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Current Electricity - Mobility of Charge Carriers

Complete formula sheet, derivations, concept explanations, diagrams and exam-focused practice for CBSE Class 12, NEET, JEE Main, JEE Advanced, Olympiad, AP Physics, IB Physics and A-Level Physics.

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1. Formula Sheet First

Mobility connects microscopic motion of charge carriers with the macroscopic current measured in a circuit.

μ = vd/EMobility definition
vd = μEDrift velocity in field
I = nAqvdCurrent through area A
J = nqvdCurrent density
J = nqμEUsing mobility
σ = nqμConductivity
ρ = 1/σResistivity
vd = eEτ/mDrude model
μ = eτ/mMobility from relaxation time
ρ = m/(ne²τ)Metal resistivity
σe = neeElectron contribution
σ = e(neμe + nhμh)Semiconductor conductivity

Symbols

μ: mobility
vd: drift velocity
E: electric field
n: carrier number density
A: area of cross-section
q: carrier charge
e: elementary charge
J: current density
σ: conductivity
ρ: resistivity
τ: relaxation time
m: mass/effective mass
ne: electron concentration
nh: hole concentration
μe: electron mobility
μh: hole mobility
Unit of mobility: m² V⁻¹ s⁻¹. Dimensional formula: [M⁻¹ T² A].

2. What Is Mobility of Charge Carriers?

Simple Definition

Mobility tells how easily a charge carrier can move through a material when an electric field is applied.

Formal Definition

Mobility is the drift velocity acquired by a charge carrier per unit electric field: μ = vd/E.

Physical Meaning

High mobility means carriers gain larger drift velocity for the same electric field because collisions are less restrictive.

Importance

Mobility controls current density, conductivity, semiconductor speed, device performance and temperature behaviour.

3. Derivation of Mobility

By definition, mobility is drift velocity per unit electric field: μ = vd/E.
For an electron in electric field E, the electric force magnitude is F = eE. The electron charge is negative, so its acceleration is opposite to E, but magnitude uses e.
Using Newton's second law, a = F/m = eE/m, where m is the effective mass in the material.
Between two successive collisions, the average time available for acceleration is relaxation time τ.
Therefore drift velocity magnitude becomes vd = aτ = eEτ/m.
Substitute this in mobility definition: μ = vd/E = (eEτ/m)/E.
Cancel E to obtain μ = eτ/m. Mobility increases with relaxation time and decreases with effective mass.

Collisions with lattice ions, impurities and phonons disturb the accelerated motion. A larger relaxation time means fewer collisions and hence larger mobility.

4. Mobility of Electrons

Electron mobility is μe = vd,e/E. Electrons are negatively charged, so their drift is opposite to the applied electric field. Conventional current is in the direction of positive charge flow, therefore it is opposite to electron drift.

Conductor: electron drift opposite to electric field Electric field E and conventional current I Electron drift velocity v_d,e eee

5. Mobility of Holes

A hole is the absence of an electron in a nearly filled valence band. It behaves like a positive charge carrier. Hole mobility is μh = vd,h/E. Holes drift in the direction of electric field and contribute to conventional current.

Electron: negative carrier, drift opposite to E, usually higher mobility.
Hole: effective positive carrier, drift along E, usually lower mobility due to band structure.
Hole motion in p-type semiconductor E, hole drift and conventional current hhh

6. Electron Mobility vs Hole Mobility

PointElectronHole
Charge carrierActual electronVacancy acting as positive carrier
Direction of motionOpposite to electric fieldAlong electric field
Charge-e+e
MobilityUsually greaterUsually smaller
Role in currentDominant in metals and n-type semiconductorsImportant in p-type semiconductors
MetalsPrimary carriersNot used in simple metal conduction
Intrinsic semiconductorContributes with holesContributes with electrons
Extrinsic semiconductorMajority in n-typeMajority in p-type
NEET/JEE importanceDirection, formula, conductivitySemiconductor conductivity and comparison

Electron mobility is usually greater because electrons often move in bands with smaller effective mass and less restrictive hopping compared with holes in the valence band.

7. Mobility in Metallic Conductors

Metals contain many free electrons moving among fixed lattice ions. In an electric field, electrons accelerate but repeatedly collide with ions, impurities and phonons. The average time between collisions is relaxation time τ.

Conductivity relation: J = ne vd and vd = μE, so J = neμE. Since J = σE, σ = neμ.

When temperature increases in metals, lattice vibrations increase, relaxation time decreases, mobility decreases, resistance increases and conductivity decreases.

8. Mobility in Semiconductors

In intrinsic semiconductors, electrons and holes are thermally generated in equal numbers. In n-type semiconductors, electrons are majority carriers. In p-type semiconductors, holes are majority carriers.

Electron current density contribution: Je = neeE.
Hole current density contribution: Jh = nhhE.
Total current density: J = Je + Jh.
Therefore J = e(neμe + nhμh)E.
Comparing with J = σE gives σ = e(neμe + nhμh).
n-typeMajority: electronsDonor impurity adds free e⁻e p-typeMajority: holesAcceptor impurity creates h⁺h

9. Temperature Effect on Mobility

MaterialTemperature Increase CausesFinal Effect
MetalsLattice vibrations increase, relaxation time decreases, mobility decreases.Resistance increases and conductivity decreases.
SemiconductorsMobility may decrease due to scattering, but carrier concentration increases strongly.Conductivity increases and resistance decreases in usual intrinsic behaviour.

10. Mobility, Conductivity and Resistivity

Start with J = nqvd.
Use vd = μE, so J = nqμE.
Compare with Ohm's microscopic form J = σE.
Therefore σ = nqμ and ρ = 1/(nqμ).

Example 1

If n = 8 × 10²⁸ m⁻³ and μ = 4 × 10⁻³ m²V⁻¹s⁻¹, then σ = neμ = 8×10²⁸ × 1.6×10⁻¹⁹ × 4×10⁻³ = 5.12×10⁷ S m⁻¹.

Example 2

If μ doubles while n remains constant, conductivity doubles and resistivity becomes half.

11. Mobility and Drift Velocity

The relation vd = μE means drift velocity is directly proportional to electric field for ohmic conditions. If voltage increases for fixed length, E = V/L increases and drift velocity increases. If length increases for fixed voltage, E decreases and drift velocity decreases. Area does not directly change vd for fixed E, but it changes current I = nAqvd. Temperature changes μ, so it indirectly changes vd.

12. Dimension and Unit of Mobility

μ = vd/E.
Unit of vd is m s⁻¹.
Unit of E is V m⁻¹.
So unit of μ = (m s⁻¹)/(V m⁻¹) = m² V⁻¹ s⁻¹.
Since V = kg m² s⁻³ A⁻¹, dimension of μ = m²/(V s) = M⁻¹ T² A.

18. Diagrams and Visuals

Mobility vs Electric FieldEvd Temperature Effectmetal μ decreasesTμ Current DirectionsI and Eelectron drift Carrier Contributionsnₑ μₑnₕ μₕσ = e(nₑμₑ + nₕμₕ)

13-17. Exam Practice Bank With Accordion Solutions

Click any question to open the answer and explanation.

19. Common Student Mistakes

20. Exam Strategy

CBSE

Focus on definitions, derivations, units, dimensions and direct formula application.

NEET

Memorise formula links: μ, vd, J, σ, ρ and temperature effects.

JEE Main

Practise numerical chains combining E = V/L, vd = μE and I = nAqvd.

JEE Advanced

Handle multi-carrier conduction, graphs, varying field and semiconductor traps.

Olympiad

Build microscopic intuition: scattering, relaxation time, effective mass and model assumptions.

AP Physics

Connect microscopic current with circuit quantities and proportional reasoning.

IB Physics

Emphasise explanation quality, units, graph interpretation and uncertainty in models.

A-Level Physics

Practise drift velocity derivations, charge carrier density and resistivity links.

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