻³ = 0.07854 A m².

Initial plane is perpendicular to B, so magnetic moment is parallel to B. Rotating by 180° changes energy by 2MB.

W = 2×0.07854×1.5 = 0.236 J ≈ 0.24 J.

Final Answer: 0.24 J.
Type D - Q18Work done in rotating a coil

Question: A circular coil of 50 turns and diameter 8 cm carries a current of 2 ampere. How much work will be done in rotating the coil through 180°, when suspended in a uniform magnetic field of 0.1 Wb/m².

Given Data: N = 50, diameter = 8 cm so r = 0.04 m, I = 2 A, B = 0.1 T.

Formula UsedM = NIA, W = 2MB
Step-by-step Solution:

A = π(0.04)² = 5.027×10⁻³ m².

M = 50×2×5.027×10⁻³ = 0.5027 A m².

W = 2×0.5027×0.1 = 0.1005 J.

Final Answer: 0.1 J.
Type D - Q19Torque on solenoid

Question: A straight solenoid of length 50 cm has 1000 turns per metre and a mean cross-sectional area of 2 × 10⁻⁴ m². It is placed with its axis at 30°, with a uniform magnetic field of 0.32 T. Find the torque acting on the solenoid when a current of 2 ampere is passed through it.

Given Data: n = 1000 m⁻¹, L = 0.50 m, N = 500, A = 2×10⁻⁴ m², I = 2 A, B = 0.32 T, θ = 30°.

Formula UsedM = NIA, τ = MB sinθ
Step-by-step Solution:

N = nL = 1000×0.50 = 500 turns.

M = 500×2×2×10⁻⁴ = 0.20 A m².

τ = 0.20×0.32×sin30° = 0.032 N m.

Final Answer: 0.032 N m.
Type D - Q20Moment, equilibrium and potential energy

Question: A short bar magnet placed with its axis at 30° with a uniform external magnetic field of 0.16 T experiences a torque of magnitude 0.032 J. Estimate the magnetic moment of the magnet. If the bar were free to rotate, which orientations would correspond to its (i), stable and (ii), unstable equilibrium ? What is the potential energy of the magnet in the two cases ?

Given Data: B = 0.16 T, θ = 30°, τ = 0.032 N m.

Formula Usedτ = MB sinθ, U = −MB cosθ
Step-by-step Solution:

M = τ/(B sinθ) = 0.032/(0.16×0.5) = 0.4 A m².

Stable equilibrium: θ = 0°, U = −MB = −0.4×0.16 = −0.064 J.

Unstable equilibrium: θ = 180°, U = +MB = +0.064 J.

Final Answer: 0.4 A m²; stable θ = 0°, unstable θ = 180°; U = −0.064 J and +0.064 J.
Type D - Q21Magnetic moment of coil

Question: A circular coil of 300 turns and diameter 14 cm carries a current of 15 A. What is the magnitude of magnetic moment associated with the coil ?

Given Data: N = 300, diameter = 14 cm so r = 0.07 m, I = 15 A.

Formula UsedM = NIA = NIπr²
Step-by-step Solution:

A = π(0.07)² = 0.015394 m².

M = 300×15×0.015394 = 69.27 A m².

Final Answer: 69.3 J T⁻¹ or 69.3 A m².
Type D - Q22Earth as current loop

Question: The magnetic dipole moment of earth is 6.4 × 10²¹ A m². If we consider it to be due to a current loop wound around the magnetic equator of the earth, then what should be the magnitude of the current ? Take earth to be a sphere of radius 6400 km.

Given Data: M = 6.4×10²¹ A m², R = 6.4×10⁶ m.

Formula UsedM = IA = IπR²
Step-by-step Solution:

I = M/(πR²).

I = 6.4×10²¹/[π(6.4×10⁶)²] = 4.97×10⁷ A.

Final Answer: 5 × 10⁷ A.
Type D - Q23Revolving electron magnetic moment

Question: An electron in an atom revolves around the nucleus in an orbit of radius 0.53 Å. Calculate the equivalent magnetic moment, if the frequency of revolution of electron is 6.8 × 10⁹ MHz.

Given Data: r = 0.53 Å = 0.53×10⁻¹⁰ m, f = 6.8×10⁹ MHz = 6.8×10¹⁵ Hz, e = 1.6×10⁻¹⁹ C.

Formula UsedI = ef, M = IA = efπr²
Step-by-step Solution:

I = ef because one electronic charge crosses a point once per revolution.

M = efπr² = (1.6×10⁻¹⁹)(6.8×10¹⁵)π(0.53×10⁻¹⁰)².

M ≈ 9.6×10⁻²⁴ A m².

Final Answer: 9.6 × 10⁻²⁴ A m².
Type D - Q24Electron in orbit

Question: An electron in an atom revolves around the nucleus in an orbit of radius 0.5 Å. Calculate the equivalent magnetic moment if the frequency of revolution of electron is 10¹⁰ MHz.

Given Data: r = 0.5 Å = 0.5×10⁻¹⁰ m, f = 10¹⁰ MHz = 10¹⁶ Hz.

Formula UsedM = efπr²
Step-by-step Solution:

M = (1.6×10⁻¹⁹)(10¹⁶)π(0.5×10⁻¹⁰)².

M = 1.257×10⁻²³ A m².

Final Answer: 1.257 × 10⁻²³ A m².
Type A - Material Q1Rowland ring magnetic field

Question: A Rowland ring of mean radius 18 cm has 3500 turns of wire wound on a ferromagnetic core of relative permeability 800. What is the magnetic field in the core for a magnetising current of 1.2 amp. ?

Given Data: r = 0.18 m, N = 3500, μr = 800, I = 1.2 A.

Formula UsedB = μ₀μrNI/(2πr)
Step-by-step Solution:

B = (4π×10⁻⁷)(800)(3500)(1.2)/(2π×0.18).

B = 3.73 T.

Final Answer: 3.73 T.
Type A - Material Q2Intensity of magnetisation from cgs moment

Question: A magnet weighs 75 gm and its magnetic moment is 2000 c.g.s. units. If the density of material is 7.5 g/cc, calculate the intensity of magnetisation.

Given Data: Mass = 75 g, density = 7.5 g/cc, magnetic moment = 2000 cgs units.

Formula UsedI = magnetic moment / volume
Step-by-step Solution:

Volume = mass/density = 75/7.5 = 10 cc.

Intensity of magnetisation = 2000/10 = 200 cgs units.

Final Answer: 200 c.g.s. units.
Type A - Material Q3Flux density in iron ring

Question: Calculate magnetic flux density in a ring of iron of mean radius 0.25 m on which 1500 turns of wire are wound uniformly. The current passed is 5 ampere. Take relative permeability of iron = 1600.

Given Data: r = 0.25 m, N = 1500, I = 5 A, μr = 1600.

Formula UsedB = μ₀μrNI/(2πr)
Step-by-step Solution:

B = (4π×10⁻⁷)(1600)(1500)(5)/(2π×0.25).

B = 9.6 T.

Final Answer: 9.6 T.
Type A - Material Q4Cropped iron rod question

Question: An iron rod of 0.2 cm² area of cross-section is subjected to a magnetising field of 1200 A m⁻¹.

Given Data: Only partial question is visible in the uploaded image.

Formula UsedAdditional data such as susceptibility, permeability or required quantity is needed.
Step-by-step Solution:

The image cuts off the remaining part of the question, so a unique numerical answer cannot be obtained from the visible data alone.

If susceptibility χ is given, then M = χH, B = μ₀(H+M), and magnetic moment = M × volume.

Final Answer: Question is visibly incomplete in the uploaded image.
Type A - Material Q5Magnetic intensity near a pole

Question: Calculate the magnetic field intensity at a distance of 20 cm. from a pole of strength 40 Am in air. Find the magnetic induction at the same point.

Given Data: m = 40 A m, r = 0.20 m.

Formula UsedH = m/(4πr²), B = μ₀H
Step-by-step Solution:

H = 40/[4π(0.20)²] = 79.54 A m⁻¹.

B = (4π×10⁻⁷)(79.54) = 1.0×10⁻⁴ T.

Final Answer: H = 79.54 A m⁻¹; B = 10⁻⁴ Wb/m².
Type A - Material Q6Relative permeability of toroid core

Question: A toroid has 2000 turns. The inner & outer radii of its core are 11 cm and 12 cm respectively. The magnetic field in the core for a current of 0.7 A is 2.5 T. What is relative permeability of core ?

Given Data: N = 2000, I = 0.7 A, B = 2.5 T, mean radius = 11.5 cm = 0.115 m.

Formula UsedB = μ₀μrNI/(2πr)
Step-by-step Solution:

μr = B(2πr)/(μ₀NI).

μr = 2.5×2π×0.115/[(4π×10⁻⁷)×2000×0.7].

μr = 1026.9.

Final Answer: 1026.9.
Type A - Material Q7Permeability from susceptibility

Question: The susceptibility of annealed iron at saturation is 5500. Find the permeability of annealed iron at saturation ?

Given Data: χ = 5500.

Formula Usedμ = μ₀μr = μ₀(1+χ)
Step-by-step Solution:

μ = 4π×10⁻⁷ × 5501.

μ = 6.9×10⁻³ T m A⁻¹.

Final Answer: 6.9 × 10⁻³ T m A⁻¹.
Type A - Material Q8Relative permeability and susceptibility

Question: The magnetic field B and the magnetic intensity H in a material are found to be 1.6 T and 1000 A/m respectively. Calculate the relative permeability μr and the susceptibility χ of material.

Given Data: B = 1.6 T, H = 1000 A m⁻¹.

Formula Usedμr = B/(μ₀H), χ = μr − 1
Step-by-step Solution:

μr = 1.6/[(4π×10⁻⁷)(1000)] = 1.27×10³ ≈ 1.3×10³.

χ = μr − 1 ≈ 1.3×10³ for a large value.

Final Answer: μr ≈ 1.3 × 10³; χ ≈ 1.3 × 10³.
Type A - Material Q9μ-metal permeability

Question: The maximum value of permeability of μ-metal (77% Ni, 16% Fe, 5% Cu, 2% Cr) is 0.126 T-m/A. Find the maximum relative permeability and susceptibility ?

Given Data: μ = 0.126 T m A⁻¹.

Formula Usedμr = μ/μ₀, χ = μr − 1
Step-by-step Solution:

μr = 0.126/(4π×10⁻⁷) ≈ 1.00×10⁵.

χ = μr − 1 ≈ 1.00×10⁵.

Final Answer: 1.00 × 10⁵ each.
Type B - Material Q10Curie law for aluminium

Question: For a magnetising field of intensity 2 × 10³ A m⁻¹ aluminium at 280 K acquires intensity of magnetisation of 4.8 × 10⁻² A m⁻¹. Find the susceptibility of aluminium at 280 K. If the temperature of the metal is raised to 320 K, what will be its susceptibility and intensity of magnetisation ?

Given Data: H = 2×10³ A m⁻¹, M₁ = 4.8×10⁻² A m⁻¹, T₁ = 280 K, T₂ = 320 K.

Formula Usedχ = M/H, Curie law: χT = constant
Step-by-step Solution:

χ₁ = M₁/H = 4.8×10⁻²/(2×10³) = 2.4×10⁻⁵.

χ₂ = χ₁T₁/T₂ = 2.4×10⁻⁵ × 280/320 = 2.1×10⁻⁵.

M₂ = χ₂H = 2.1×10⁻⁵ × 2×10³ = 4.2×10⁻² A m⁻¹.

Final Answer: 2.4 × 10⁻⁵; 2.1 × 10⁻⁵; 4.2 × 10⁻² A m⁻¹.
Type B - Material Q11Hysteresis loss per unit volume per cycle

Question: An iron sample having mass 8.4 kg is repeatedly taken over cycles of magnetisation and demagnetisation at a frequency of 50 cycles per second. It is found that energy of 3.2 × 10⁴ J is dissipated as heat in the sample in 30 minutes. If the density of iron is 7200 kg m⁻³, calculate the value of energy dissipated per unit volume per cycle in the iron sample.

Given Data: m = 8.4 kg, ρ = 7200 kg m⁻³, f = 50 s⁻¹, t = 30 min = 1800 s, E = 3.2×10⁴ J.

Formula UsedLoss per unit volume per cycle = E/(Vft)
Step-by-step Solution:

V = mass/density = 8.4/7200 = 1.1667×10⁻³ m³.

Total cycles = 50×1800 = 90000.

Loss = 3.2×10⁴/(1.1667×10⁻³ × 90000) = 304.8 J m⁻³ cycle⁻¹.

Final Answer: 304.8 J m⁻³ cycle⁻¹.
Type C - Material Q12Magnetic moment of iron rod in solenoid

Question: An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long solenoid wound with 5 turns/cm. If a current of 0.5 A is passed through the solenoid, find the magnetic moment of the rod.

Given Data: V = 10⁻⁴ m³, μr = 1000, n = 5 turns/cm = 500 m⁻¹, I = 0.5 A.

Formula UsedH = nI, χ = μr−1, M = χH, magnetic moment = M V
Step-by-step Solution:

H = 500×0.5 = 250 A m⁻¹.

χ = 1000 − 1 = 999.

M = χH = 999×250 = 249750 A m⁻¹.

Magnetic moment = MV = 249750×10⁻⁴ = 24.975 A m².

Final Answer: 25 A m².
Type C - Material Q13Bar magnet material quantities

Question: A bar magnet has pole strength 4.5 Am, magnetic length 12 cm and cross sectional area 0.9 cm². Find (a) intensity of magnetisation (I) (b) magnetic intensity (H) at the centre and (c) magnetic induction (B) at the centre of the magnet.

Given Data: m = 4.5 A m, 2l = 12 cm so l = 0.06 m, A = 0.9 cm² = 0.9×10⁻⁴ m².

Formula UsedI = m/A; H = (m/4π)(2/l²); B = μ₀(H+I)
Step-by-step Solution:

I = 4.5/(0.9×10⁻⁴) = 5×10⁴ A m⁻¹.

H = (4.5/4π)(2/0.06²) = 199 A m⁻¹.

B = 4π×10⁻⁷(5×10⁴ + 199) = 6.26×10⁻² T.

Final Answer: 5 × 10⁴ A m⁻¹; 199 A m⁻¹; 6.26 × 10⁻² T.

4. Magnetisation and Magnetic Properties of Materials

MagnetisationM = magnetic moment / volume
Magnetic susceptibilityχ = M/H
Relative permeabilityμr = 1 + χ
Magnetic permeabilityμ = μ₀μr
B-H-M relationB = μ₀(H + M)
Linear materialM = χH
Diamagnetic, paramagnetic and ferromagnetic response
DiamagneticParamagneticFerromagnetic χ < 0 small χ > 0 large χ > 0
MaterialSusceptibilityBehaviourExamples
DiamagneticSmall negativeWeakly repelled; induced M opposite to BBi, Cu, water
ParamagneticSmall positiveWeakly attracted; follows Curie lawAl, Pt, O₂
FerromagneticVery large positiveStrong domain alignmentFe, Co, Ni

5. Ferromagnetic Materials and Domain Theory

Ferromagnetic materials contain domains. In the unmagnetised state, domains are randomly oriented. In an external magnetic field, domains rotate and grow along the field direction, producing strong magnetisation.

Ferromagnetic domain theory
randompartial alignmentcomplete alignment

6. Hysteresis, Retentivity, Coercivity and Loss

Hysteresis is the lagging of B or M behind H during a complete magnetisation cycle. Retentivity is the residual magnetisation at H = 0. Coercivity is the reverse field required to reduce residual magnetisation to zero. The loop area gives energy loss per unit volume per cycle.

Physically correct hysteresis loop
HB or M +Bs-Bs +Br-Br -Hc+Hc saturationloop area = energy loss
RetentivityB or M remaining at H = 0
Coercivityreverse H required to make B or M zero
Hysteresis lossloss per unit volume per cycle = area of B-H loop

7. NEET Important Conceptual MCQs

These questions are exam-oriented and designed around the concepts repeatedly tested in board and competitive examinations.

NEET-C-1Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

NEET-C-2For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

NEET-C-3A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

NEET-C-4A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

NEET-C-5According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

NEET-C-6For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

NEET-C-7The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

NEET-C-8The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

NEET-C-9At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

NEET-C-10At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

NEET-C-11Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

NEET-C-12For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

NEET-C-13A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

NEET-C-14A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

NEET-C-15According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

NEET-C-16For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

NEET-C-17The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

NEET-C-18The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

NEET-C-19At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

NEET-C-20At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

NEET-C-21Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

NEET-C-22For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

NEET-C-23A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

NEET-C-24A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

NEET-C-25According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

NEET-C-26For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

NEET-C-27The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

NEET-C-28The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

NEET-C-29At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

NEET-C-30At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

NEET-C-31Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

NEET-C-32For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

NEET-C-33A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

NEET-C-34A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

NEET-C-35According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

NEET-C-36For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

NEET-C-37The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

NEET-C-38The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

NEET-C-39At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

NEET-C-40At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

NEET-C-41Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

NEET-C-42For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

NEET-C-43A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

NEET-C-44A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

NEET-C-45According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

NEET-C-46For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

NEET-C-47The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

NEET-C-48The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

NEET-C-49At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

NEET-C-50At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

8. NEET Numerical MCQs

These questions are exam-oriented and designed around the concepts repeatedly tested in board and competitive examinations.

NEET-N-1A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Medium

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

NEET-N-2A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Medium

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

NEET-N-3If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Medium

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

NEET-N-4If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Medium

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

NEET-N-5A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Medium

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

NEET-N-6For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Medium

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

NEET-N-7For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Medium

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

NEET-N-8If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

NEET-N-9If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Medium

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

NEET-N-10A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

NEET-N-11A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Medium

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

NEET-N-12A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Medium

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

NEET-N-13If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Medium

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

NEET-N-14If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Medium

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

NEET-N-15A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Medium

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

NEET-N-16For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Medium

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

NEET-N-17For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Medium

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

NEET-N-18If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

NEET-N-19If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Medium

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

NEET-N-20A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

NEET-N-21A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Medium

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

NEET-N-22A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Medium

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

NEET-N-23If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Medium

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

NEET-N-24If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Medium

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

NEET-N-25A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Medium

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

NEET-N-26For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Medium

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

NEET-N-27For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Medium

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

NEET-N-28If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

NEET-N-29If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Medium

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

NEET-N-30A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

NEET-N-31A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Medium

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

NEET-N-32A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Medium

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

NEET-N-33If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Medium

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

NEET-N-34If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Medium

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

NEET-N-35A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Medium

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

NEET-N-36For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Medium

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

NEET-N-37For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Medium

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

NEET-N-38If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

NEET-N-39If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Medium

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

NEET-N-40A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

NEET-N-41A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Medium

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

NEET-N-42A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Medium

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

NEET-N-43If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Medium

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

NEET-N-44If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Medium

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

NEET-N-45A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Medium

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

NEET-N-46For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Medium

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

NEET-N-47For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Medium

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

NEET-N-48If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

NEET-N-49If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Medium

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

NEET-N-50A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Medium

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

9. NEET Assertion and Case Based Practice

These questions are exam-oriented and designed around the concepts repeatedly tested in board and competitive examinations.

NEET-A-1Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

NEET-A-2For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

NEET-A-3A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

NEET-A-4A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

NEET-A-5According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

NEET-A-6For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

NEET-A-7The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

NEET-A-8The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

NEET-A-9At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

NEET-A-10At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

NEET-A-11A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

NEET-A-12A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

NEET-A-13If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

NEET-A-14If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

NEET-A-15A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

NEET-A-16For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

NEET-A-17For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

NEET-A-18If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

NEET-A-19If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

NEET-A-20A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

NEET-A-21Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

NEET-A-22For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

NEET-A-23A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

NEET-A-24A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

NEET-A-25According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

NEET-A-26For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

NEET-A-27The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

NEET-A-28The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

NEET-A-29At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

NEET-A-30At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

NEET-A-31A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

NEET-A-32A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

NEET-A-33If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

NEET-A-34If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

NEET-A-35A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

NEET-A-36For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

NEET-A-37For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

NEET-A-38If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

NEET-A-39If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

NEET-A-40A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

10. JEE Main Questions

These questions are exam-oriented and designed around the concepts repeatedly tested in board and competitive examinations.

JEE-M-1A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-M-2A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-M-3If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-M-4If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-M-5A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-M-6For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-M-7For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-M-8If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-M-9If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-M-10A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-M-11Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-M-12For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-M-13A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-M-14A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-M-15According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

JEE-M-16For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

JEE-M-17The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

JEE-M-18The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

JEE-M-19At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

JEE-M-20At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

JEE-M-21A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-M-22A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-M-23If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-M-24If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-M-25A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-M-26For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-M-27For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-M-28If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-M-29If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-M-30A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-M-31Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-M-32For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-M-33A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-M-34A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-M-35According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

JEE-M-36For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

JEE-M-37The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

JEE-M-38The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

JEE-M-39At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

JEE-M-40At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

JEE-M-41A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-M-42A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-M-43If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-M-44If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-M-45A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-M-46For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-M-47For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-M-48If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-M-49If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-M-50A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-M-51Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-M-52For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-M-53A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-M-54A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-M-55According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

JEE-M-56For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

JEE-M-57The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

JEE-M-58The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

JEE-M-59At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

JEE-M-60At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

JEE-M-61A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-M-62A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-M-63If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-M-64If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-M-65A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-M-66For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-M-67For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-M-68If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-M-69If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-M-70A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-M-71Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-M-72For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-M-73A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-M-74A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-M-75According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

JEE-M-76For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

JEE-M-77The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

JEE-M-78The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

JEE-M-79At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

JEE-M-80At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

JEE-M-81A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-M-82A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-M-83If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-M-84If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-M-85A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-M-86For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-M-87For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-M-88If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-M-89If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-M-90A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-M-91Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-M-92For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-M-93A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-M-94A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-M-95According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

11. JEE Advanced Questions

These questions are exam-oriented and designed around the concepts repeatedly tested in board and competitive examinations.

JEE-A-1A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Difficult

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-A-2A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Difficult

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-A-3If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Difficult

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-A-4If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Difficult

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-A-5A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Difficult

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-A-6For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Difficult

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-A-7For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Difficult

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-A-8If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-A-9If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Difficult

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-A-10A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-A-11Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Difficult

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-A-12For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Difficult

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-A-13A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Difficult

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-A-14A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Difficult

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-A-15According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Difficult

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

JEE-A-16For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Difficult

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

JEE-A-17The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Difficult

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

JEE-A-18The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Difficult

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

JEE-A-19At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Difficult

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

JEE-A-20At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Difficult

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

JEE-A-21A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Difficult

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-A-22A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Difficult

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-A-23If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Difficult

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-A-24If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Difficult

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-A-25A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Difficult

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-A-26For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Difficult

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-A-27For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Difficult

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-A-28If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-A-29If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Difficult

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-A-30A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-A-31Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Difficult

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-A-32For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Difficult

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-A-33A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Difficult

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-A-34A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Difficult

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-A-35According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Difficult

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

JEE-A-36For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Difficult

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

JEE-A-37The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Difficult

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

JEE-A-38The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Difficult

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

JEE-A-39At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Difficult

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

JEE-A-40At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Difficult

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

JEE-A-41A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Difficult

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-A-42A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Difficult

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-A-43If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Difficult

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-A-44If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Difficult

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-A-45A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Difficult

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-A-46For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Difficult

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-A-47For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Difficult

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-A-48If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-A-49If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Difficult

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-A-50A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-A-51Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Difficult

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-A-52For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Difficult

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-A-53A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Difficult

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-A-54A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Difficult

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-A-55According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Difficult

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

JEE-A-56For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Difficult

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

JEE-A-57The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Difficult

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

JEE-A-58The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Difficult

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

JEE-A-59At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Difficult

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

JEE-A-60At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Difficult

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

JEE-A-61A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Difficult

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-A-62A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Difficult

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-A-63If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Difficult

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-A-64If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Difficult

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-A-65A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Difficult

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-A-66For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Difficult

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-A-67For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Difficult

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-A-68If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-A-69If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Difficult

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-A-70A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-A-71Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Difficult

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-A-72For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Difficult

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-A-73A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Difficult

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-A-74A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Difficult

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-A-75According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Difficult

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

JEE-A-76For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Difficult

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

JEE-A-77The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Difficult

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

JEE-A-78The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Difficult

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

JEE-A-79At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Difficult

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

JEE-A-80At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Difficult

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

JEE-A-81A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Difficult

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-A-82A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Difficult

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-A-83If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Difficult

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-A-84If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Difficult

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-A-85A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Difficult

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

JEE-A-86For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Difficult

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

JEE-A-87For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Difficult

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

JEE-A-88If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

JEE-A-89If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Difficult

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

JEE-A-90A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Difficult

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

JEE-A-91Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Difficult

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

JEE-A-92For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Difficult

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

JEE-A-93A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Difficult

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

JEE-A-94A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Difficult

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

JEE-A-95According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Difficult

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

JEE-A-96For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Difficult

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

JEE-A-97The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Difficult

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

JEE-A-98The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Difficult

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

JEE-A-99At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Difficult

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

JEE-A-100At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Difficult

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

JEE-A-101A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Difficult

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

JEE-A-102A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Difficult

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

JEE-A-103If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Difficult

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

JEE-A-104If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Difficult

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

JEE-A-105A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Difficult

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

12. IB Physics Structured Questions

These questions are exam-oriented and designed around the concepts repeatedly tested in board and competitive examinations.

IB-1Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

IB-2For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

IB-3A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

IB-4A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

IB-5According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

IB-6For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

IB-7The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

IB-8The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

IB-9At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

IB-10At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

IB-11Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

IB-12For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

IB-13A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

IB-14A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

IB-15According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

IB-16For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

IB-17The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

IB-18The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

IB-19At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

IB-20At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

13. IGCSE / ICSE Questions

These questions are exam-oriented and designed around the concepts repeatedly tested in board and competitive examinations.

SCHOOL-1Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

SCHOOL-2For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

SCHOOL-3A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

SCHOOL-4A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

SCHOOL-5According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

SCHOOL-6For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

SCHOOL-7The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

SCHOOL-8The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

SCHOOL-9At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

SCHOOL-10At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

SCHOOL-11A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

SCHOOL-12A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

SCHOOL-13If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

SCHOOL-14If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

SCHOOL-15A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

SCHOOL-16For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

SCHOOL-17For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

SCHOOL-18If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

SCHOOL-19If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

SCHOOL-20A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

SCHOOL-21Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

SCHOOL-22For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

SCHOOL-23A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

SCHOOL-24A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

SCHOOL-25According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

SCHOOL-26For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

SCHOOL-27The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

SCHOOL-28The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

SCHOOL-29At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

SCHOOL-30At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

SCHOOL-31A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

SCHOOL-32A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

SCHOOL-33If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

SCHOOL-34If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

SCHOOL-35A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

SCHOOL-36For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

SCHOOL-37For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

SCHOOL-38If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

SCHOOL-39If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

SCHOOL-40A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

14. British Curriculum / A-Level Questions

These questions are exam-oriented and designed around the concepts repeatedly tested in board and competitive examinations.

AL-1A coil of 200 turns, area 4×10⁻³ m², carries 2 A. Its magnetic moment is
  1. A) 0.8 A m²
  2. B) 1.6 A m²
  3. C) 4 A m²
  4. D) 0.004 A m²

Difficulty: Exam Level

Correct Answer: B
Explanation:

M = NIA = 200×2×4×10⁻³ = 1.6 A m².

AL-2A bar magnet has moment 6 A m² and pole separation 0.30 m. Pole strength is
  1. A) 20 A m
  2. B) 1.8 A m
  3. C) 0.05 A m
  4. D) 18 A m

Difficulty: Exam Level

Correct Answer: A
Explanation:

m = M/(2l) = 6/0.30 = 20 A m.

AL-3If χ = 999, then relative permeability is
  1. A) 998
  2. B) 999
  3. C) 1000
  4. D) 1001

Difficulty: Exam Level

Correct Answer: C
Explanation:

μr = 1 + χ = 1000.

AL-4If μ = 4π×10⁻⁴ T m A⁻¹, then μr is approximately
  1. A) 100
  2. B) 1000
  3. C) 10⁴
  4. D) 10⁻³

Difficulty: Exam Level

Correct Answer: B
Explanation:

μr = μ/μ0 = 4π×10⁻⁴ / 4π×10⁻⁷ = 1000.

AL-5A paramagnetic sample has χ = 3×10⁻⁵ at 300 K. At 600 K, χ becomes
  1. A) 6×10⁻⁵
  2. B) 3×10⁻⁵
  3. C) 1.5×10⁻⁵
  4. D) 9×10⁻⁵

Difficulty: Exam Level

Correct Answer: C
Explanation:

By Curie law χ ∝ 1/T; doubling T halves χ.

AL-6For M = 0.5 A m² and B = 0.2 T, maximum torque is
  1. A) 0.01 N m
  2. B) 0.1 N m
  3. C) 0.25 N m
  4. D) 2.5 N m

Difficulty: Exam Level

Correct Answer: B
Explanation:

τmax = MB = 0.5×0.2 = 0.1 N m.

AL-7For a magnetic dipole M = 0.4 A m² in B = 0.16 T, energy difference between unstable and stable orientations is
  1. A) 0.064 J
  2. B) 0.128 J
  3. C) 0.032 J
  4. D) 0.4 J

Difficulty: Exam Level

Correct Answer: B
Explanation:

ΔU = (+MB) − (−MB) = 2MB = 2×0.4×0.16 = 0.128 J.

AL-8If H = 500 A/m and χ = 2000, magnetisation is
  1. A) 2.5 A/m
  2. B) 1000 A/m
  3. C) 10⁶ A/m
  4. D) 4 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

M = χH = 2000×500 = 10⁶ A/m.

AL-9If hysteresis energy loss is 900 J in volume 0.01 m³ over 300 cycles, loss per unit volume per cycle is
  1. A) 3 J/m³
  2. B) 30 J/m³
  3. C) 300 J/m³
  4. D) 2700 J/m³

Difficulty: Exam Level

Correct Answer: C
Explanation:

Loss = 900/(0.01×300)=300 J/m³/cycle.

AL-10A solenoid has n = 1000 m⁻¹ and I = 2 A. H inside is
  1. A) 500 A/m
  2. B) 1000 A/m
  3. C) 2000 A/m
  4. D) 4000 A/m

Difficulty: Exam Level

Correct Answer: C
Explanation:

H = nI = 1000×2 = 2000 A/m.

AL-11Which relation is correct for a linear magnetic material?
  1. A) M = χH
  2. B) M = χ/B
  3. C) B = H/μ
  4. D) χ = H/M

Difficulty: Exam Level

Correct Answer: A
Explanation:

Susceptibility is defined by χ = M/H, therefore M = χH.

AL-12For a diamagnetic substance, the susceptibility is
  1. A) small positive
  2. B) large positive
  3. C) small negative
  4. D) zero only

Difficulty: Exam Level

Correct Answer: C
Explanation:

Diamagnetic induced magnetisation is opposite to applied field, so χ is negative.

AL-13A permanent magnet should have
  1. A) high retentivity and high coercivity
  2. B) low retentivity and low coercivity
  3. C) high retentivity and low coercivity
  4. D) zero hysteresis area

Difficulty: Exam Level

Correct Answer: A
Explanation:

Permanent magnets should retain magnetisation and resist demagnetisation.

AL-14A transformer core should have
  1. A) wide hysteresis loop
  2. B) narrow hysteresis loop
  3. C) very high coercivity
  4. D) large eddy currents

Difficulty: Exam Level

Correct Answer: B
Explanation:

Narrow hysteresis loop reduces heat loss per cycle.

AL-15According to Curie law for paramagnetic materials
  1. A) χT = constant
  2. B) χ/T = constant
  3. C) χ is independent of T
  4. D) χ increases as T²

Difficulty: Exam Level

Correct Answer: A
Explanation:

Curie law gives χ = C/T, hence χT = C.

AL-16For a current loop, magnetic moment is
  1. A) NIA
  2. B) NI/A
  3. C) IA/N
  4. D) N/I A

Difficulty: Exam Level

Correct Answer: A
Explanation:

A coil of N turns carrying current I and area A has M = NIA.

AL-17The unit A m is the unit of
  1. A) magnetic moment
  2. B) pole strength
  3. C) magnetic field
  4. D) magnetic flux

Difficulty: Exam Level

Correct Answer: B
Explanation:

Pole strength has unit ampere metre; magnetic moment has unit A m².

AL-18The area of B-H loop gives
  1. A) retentivity
  2. B) coercivity
  3. C) energy loss per unit volume per cycle
  4. D) relative permeability

Difficulty: Exam Level

Correct Answer: C
Explanation:

Hysteresis loss per unit volume per cycle equals area of hysteresis loop.

AL-19At stable equilibrium of a magnetic dipole in field
  1. A) θ = 0°
  2. B) θ = 90°
  3. C) θ = 180°
  4. D) θ = 270°

Difficulty: Exam Level

Correct Answer: A
Explanation:

U = −MB cosθ is minimum at θ = 0°.

AL-20At unstable equilibrium of magnetic dipole
  1. A) U = −MB
  2. B) U = 0
  3. C) U = +MB
  4. D) torque is maximum

Difficulty: Exam Level

Correct Answer: C
Explanation:

At θ = 180°, U = +MB and torque is zero but equilibrium is unstable.

15. Common Exam Traps

Magnetic moment vs pole strength

Magnetic moment has unit A m², but pole strength has unit A m.

Wrong loop formula

For a current loop use M = NIA, not m × 2l.

Wrong susceptibility sign

Diamagnetic χ is negative; paramagnetic χ is positive but small.

Wrong hysteresis graph

Always show retentivity at H = 0, coercivity at B = 0, saturation and loop area.

Curie law mistake

For paramagnetic materials, χ is inversely proportional to absolute temperature.

Energy confusion

For magnetic dipole, U = −MB cosθ; stable means minimum potential energy.

16. Final Revision Sheet

Magnetic moment of loopM = NIA
Magnetic moment of bar magnetM = m × 2l
Torqueτ = MB sinθ
Potential energyU = −MB cosθ
Susceptibilityχ = M/H
Relative permeabilityμr = 1 + χ
Permeabilityμ = μ₀μr
Curie lawχ = C/T
Toroid fieldB = μ₀μrNI/(2πr)
Hysteresis lossloss/volume/cycle = area of B-H loop

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